If you add 4.6 g of sodium to water, how many molecules of H2 will be formed? (4points)
2Na(s)+2H2O(l)-->2NaOH(aq)+H2(g)
mols Na = grams/atomic mass.
Uing the coefficients in the balanced equation, convert mols Na to mols H2.
Convert mols H2 to molecules. 1 mol contains 6.02E23 molecules.
thanks
To determine the number of molecules of H2 formed when adding 4.6 g of sodium to water, we need to go through a series of steps:
Step 1: Calculate the number of moles of sodium (Na)
We can use the molar mass of sodium (22.99 g/mol) to calculate the number of moles present in 4.6 grams of sodium.
Number of moles = mass / molar mass
Number of moles of Na = 4.6 g / 22.99 g/mol
Step 2: Calculate the stoichiometry ratio between sodium (Na) and hydrogen gas (H2)
From the balanced chemical equation, 2 moles of sodium (Na) react to produce 1 mole of hydrogen gas (H2).
Step 3: Calculate the number of moles of hydrogen gas (H2)
To find the number of moles of hydrogen gas formed, we need to multiply the number of moles of sodium by the stoichiometry ratio.
Number of moles of H2 = Number of moles of Na * Stoichiometry ratio
Number of moles of H2 = (4.6 g / 22.99 g/mol) * (1 mol H2 / 2 mol Na)
Step 4: Convert the number of moles of hydrogen gas to molecules
To convert from moles to molecules, we can use Avogadro's number (6.022 x 10^23 molecules/mol).
Number of molecules of H2 = Number of moles of H2 * Avogadro's number
Number of molecules of H2 = (4.6 g / 22.99 g/mol) * (1 mol H2 / 2 mol Na) * (6.022 x 10^23 molecules/mol)
Now, you can follow these steps and perform the calculations to find the final answer.