physics

An electron passes location
h0.02m, 0.04m,−0.06mi, and 4 μs later is de-
tected at location h0.02 m, 1.84 m,−0.86 mi.
Find the average velocity of the elecron:
¯v = <vx, vy, vz>

If the electron continues to travel at this av-
erage velocity, find where it will be in another
9 μs :
~d = <dx, dy, dz>

Answer in units of m

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asked by NADIA

  1. dx=(xf-xi)

    vx=dx/dt=dx/4E-6

    similarlly, vy, vz.

    then for the second part, knowing the velocities

    xf=xi+vx*dt

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    posted by bobpursley

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