physics

A small cube of mass m1= 1.0 kg slides down a circular and frictionless track of radius R= 0.4 m cut into a large block of mass m2= 4.0 kg as shown in the figure below. The large block rests on a horizontal and frictionless table. The cube and the block are initially at rest, and the cube m1 starts from the top of the path. Find the speed of the cube v1 as it leaves the block. Take g= 10.0 m/s2. Enter your answer in m/s.

v1=

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asked by Garry
  1. Looks like 8:01 to me.

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    posted by Damon
  2. so

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  3. Well remember the work energy theorem
    First m1 has potencial energy mgR then it starts moving such as the block
    m1gR=1/2m1v(square2) + 1/2m2v(square2)

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    posted by Daoine
  4. Remember conservation of momentum. If the cube moves one way, the large block moves the other way. There is no friction.

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    posted by Damon
  5. I was trying in this way - one equation is conservation of momentum, m2*v2 - m1*v1, and second conservation of energy, which is writen by Daoine. Two equations with two unknowns, but it gave me wrong answer

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  6. m2*v2 - m1*v1 = 0 , correction

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  7. Got it, I have been messed up with indexes

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  8. anonymous please elaborate how did u do it

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    posted by fighter
  9. you need to use conservation of momentum and conservation of energy.....
    v = 2,......

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    posted by Hawk
  10. i got the green tick so here is the solution

    equation (1)
    m1gR=0,5m1v1^2+0,5m2v2^2

    m2v2-m1v1=0 so

    equation (2)
    v2=m1v1/m2

    we substitute to equation (1)

    m1gR=0,5m1v1^2+0,5m2(m1v1/m2)^2

    and we solve for v1

    Ps i expect a thanks ( xaxaxaxx)

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    posted by Greco
  11. Thank you so much Greco, I found a lot of help from you during this course.

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    posted by koala
  12. Thanks Greco.. Just replace the ',' with '.'

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