need help don't undertsand the problem i tried the point slope formula but wasn't working out
Find the x and y intercept of the line that passes thorugh the given points. (-6,2) and (-3,4)
To find the x and y intercepts of a line that passes through two given points, you can follow these steps:
Step 1: Calculate the slope of the line using the formula:
slope = (change in y) / (change in x)
slope = (y2 - y1) / (x2 - x1)
Using the given points (-6,2) and (-3,4), the slope can be calculated as follows:
slope = (4 - 2) / (-3 - (-6))
slope = 2 / 3
Step 2: Write the equation of the line using the point-slope form:
y - y1 = m(x - x1)
Using point (-3,4) and the slope of 2/3, the equation can be written as:
y - 4 = (2/3)(x - (-3))
Step 3: Simplify the equation:
y - 4 = (2/3)(x + 3)
y - 4 = (2/3)x + 2
Step 4: Solve for y-intercept:
Set x = 0 in the equation and solve for y:
y - 4 = (2/3)(0 + 3)
y - 4 = (2/3)(3)
y - 4 = 2
y = 6
Therefore, the y-intercept is 6.
Step 5: Solve for x-intercept:
Set y = 0 in the equation and solve for x:
0 - 4 = (2/3)x + 2
-4 - 2 = (2/3)x
-6 = (2/3)x
-6 * 3 = 2x
-18 = 2x
x = -9
Therefore, the x-intercept is -9.
Hence, the x-intercept is -9 and the y-intercept is 6 for the line that passes through the given points (-6,2) and (-3,4).