Algebra

Gustavs father is seven times as olda s he is.a. Year ago,he was nine timesa s olda s gustav. Find gustavs present age

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  1. g = Gustavs age

    f = Fathers age


    Gustavs father is 7 times as olda s he is.

    f = 7 g


    Year ago,he was nine timesa s olda s gustav

    ( f - 1 ) / ( g - 1 ) = 9


    ( 7 g - 1 ) / ( g - 1 ) = 9 Multiply both sides by ( g - 1 )

    7 g - 1 = 9 ( g - 1 )

    7 g - 1 = 9 g - 9 Subtract 7 g to both sides

    7 g - 1 - 7 g = 9 g - 9 - 7 g

    - 1 = 2 g - 9 Add 9 to both sides

    - 1 + 9 = 2 g - 9 + 9

    8 = 2 g Divide both sides by 2

    4 = g

    g = 4

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  2. f = father
    g = Gustav

    Write two equations.

    f = 7g
    f - 1 = 9(g - 1)

    Substitute first equation into second.

    7g - 1 = 9g - 9
    7g - 9g -1 + 1 = 9g - 9g - 9 + 1
    -2g = -8
    -2g/-2 = -8/-2
    g = 4

    Substitute g value in either equation.

    f = 7(4)
    f = 28

    Check:

    One year ago.....
    f is 27 and 9 times older than g
    g is 3

    27 = 3 * 9

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    posted by Chelle
  3. Gustav -- x
    his father -- 7x

    One year ago:
    Gustav -- x-1
    his father -- 7x-1

    7x-1 = 9(x-1)
    7x-1 = 9x - 9
    -2x = -8
    x = 4

    Gustav is now 4 years old

    check:
    his father is now 28
    one year ago, Gustav was 3 and his father would have been 27, which is 9 time Gustav's age

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    posted by Reiny
  4. If 22.5 L of nitrogen at 748 mm Hg are composed of 725 mm Hg at constant. What is yhe new volume?

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