(100, 18,000)
(200, 37,000)
(300, 48,000)
(400, 66,000)
Write an equation for the line that models the data.
maybe it'd be easier without all the zeros:
1 18
2 37
3 48
4 66
y=17x comes close. The errors are
1 +1
2 +3
3 +1
4 -2
Use your favorite regression tool for a more exact line. The best-fit line is
y = 15.5x + 3.5
a good calculator and grapher is at
http://www.alcula.com/calculators/statistics/linear-regression/
It requires at least 5 data points, though so enter 5,81 as a 5th point, since it is exactly on the line of best fit.
To write an equation for the line that models the given data, we can use the slope-intercept form of a linear equation: y = mx + b, where m is the slope and b is the y-intercept.
First, let's calculate the slope (m):
We can calculate the slope (m) using the formula:
m = (change in y) / (change in x)
m = (48,000 - 18,000) / (300 - 100)
m = 30,000 / 200
m = 150
Next, we need to find the y-intercept (b).
We can substitute any of the given points into the equation and solve for b.
Let's use the point (100, 18,000):
18,000 = 150 * 100 + b
18,000 = 15,000 + b
b = 18,000 - 15,000
b = 3,000
Now we have the slope (m = 150) and the y-intercept (b = 3,000), so we can write the equation:
y = 150x + 3,000
Therefore, the equation for the line that models the given data is y = 150x + 3,000.