MS. SUE - MATH HELP PLEASE

The sum of five times a number and twice a second number is 18, but the difference of three times the first number and seven times the second number is -22. Find the two numbers using the elimination method.

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  1. 5n+2m=18
    3n-7m=-22

    can you solve this?

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  2. translate the English into Math
    "The sum of five times a number and twice a second number is 18" ---->5x + 2y = 18
    "the difference of three times the first number and seven times the second number is -22" ---> 3x - 7y = -22

    1st times 7 -- 35x + 14y = 126
    2nd times 2 -- 6x - 14y = -44
    add them
    41x = 82
    x = 82/41= 2

    into the 1st

    5(2) + 2y = 18
    10 + 2y = 18
    2y = 8
    y = 4

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    posted by Reiny

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