# Need help also with this chem ?

I also thought this question on combining gas laws P1V1/T1=P2V2/T2 was also a bit tricky for me.

P1V1/T1=P2V2/T2

P1 is 760 torr with a blank box underneath it.

V1 is 2.4 L.

T1 is 37 °C with a blank box underneath it.

P2 is a ?.

V2 is 4.8 L.

T2 is 300 K.

How do I combine these gas laws.

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1. This is the same kind of problem that I helped you with. Now that you see how to do that, try this one on your own. If you still have trouble. repost and explain what you don't understand.

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2. I don't understand what goes inside the blank box of P2 and the blank box of P1.

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3. I also thought this question on combining gas laws P1V1/T1=P2V2/T2 was also a bit tricky for me.

P1V1/T1=P2V2/T2

P1 is 760 torr with a blank box underneath it.

V1 is 2.4 L.

T1 is 37 °C with a blank box underneath it.

P2 is a ?.

V2 is 4.8 L.

T2 is 300 K.

How do I combine these gas laws.

I just don't no what to provided for P1 and P2 if they're both are a ? that needs an answer to it.

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2. 👎 0
4. I also thought this question on combining gas laws P1V1/T1=P2V2/T2 was also a bit tricky for me.

P1V1/T1=P2V2/T2

P1 is 760 torr with a blank box underneath it.

V1 is 2.4 L.

T1 is 37 °C with a blank box underneath it.

P2 is a ?.

V2 is 4.8 L.

T2 is 300 K.

How do I combine these gas laws.

1. 👍 0
2. 👎 0
5. P1V1/T1=P2V2/T2

P1 is 760 torr with a blank box underneath it.
You don't say what units go with the blank box. I suspect it is atmospheres. If so, there are 760 torr in 1 atm so 760/760 = 1 atm.

V1 is 2.4 L.

T1 is 37 °C with a blank box underneath it.
Again, what units? Probably Kelvin. Convert C to Kelvin by Kelvin = 273 + C.<b/>

P2 is a ?.
I assume this is the unknown for which you are to solve.

V2 is 4.8 L.

T2 is 300 K.
This is already in Kelvin and need not be changed.

How do I combine these gas laws.
You don't. The name of P1V1/T1 = P2V2/T2 is "the combined gas law."

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