Physics

Problem 1- A 0.5 kg ball is moving to the right at 5 m/s when it is suddenly collide by a wall that exerts on it a horizontal force of 2.5 N for a period of 0.8 s.
a) What is the impulse does the force of the wall exert on the ball?
b) What is the velocity of the ball after the collision?

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asked by Mariam
  1. impulse = change of momentum
    = average force * time
    = -2.5*.8 = -2 N s = - 2 kg m/s

    original momentum = .5*5 = 2.5 kg m/s

    final momentum = original momentum + impulse
    = 2.5 - 2 = .5
    It broke through the wall and is still going right
    m v = .5
    .5 v = .5
    v = 1 m/s

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    posted by Damon

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