an aluminium of mass 2.1 kg rests on a steel platform. A horizontal force of 15N is applied to block(a) given the coefficient of limiting friction is 0.61 will the block move? (b)if it moves what will be its acceleration?
2.1 * 9.81 * .61 = 12.57 Newtons maximum friction force
so no
15 - 12.56 = 2.43 Newton net force
a = F/m = 2.43 / 2.1 = 1.16 m/s^2
I need the question please
Question
To determine whether the aluminum block will move on the steel platform, we need to compare the applied force (15N) to the maximum frictional force that can be exerted before the block starts moving. This maximum frictional force is equal to the product of the coefficient of friction (0.61) and the normal force.
First, let's calculate the normal force acting on the block. The normal force is the force exerted by the platform perpendicular to the block's surface and is equal to the weight of the block.
Weight (W) = mass (m) x gravitational acceleration (g)
Given that the mass of the aluminum block is 2.1 kg and the gravitational acceleration is approximately 9.8 m/s^2 (on Earth), we have:
Weight (W) = 2.1 kg x 9.8 m/s^2
Now, with the normal force (N) calculated, we can determine the maximum frictional force (F_friction_max) using the equation:
F_friction_max = coefficient of friction (μ) x normal force (N)
Given that the coefficient of friction is 0.61, we have:
F_friction_max = 0.61 x normal force (N)
To check if the block is in equilibrium (not moving), we compare the applied force to the maximum frictional force:
If applied force (15N) ≤ maximum frictional force (F_friction_max), the block will not move.
However, if the applied force is greater than the maximum frictional force (15N > F_friction_max), the block will start moving.
For part (a), compare the applied force (15N) to the maximum frictional force (F_friction_max) to determine if the block will move.
For part (b), assuming the block moves, we can calculate its acceleration (a) using Newton's second law:
Force (F) = mass (m) x acceleration (a)
Since the applied force (15N) exceeds the maximum frictional force, the block will experience a net force, causing it to accelerate. Plug the given mass of the block (2.1 kg) and the applied force (15N) into the equation above to solve for acceleration (a).