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I need help for this question in combining gas law P1V1/T1=P2V2/T2.

P1V1/T1=P2V2/T2


P1 is 1.5 atm

V1 is a question mark.

T1 is -20 °C K

P2 is 2.6 atm

V2 is 750 mL with a blank box underneath it.

T2 is -5 °C K.

How can I combine this question?

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  1. P1V1/T1=P2V2/T2

    I'm not sure you copied all of the problem. I don't know what you're combining. You are making some conversions and some substitutions. Here is some help on what I can determine from your numbers.

    P1 is 1.5 atm

    V1 is a question mark.
    I suppose the question mark means that you are solving for V1 and I assume it is to be determined in liters.

    T1 is -20 °C K
    What you have written doesn't make sense to me. I assume T1 is -20 C and you want to convert that to Kelvin. To convert to Kelvin, remember Kelvin = 273 + C.

    P2 is 2.6 atm
    Nothing needs to be done to this since P1 is in atm, also.

    V2 is 750 mL with a blank box underneath it.
    My best guess is that 750 mL is to be converted to liters. That is done by using the conversion factor of 1 L = 1000 mL.
    750 mL x (1 L/1000 mL) = ?? Liters.


    T2 is -5 °C K.
    Again, I must assume T2 is -5 C and you want to convert to Kelvin. See above conversion for T1.

    Plug all those numbers into the formula and solve for V1. The answer will be in liters.

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