Okay, so I've figured this much out on my own, I just need help with the next part.
It's a two block system with a friction of .20 a hanging mass of 7.5 kg and mass on the table at 10 kg. I got 3.08 m/s^2 for the acceleration and I got 22.8 N for the tension in the rope.
This part has me stuck:Suppose the hanging mass is replaced by a downward force of 75 N. What will be the resulting acceleration of the system?
ok, what has the hanging mass have to do with a table?
Well it's a two part system, so the mass is a force that the other mass has to overcome in order to move
To find the resulting acceleration of the system when the hanging mass is replaced by a downward force of 75 N, we can use Newton's second law of motion which states that the net force acting on an object is equal to the product of its mass and acceleration.
In this case, the net force is the tension in the rope since there is no friction acting horizontally. So, we can find the new net force by subtracting the force applied by the hanging mass from the downward force applied:
Net force = Force applied - Force by hanging mass
Net force = 75 N - 22.8 N
Net force = 52.2 N
Next, we need to calculate the new acceleration of the system. The total mass of the system consists of the mass on the table and the hanging mass that has been replaced:
Total mass = mass on the table + mass of hanging mass
Total mass = 10 kg + 7.5 kg
Total mass = 17.5 kg
Now we can use Newton's second law to find the acceleration:
Net force = Total mass × Acceleration
Substituting the known values, we have:
52.2 N = 17.5 kg × Acceleration
Solving for acceleration:
Acceleration = 52.2 N / 17.5 kg
Acceleration ≈ 2.98 m/s^2
Therefore, the resulting acceleration of the system when the hanging mass is replaced by a downward force of 75 N is approximately 2.98 m/s^2.