# Chemistry Help Please!

An industrial chemist puts 1.00 mol each of H2(g) and CO2(g) in a 1.00-L container at 800oC. When equilibrium is established, 0.49 mol of CO(g) is in the container. Find Kc at 800 C for the following reaction:
H2(g) + CO2(g) ⇌ H2O(g) + CO(g).

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asked by Josh
1. H2 + CO2 <> H2O + C0 all gases.

K= [H2O][CO]/[H2}{CO2]

K= (.49)^2 /(1-.49)(1-.49)=(.49/.51)^2

check my work

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2. 👎 0

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