# physics

A body of mass 10kg in air and 4kg in water calculate the volume and its density

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1. Vw=(10kg-4kg) * 1m^3/1000kg = 0.006 m^3
= Vol. of water displaced = Vol. of the
object submerged.

Do = 6kg/0.006m^3 = 1000kg/m^3 = Density
of the object. = Density of water(Dw).

Do/Dw * Vo = 0.006 m^3
(1000/1000) * Vo = 0.006m^3
Vo = 0.006 m^3 = Vol. of the object.

So the object is 100% submerged.

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posted by Henry

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