# Calculus

What is the domain of f(x)= (x-3)/(x^2-9)?

lim f(x)
x->3

1. domain of f(x) :
any real number, x ≠ 3

lim (x-3)/(x^2 - 9) , x --->3
= lim (x-3)((x-3)(x+3))
= lim 1/(x+3) , as x -->3
= 1/6

posted by Reiny
2. x = -3 is also excluded from the domain, eh? since x^2-9 = 0

posted by Steve@Math

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