# Physics

A car traveling with an initial velocity of 68 km/h accelerates uniformly at a rate of 1.35 m/s^2 for 4.7s. Find the final speed and displacement of the car during the specified time interval.

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1. Vo = 68km/h = 68,000m/3600s = 18.89 m/s.

V=Vo + a*t = 18.89 + 1.35*4.7 = 25.2m/s
= Final velocity.

D = Vo*t + 0.5*a*t^2
D = 18.89*4.7 + 0.5*1.35*4.7^2=103.7 m.

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posted by Henry

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