Magnetic force between two poles is 80 unit. Separation between poles is doubled. What is force between them?
it follows an inverse law...
what is 30/4 ?
30/4 = 7.5
To find the force between two magnetic poles when the separation is doubled, we need to understand the relationship between the magnetic force and the separation.
The magnetic force between two magnetic poles (F) is given by the formula:
F = (μ0 * m1 * m2) / (4π * r^2)
Where:
- F is the magnetic force between the poles,
- μ0 is the permeability of free space (constant value),
- m1 and m2 are the magnitudes of the magnetic poles, and
- r is the separation distance between the poles.
We are given that the initial force between the poles is 80 units. Let's call this initial separation distance r1. We are asked to find the new force between the poles when the separation distance is doubled. Let's call this new separation distance r2.
We can set up a ratio using the formula to find the new force:
F1 / F2 = (r1^2)/(r2^2)
Since the separation distance is doubled, r2 = 2 * r1.
Substituting the given values into the equation, we have:
80 / F2 = (r1^2) / ((2 * r1)^2)
80 / F2 = (r1^2) / (4 * r1^2)
We can simplify the equation by canceling the common term "r1^2":
80 / F2 = 1 / 4
Now we can solve for F2, the new force between the poles:
F2 = 80 / (1/4)
F2 = 80 * (4/1)
F2 = 320 units
Therefore, the force between the poles when the separation is doubled is 320 units.