Posts by parnas

Total # Posts: 2

geometry
For "circle"(O,r) , AP is the tangent at "A belongs to circle", from an exterior point P. Now, OP "intersection" circle = {B}. If BP = 1.6 = AB/5 , Then find diameter of the circle.

trig
Prove : (sinA-cosA+1)/(sinA+cosA-1) = (1+sinA)/cosA

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