# math

Rewrite by completing the square.
2x^2 - 12x + 11

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asked by Cassy
1. 2x^2 - 12x + 11
2(x^2 - 6x) + 11
2(x^2 - 6x + 9) + 11 - 2*9
2(x-3)^2 - 7

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2. 2 x ^ 2 - 12 x + 11 =

2 ( x ^ 2 - 6 x ) + 11 =

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Take one half of the coefficient of x and square it.

In this case : [ ( 1 / 2 ) * 6 ] ^ 2 = 3 ^ 2 = 9

Multiply by 2

2 * 9 = 18
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2 ( x ^ 2 - 6 x + 9 ) + 11 - 18 =

2 ( x ^ 2 - 6 x + 9 ) - 7 =

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Exspress x ^ 2 - 6 x + 9 as a square:

x ^ 2 - 6 x + 9 = ( x - 3 ) ^ 2
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2 ( x - 3 ) ^ 2 - 7

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posted by Bosnian

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