# math 7

Nila is now x years old. Three yrs ago, her brother ricky was twice as old as she, write rickys age ten yrs frm now in terms of x.

(With solution pls) tnx...

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1. Nila's age = X yrs old, now.
Nila's age = (X-3) yrs old, 3 yrs ago.

Ricky's age = 2(X-3) yrs old, 3 yrs ago.
Ricky-Nila = 2(X-3)-(X-3) = (X-3) yrs
older than Nila.

Ricky's age, now = X + (X-3) = (2x-3)
yrs old.

Ricky's age 10 yrs from now = 10(2x-3) =
(20x-30) yrs old.

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posted by Henry
2. Correction:
Ricky's age 10 yrs from now =(2x-3)+10 =
2x+7.

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posted by Henry
3. 2x+7

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