If you stood atop a ladder that was so tall that you were twice as far from Earth's center, how would your weight compare with its present value?

since F ∝ 1/r^2, 1/(2r)^2 = 1/4 * 1/r^2, so the pull would be 1/4 as much.

Of course, that ignores the tremendous torque on the ladder caused by the earth's spin! :-)

If you stood atop a ladder that was so tall that you were twice as far from Earth's center, your weight would be reduced to one-fourth (1/4) of its present value. This is because weight is directly proportional to the distance from the center of the Earth.

According to Newton's law of universal gravitation, the force of gravity acting on an object is inversely proportional to the square of the distance between the centers of the two objects. Mathematically, this can be represented as:

F = G * (m1 * m2) / r^2

Where:
F is the force of gravity,
G is the gravitational constant,
m1 and m2 are the masses of the two objects, and
r is the distance between the centers of the two objects.

In this case, the mass of the Earth (m1) remains constant, so the force of gravity acting on you (F) is directly proportional to the distance squared (r^2).

If you are twice as far from the center of the Earth, the distance between you and the Earth's center (r) will be doubled. Thus, the force of gravity acting on you will become one-fourth (1/2^2) of its present value. Since weight is the measure of the force of gravity acting on an object, your weight would also be reduced to one-fourth (1/4) of its present value.

To understand how your weight would compare if you were standing atop a ladder that is twice as tall as your current distance from Earth's center, we need to consider the concept of gravitational force.

The weight of an object on Earth is a result of the force of gravity pulling it towards the center of the planet. This force depends on the mass of the object and the distance between the object's center of mass and the center of the Earth.

Assuming that your mass remains constant, if you stand on a ladder that is twice as tall as your current distance from the Earth's center, the distance between your center of mass and the Earth's center would also double.

The gravitational force between two objects is inversely proportional to the square of the distance separating them. In this case, when the distance doubles, the gravitational force decreases to one-fourth of its original value (2 x 2 = 4).

Therefore, if you stood on a ladder that is twice as tall, your weight would be one-fourth of its present value. This means you would weigh significantly less compared to your current weight.

It is important to note that this explanation assumes a simplified scenario, disregarding other factors such as the Earth's rotation and any potential changes in your own body composition due to standing on the ladder. Additionally, in reality, ladders cannot be built to such extreme heights without significant structural and logistical challenges.