Moffett’s Candy Factory makes candy in the shape of cylinders. The net of a cylindrical piece of candy is shown below.
two circle with diameter of 4cm each and a rectangle with a lenght of 1.5 cm
wha is the total surface area of this piece of candy?
To find the total surface area of the cylindrical candy, we need to calculate the areas of each face and add them up.
First, we need to find the area of the two circular faces. The formula to find the area of a circle is A = πr², where A represents the area and r represents the radius. In this case, the diameter is given as 4 cm, so the radius is half of the diameter, which is 2 cm.
Thus, the area of one circular face is A1 = π(2 cm)² = 4π cm².
Since there are two circular faces, the total area of the two circular faces is:
A2 = 2 × A1 = 2 × 4π cm² = 8π cm².
Next, we need to find the area of the rectangle, which will be the curved surface area of the cylinder. The formula for the curved surface area of a cylinder is A = 2πrh, where r is the radius and h is the height or length of the rectangle.
In this case, the height of the rectangle is given as 1.5 cm, and we already know the radius is 2 cm.
Thus, the curved surface area of the cylinder is A3 = 2π(2 cm)(1.5 cm) = 6π cm².
Finally, to find the total surface area, we add up the areas of all the faces:
Total Surface Area = A2 + A3 = 8π cm² + 6π cm² = 14π cm².
So, the total surface area of this piece of candy is 14π square centimeters, or approximately 43.98 square centimeters.
that would be 2πr(r+c) = 2π(2)(2+1.5) = 14π
before being licked...
That's on odd shape for a piece of candy - like a hockey puck.