# Posts by hmmmm

Total # Posts: 29

**Math**

R they correct? ^^^^^^^^^^ Plz plz plz let mui know?...

**language arts**

Yep the correct answers are 1.B 2.A 3.B 100% Thanks XD and _ilovepink__24

**Physics**

FLu your ans of 2b is 1.69e-4

**Physics**

yes FLu you are doing it wrong L=(mu_0*A*N^2)/L send me your values i'll post your answer

**Physics**

and in neumerator I its current and in denominator its l length

**Physics**

pi*r^2

**Physics**

formula for question 2 a)B=meu_0*N*I/l b)L=meu_0*N^2*A//l c)I=V/R d)U=1/2(LI^2)

**Physics**

radiation pressure qn a) 5.823e8 b) 3.56e22

**Physics**

sorry it is meu_0 and I is given in question meu=4*pi*1E-7 as mentioned by other friends

**Physics**

ans=1.44 for people with other values use this B=(meu not*N*I)/((2*pi*R/km) +d)

**Physics**

this was for question 4

**Physics**

B=(meu not*N*I)/((2*pi*R/km) +d)

**Physics**

ist part ans is 5.823e8

**Physics**

a) 15.705 , b) 350 c) 55.714 d) 0 other parts still working on it

**Physics**

a) R/L and 1/LC

**Physics**

ans: 0.657

**Physics**

did u get it right FLU?

**Physics**

i used this getting wrong answer

**Physics**

anyone for part b please,clearly

**Physics**

link is not allowed here, please search it by abdul rahman name on Tuesday, April 9, 2013 at 2:30pm.

**Physics**

c)0.0001386

**Physics**

sorry i slept so couldn't reply i missed that part too.

**Physics**

(b)((R_1*epsilon)/(R_1+R_2))+(100*epsilon)

**Physics**

(a)((R_1*epsilon)/(R_1+R_2))+(epsilon)

**Physics**

V1/V2=1+2*R_1/R_2 and V1/v2=100+101*(R_1/R_2)

**Physics**

not this question . but done 80% of others

**Physics**

V2=(R_2*epsilon)/(R_1+R_2) in both V2 options

**math**

put these polar equations into cartesians form: 1) theta=135 degrees 2)rcostheta=-1 for #1 is it like: (-1,1)? and for #2, X=-1, but i cant find y, any help is appreciated The slope should be sin(theta)/cos(theta) and the intercept is the origin. x=r*cos(theta) If r=1 we have ...

**math**

change equations to polar form: 1) y= -1 2) x^2 + y^2 = 4 how would i do these questions? thank u to convert to polar, you use the relationship: x = rcos(theta), and y = rsin(theta) 1) rsin(theta) = -1, r = 1-/sin(theta) 2)try this yourself by substituting as in part 1. but ...

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