A rectangular area is to be enclosed and divided into thirds. The family has \$700 to spend for the fencing material. The outside fence costs \$12 per running foot installed, and the dividers cost \$30 per running foot installed. What are the dimensions that will maximize the area enclosed?

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1. Draw a picture of the problem. You should get to the forumlae 700=24L+84W with basic math. Solve for L (or W). A=LxW. Maximum Area occurs when derivative = 0. Take derivative and solve for L (or W).

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posted by Doug

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