What would be the temperature change if 3.0g of water absorbed 15J of heat?
To calculate the temperature change, we can use the equation:
q = mcΔT
Where:
q is the heat absorbed or released
m is the mass of the substance (in this case, water)
c is the specific heat capacity of the substance
ΔT is the change in temperature
First, we need to determine the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.
Next, we can insert the given values into the equation:
15 J = (3.0 g) * (4.18 J/g°C) * ΔT
Now, we can solve for ΔT:
ΔT = 15 J / [(3.0 g) * (4.18 J/g°C)]
Calculating this, we find:
ΔT ≈ 1.13°C
Therefore, the temperature change would be approximately 1.13°C (or 1.13 degrees Celsius).