# Posts by salah

Total # Posts: 14

Physics
A particle of charge +18.5C and mass 4.84 × 10-5 kg is released from rest in a region where there is a constant electric field of +578 N/C. What is the displacement of the particle after a time of 1.89 × 10-2 s? 1) F=Eq 2) a=F/m 3) d=vt+1/2at^2 1) F= 10693 N 2) a=...

Math
The object increases by 505%

physics
QV= 1/2(mv^2) Q is the charge V= potential V= speed m= mass Q * 25000= 0.5 * 0.000839* 1170* 1170 Q= 574/ 25000= 0.023 C See if this can help

Math
Let C = Annual income (22/100)* C = Annual Budget= 400* 12 C= 400* 12*100/ 22= 21818 Her annual income is \$21818 Good luck Mariya.

pre-alg
C is correct (X1 + X2)^2 + ( y1 + y2)^2 = D^ 2 ( 2 + 4)^2 + (2+6)^2= D^2 36 + 64 = 100= D^2 D= root of 100= 10 D is the distance Ignore the minus sign in the given values

pe
pe and science objectives

eng
but is a comparison or a contrast

PE
any common activities between PE and science

PE
list the common objectives between science curriculum and PE curriculum ?

PE
what is the common objectives between science curriculum and PE curriculum ?

PE
what is the common objectives between science curriculum and PE curriculum ?

Polar equations
r^2=9

6th grade math
we don't got no pets in our family

physics
Lifted weight= Bouyant force g*[(He density)*V+650+4600]=Air density *V*g g= gravity= 9.8 N/Kg Air Density= 1.29 Kg/m^3 He Density= 0.179 Kg/ m^3 Ballon Voulme= Gas Volume= Air volume approximately Solving the equation V= 4227 m^3