Math

The cable supporting a ski lift rises 2 feet for each 5 feet of horizontal length. The top of the cable is fastened 1320 feet above the cable’s lowest point. Find the lengths b and c, and find the measure of the angle theta.

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  1. let the rise be 2x , and the run be 5x, then the hypotenuse is 1320
    (2x)^2 + (5x)^2 = 1320
    29x^2 = 1320
    x^2 = 1320/29
    x = √(1320./29) = appr 6.74665

    rise = 2x = appr 13.5 ft
    run = 5x = appr 33.7 ft

    don't know what your b and c refers to , but I am sure you can match them up with the answers given.
    I will assume base angle is Ø

    tan Ø = rise/run = 2/5
    Ø = appr 21.8°

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    posted by Reiny

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