A small ball rolls horizontally off the edge of a table that is 1.20 m high. It strikes the floor at a point 1.52 m horizontally from the table edge. How long is the ball in the air? What is the velocity of the ball when it hits the floor?
It fell 1.20m.
1.20= 1/2 g time^2 solve for time in air.
Velocity? Its intial horizontal veloicty must have been 1.52/timeinair.
So, take the falling final velocity (v= g t), add it to the horizontal velocity as a vector at 90 degrees, and you have the velocity at the floor.
What is g? The acceleration in m/s^2?
g= 9.8m/s^2
How do you get rid of t^2
Square root.
a ball rolls off an 80cm high table & lands 1.2m a long the floor (g=10m/s.s) find total time?
To find the time the ball is in the air, we can use the kinematic equation that relates the height, time, and acceleration due to gravity. The equation is:
h = (1/2) * g * t^2
Where:
h is the height (in this case, the vertical distance the ball falls)
g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
t is the time the ball is in the air.
In this case, the initial height of the ball is 1.20 m. The ball falls to the ground, so the final height is 0 m. We can plug these values into the equation to solve for t:
0 = (1/2) * 9.8 * t^2
Simplifying the equation, we get:
0 = 4.9 * t^2
Solving for t, we find t = 0. Hence, the ball is in the air for 0 seconds.
Now, to find the horizontal velocity of the ball when it hits the floor, we can use the kinematic equation that relates horizontal distance, time, and horizontal velocity. The equation is:
d = v * t
Where:
d is the horizontal distance the ball travels (1.52 m in this case)
v is the horizontal velocity of the ball.
t is the time the ball is in the air.
We can plug in the values we know and solve for v:
1.52 = v * 0
Since the ball is in the air for 0 seconds, the value of v does not matter, as the ball has not moved horizontally. Therefore, we cannot determine the horizontal velocity of the ball when it hits the floor.