Grade 5 maths

Alan, Bill and Carl shared $372. After Alan spend 2/ 5 of his share, Bill spent 1 /2 of his share and Carl spent 1/3 of his share, the boys found they had the same amount of money left.

(a) What is the ratio of Alan's share to Bill's share to Carl's share?

(b) How much did they spend altogether?

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  3. 👁 104
asked by Bryan

  1. a + b + c = 372
    what is left to each = 1-fraction spent
    (3/5) a = (1/2)b = (2/3) c

    (a) common denominator is 30
    18a = 15 b = 20 c
    so a/b = 15/18 = 5/6
    a/c = 20/18 = 10/9
    b/c = 20/15 = 4/3

    (b)
    a = 10 c/9
    b = 4c/3

    a + b + c = 372
    10c/9 + 4c/3 + c = 372

    10 c/9 + 12 c/9 + 9 c/9 = 372
    31 c = 9*372
    c = 108

    You can take it from there I think

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    posted by Damon

  2. By the way - grade 5 ??

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    posted by Damon

  3. A, B, C are the initial amounts.

    then
    3/5 A= 1/2 B = 2/3 C then
    A=10/9 C
    B=4/3 C
    but A+B+C=372 so
    10/9 C+ 4/3 C+ C=372
    10C+12C+9C=9*372
    31C=9*372

    C= you do it. From this, figure A, and B.

    Then, ratios are A/B, A/C, and B/C

    how much did they spend? go back to the problem, and do that calculation.

    check my logic

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    posted by bobpursley

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