# Trig

Solve triangle ABC given the following conditions:
1. C = 135.77 deg, b = 10cm, a = 12cm
2. a = 11.5m, b = 10m, c = 16.94m

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1. in each case, use law of cosines to get c or C:

c^2 = a^2+b^2-2ab cosC

Now, having all 3 sides, and angle C, use law of sines to get A and B:

sinA/a = sinB/b = sinC/c

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posted by Steve

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