A ball pit contains 10 yellow balls and 14 green balls. What is the probability of randomly picking 3 green balls (replacing them), from the pit?
3/24
chance of one green ball: 14/24 = 7/12
chance of 3 green balls in a row: (7/12)^3 = 0.198
To calculate the probability of randomly picking 3 green balls from the ball pit, we need to know the total number of balls in the pit. You mentioned that the pit contains 10 yellow balls and 14 green balls, so the total number of balls is 10 + 14 = 24.
When we pick the first green ball, there are 14 green balls out of 24 total balls. After replacing it back into the pit, the probability of picking a green ball again remains the same for each subsequent pick. Therefore, the probability of picking a green ball for each pick is 14/24.
Since we are picking 3 green balls, and the probability of picking a green ball remains the same for each pick, we can simply multiply the individual probabilities together. Thus, the probability of picking 3 green balls would be (14/24) * (14/24) * (14/24).
Simplifying this calculation, we get 196/13824, which can be further reduced to 1/72.
Therefore, the probability of randomly picking 3 green balls from the ball pit is 1/72.