How do I set up my equation for 18 wheeler with 71 fridges and 118 TVs and 51 fridges and 176 TVs with my graph showing (0,330) and (110,0)? Page 539 problem 68 Thanks!

To set up an equation for the given problem, we need to consider the number of fridges and TVs in each scenario and the cost associated with them. Since the question provided a graph with two points, we can use those points to form linear equations and solve for the unknown variables.

Let's assume the cost of each fridge is 'f' and the cost of each TV is 't'.

In the first scenario, we are given that there are 71 fridges and 118 TVs. Therefore, the total cost can be calculated as:

Cost_1 = 71f + 118t

In the second scenario, there are 51 fridges and 176 TVs. Thus, the total cost can be expressed as:

Cost_2 = 51f + 176t

Now we can set up a system of equations using the two given scenarios:

71f + 118t = 330 (Equation 1)
51f + 176t = 0 (Equation 2)

To solve this system of equations, we can use various methods, such as substitution or elimination. Here, we will use the elimination method.

First, multiply Equation 2 by 118 to make the coefficients of 't' equal:

5796f + 20768t = 0 (Equation 3)

Next, subtract Equation 3 from Equation 1:

(71f + 118t) - (5796f + 20768t) = 330 - 0

Which simplifies to:

-5725f - 20650t = 330

Now, we have a new equation:

5725f + 20650t = -330 (Equation 4)

By solving Equations 3 and 4 simultaneously, we can find the values of 'f' and 't,' which represent the cost of each fridge and TV, respectively.

Now, you can solve this system of equations using a calculator, online solver, or by hand to find the values of 'f' and 't'.