in a class there are 35 students.25 of the students can play basketball ,and 15 of the students can play football .5 of the students cannot play either of these.how many students can play both?
25+15-x = 35-5
x = 10
a is a digit of four digit number 634a if 634a is divisible 15 find a
To find out how many students can play both basketball and football, we need to determine the number of students who can play basketball only, the number of students who can play football only, and the number of students who cannot play either.
Given:
- Number of students in the class: 35
- Number of students who can play basketball: 25
- Number of students who can play football: 15
- Number of students who cannot play either: 5
Step 1: Determine the number of students who can play basketball only.
To calculate this, we take the total number of students who can play basketball (25) and subtract the number of students who can play both basketball and football (unknown) and the number of students who can play football only (unknown).
25 - (unknown) - (unknown) = (unknown)
Step 2: Determine the number of students who can play football only.
To calculate this, we take the total number of students who can play football (15) and subtract the number of students who can play both basketball and football (unknown) and the number of students who can play basketball only (unknown).
15 - (unknown) - (unknown) = (unknown)
Step 3: Determine the number of students who cannot play either.
Given that there are 5 students who cannot play either basketball or football.
Step 4: Calculate the number of students who can play both basketball and football.
To find this, we subtract the sum of the number of students who can play basketball only and the number of students who can play football only from the total number of students in the class.
35 - (number of students who can play basketball only) - (number of students who can play football only) = (number of students who can play both basketball and football)
Following these steps, we can find the answer by solving the equations.
To find out how many students can play both basketball and football, we need to use the concept of set intersection. We know that there are 35 students in total, 25 of whom can play basketball, and 15 of whom can play football. Remember that set intersection refers to the elements that are common in two sets.
To solve this problem, we need to subtract the number of students who cannot play any of the sports from the total number of students. Therefore, we subtract 5 (the number of students who cannot play either sport) from 35 (the total number of students):
35 - 5 = 30.
Now, we know that 30 students can play at least one of the sports. However, we still need to find the number of students who can play both. To do that, we add the number of students who can play basketball and the number of students who can play football:
25 + 15 = 40.
Here we encounter a problem: the total count of students who can play basketball or football is greater than the total number of students in the class (35). This suggests that there may have been some students who can play both sports. However, it is not possible to determine the exact number of students who can play both based on the information provided.