A die is tossed twice. What is the probability of obtaining 6 dots both times?
1/6 * 1/6 = 1/36
1/6*1/6=1/36
To find the probability of obtaining 6 dots both times when a die is tossed twice, we need to determine the total number of possible outcomes and the number of favorable outcomes.
1. Total number of possible outcomes: When a die is tossed twice, each toss has 6 possible outcomes (numbers 1 to 6). So, the total number of possible outcomes for two tosses is 6 * 6 = 36.
2. Number of favorable outcomes: We are looking for the outcome of getting 6 dots on both tosses. Since there is only one side with 6 dots on a die, the probability of rolling a 6 on each toss is 1/6. Therefore, the number of favorable outcomes is 1 * 1 = 1.
Now we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
= 1 / 36
Therefore, the probability of obtaining 6 dots both times when a die is tossed twice is 1/36.