From a survey of 100 college students, a marketing research company found that 35 students owned iPods, 25 owned cars, and 5 owned both cars and iPods

How many students owned either a car or an iPod (but not both)?

How many students do not own either a car or an iPod?
236 Incorrect: Your answer is incorrect. .

Ah, looks like we have a Venn diagram situation here! Let me do some clown calculations for you.

So we start with the total number of students, which is 100.
Now, 35 students own iPods, and 25 students own cars. But wait, 5 students own both, so we need to subtract those from each group, otherwise, we'll be counting them twice.

If we subtract the overlapping group from the iPod owners, we have 35 - 5 = 30 students.
Similarly, if we subtract the overlapping group from the car owners, we have 25 - 5 = 20 students.

Now, to find the total number of students who own either a car or an iPod (but not both), we add those two numbers together: 30 + 20 = 50 students.

So, 50 college students own either a car or an iPod (but not both).

Now, let's tackle the second part of the question - how many students do not own either a car or an iPod?

To find this, we need to subtract the total number of students who own either a car or an iPod from the total number of students (100). So, 100 - 50 = 50 students.

Therefore, 50 college students do not own either a car or an iPod.

Hope that clears things up with a touch of clown logic!

To find the number of students who owned either a car or an iPod (but not both), we need to subtract the number of students who owned both from the total number of students who owned either a car or an iPod.

Given that 35 students owned iPods, 25 owned cars, and 5 owned both, we can calculate the number of students who owned either a car or an iPod (but not both) as follows:

Number of students who owned either a car or an iPod (but not both) = (Number of students who owned iPods) + (Number of students who owned cars) - (Number of students who owned both)
= 35 + 25 - 5
= 55

Therefore, 55 students owned either a car or an iPod (but not both).

To find the number of students who do not own either a car or an iPod, we subtract the number of students who owned either a car or an iPod from the total number of students.

Total number of students = 100

Number of students who owned either a car or an iPod = 55 (which we calculated above)

Number of students who do not own either a car or an iPod = Total number of students - Number of students who owned either a car or an iPod
= 100 - 55
= 45

Therefore, 45 students do not own either a car or an iPod.

To find the number of students who owned either a car or an iPod (but not both), we need to subtract the number of students who owned both from the total number of students who owned either a car or an iPod.

We know that 35 students owned iPods, 25 owned cars, and 5 owned both cars and iPods.

To find the number of students who owned either a car or an iPod, we add the number of students who owned iPods and the number of students who owned cars: 35 + 25 = 60.

Then, we subtract the number of students who owned both cars and iPods from the total: 60 - 5 = 55.

Therefore, 55 students owned either a car or an iPod (but not both).

To find the number of students who do not own either a car or an iPod, we need to subtract the number of students who own either a car or an iPod from the total number of students.

We know that the survey was conducted on 100 college students.

To find the number of students who do not own either a car or an iPod, subtract the number of students who own either a car or an iPod from the total number of students: 100 - 60 = 40.

Therefore, 40 students do not own either a car or an iPod.

Draw a Venn diagram

overlap between cars and Ipods is 5
so Ipod alone = 35-5 = 30
and car alone = 25-5 = 20
so Ipod or car but not both = 30+20 = 50

Ipod and car = 35
car alone = 20
sum = 55
100 - 55 = 45 own nothing