The specific heat of gold is 0.031 calories/gram°C. If 10.0 grams of gold were heated and the temperature of the sample changed by 20.0°C, how many calories of heat energy were absorbed by the sample?
6.2 calories
0.016 calories
6,451 calories
0.062 calories
.031*10*20 = 6.2
so whats the answer ?
6,451 calories
0.062
To calculate the amount of heat energy absorbed by the sample, we can use the formula:
Q = mcΔT
Where:
Q = heat energy
m = mass of the sample
c = specific heat capacity of the substance
ΔT = change in temperature
In this case, we have:
m = 10.0 grams
c = 0.031 calories/gram°C
ΔT = 20.0°C
Substituting these values into the formula, we get:
Q = (10.0 grams) x (0.031 calories/gram°C) x (20.0°C)
Q = 6.2 calories
Therefore, the amount of heat energy absorbed by the sample is 6.2 calories. So the correct answer is "6.2 calories".