The dimensions of triangle B are three times the dimensions of triangle A. The area of triangle B is 72 cm2. What is the area of triangle A?

16 cm2
8 cm2
36 cm2
24 cm2
My answer 4th one?

No wait the 2nd

40.5

24

24

Yes, the correct answer is 24 cm2.

If the dimensions of triangle B are three times the dimensions of triangle A, then the ratio of their areas will be 1:9 (since area is proportional to the square of the dimensions).

So, if the area of triangle B is 72 cm2, then the area of triangle A would be 1/9 of that, which is:

72/9 = 8

Therefore, the area of triangle A is 8 cm2.

To find the area of triangle A, we can use the fact that the dimensions of triangle B are three times the dimensions of triangle A.

Let's assume the base of triangle A is x cm and the height of triangle A is y cm.

Therefore, the base of triangle B is 3x cm and the height of triangle B is 3y cm.

The area of a triangle can be calculated using the formula: Area = 1/2 * base * height.

Plugging in the values, the area of triangle A would be:

Area_A = 1/2 * x * y

And the area of triangle B would be:

Area_B = 1/2 * 3x * 3y = 9/2 * x * y

Given that the area of triangle B is 72 cm^2, we can set up the equation:

9/2 * x * y = 72

By dividing both sides of the equation by 9/2, we get:

x * y = 72 / (9/2)

Simplifying, we have:

x * y = 72 * 2/9

x * y = 16

Therefore, the area of triangle A is 16 cm^2.

So, the correct answer is the 1st option: 16 cm^2.