# Posts by jeena

Total # Posts: 22

**Physics**

During a road test,a driver brakes a 1420kg car moving at 64.8km/h [W]. The car slows down and comes to a stop after moving 729m [W]. What is the net force acting on the car?

**Math**

b

**Math**

a

**math**

prove that, apart from y=a^x and y=0, there exist no other continuous functions such that for any real x and y the equation f(x+y) = f(x)f(y) holds.

**math**

This is a linear function that will look like a straight line if graphed. The x-intercept is 3/2 and the y-intercept is -3. The slope of this line is 2.

**physics**

four equal charges of 10microculomb is placed in4 corners of a square of side 0.2m. Calculate the force at any one of the charges..........

**Chemistry: Acid Base Equilbria**

Citric acid (pKa1 = 3.13, pKa2 = 4.76, pKa3 = 6.40) is found in citrus fruit. Calculate the approximate pH of lemon juice, which is about 5% citric acid by mass. Can someone set this one up for me?

**Chemistry**

So I found that you would have to set it up using (4.1)(3.1)/(2.9)(x-1.1). The x includes the .5 of NO2 already added, so to find how much was added to the original, find x and just subtract .5. The "x" value was the new initial value used to raise SO3 to 4.1 and ...

**Chemistry**

SO2(g) + NO2(g) reverse reaction arrow SO3(g) + NO (g) At a given temperature, analysis of an equilibrium mixture found [SO2] = 4.00 M, [NO2] = 0.500 M, [SO3] = 3.00 M, and [NO] = 2.00 M. ---How many moles/liter of NO2 would have to be added to the original equilibrium mixture...

**Chem Equilbirum**

i thought you would have to decrease x from SO2?

**Chem Equilbirum**

SO2(g) + NO2(g) reverse reaction arrow SO3(g) + NO (g) At a given temperature, analysis of an equilibrium mixture found [SO2] = 4.00 M, [NO2] = 0.500 M, [SO3] = 3.00 M, and [NO] = 2.00 M. ---How many moles/liter of NO2 would have to be added to the original equilibrium mixture...

**Chemistry Eq. Question**

The answer is only temperature changes. The equilibrium constant becomes larger with a temperature change, the forward reaction is favored and the eq. shifts to the right. If the constant becomes smaller, the reverse reaction is favored and shifts to the left.

**Chemistry Eq. Question**

3H2(g) + N2(g) reverse reaction arrow 2NH3(g) What factors would affect the equilibrium constant for the reaction above? (Select all that apply.) increasing the H2 concentration decreasing the NH3 concentration increasing the temperature decreasing the temperature increasing ...

**chem for Dr. Bob**

In the reaction 2 H2(g) + S2(g) reverse reaction arrow 2 H2S(g), Kc = 6.28 multiplied by 103 at 900 K. What is the equilibrium value of [H2] if at equilibrium [H2S] = [S2]1/2?

**Chem**

for this one, when we set up the ice chart, and we have the M of HI, and we have to subtract x, would we subtract 2x because the mols of HI is two?

**Chemistry for Bob**

Do you mind posting up an example for that please? It would help out a out: What is the activation energy for a reaction whose rate tripled when temperature rose from 28 to 53C.

**chemistry**

actually, the right answer was 35.8 KJ

**chemistry**

I got 896.3 KJ. Does this seem right?

**chemistry**

but I don't have the K or the Ea. Do you mind posting a sample?

**chemistry**

What is the activation energy for a reaction whose rate is tripled by a temperature increase from 28 to 53 C? I understand that I have to use the arrhenius equation, but how do I set it up for a problem like this?

**Chemistry**

I also just found this site. DrBob222 is great!

**Chemistry**

I tried to answer the hwk using this tip for part B, but I didn't get it right...is there another way to set it up?

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