# Posts by henry

Total # Posts: 13,639

**geometry**

A = 4.83*s^2 = 3.83*5^2 = 120.75 m^2.

**Math**

An ordered pair is a single point and not a line; Therefore, it has no slope.

**Math**

A. Plug your calculated value of T(2 s.) into the given Eq and solve for S, the ht. B. Tr = 2 s. = Rise time(part A). h = 0.5g*Tf^2 = 264 Ft. g = 32Ft/s^2. Tf = Fall time. Tf = ? Tr + Tf = Time to reach gnd. C. S(o) = ht. when t = 0. In the given Eq, replace t with zero and ...

**Algebra**

(1 3/4)sugar/(2/3)milk = (7/4)/(2/3) = 7/4 * 3/2 = 21/8 = (2 5/8)/1

**Math**

r^2 = X^2 + Y^2 (-12)^2 + 5^2 = 169. r = 13. sin A = Y/r = 5/13 = 0.3846.

**Math**

a. X = Sheldon's distance. x+4 = Leonard's distance. c. x + x+4 = 26. d. 2x = 26-4 = 22. X = 11.

**math**

Let X = 3: 3x/2 + 7/2 = 2^x. 3*3/2 + 7/2 = 2^3. 9/2 + 7/2 = 8. 16/2 = 8. 8 = 8. So X = 3 satisfies the Eq.

**Math: Geometry**

New Line = EF/(1/2) = 2EF.

**contemporary mathematics**

392mi/t = 322/t + 20. 392 = 322 + 20t. 20t = 392 - 322 = 70. t = 3.5 h. r = 392mi/3.5h = 112 mi/h = Speed of the P. train. r = 322mi/3.5h = 92 mi/h = Speed of the F. train.

**Physics**

X = 5m/s. = Vw. Y = 4 m/s = Vd. a. Tan A = Y/X = 4/5 = 0.8, A = 38.7o. N. of E. = 51.3o E. of N. Vr = X/Cos A=5/Cos38.7=6.4 m/s[38.7o] = Resultant drone velocity. b. d = 120/sin38.7 = 192 m. To cross the field. V*t = 192, 4*t = 192, t = 48 s.

**physics**

M(g+a)= 478. a = ?

**physics**

See previous post: Fri, 11-28-14, 9:52 PM.

**math**

A = b*h = 300yds^2. 15h = 300. h = 20 yds.

**math**

Scale = 16in/5ft = 3.2 in/ft. Width = 15Ft * 3.2in/ft. = 48 in. Height = 10ft * 3.2in/ft. = 32 in. Area = 48 * 32 = Square inches.

**AC circuits**

Note: If the voltage across the resistor is incorrect, all voltages will be wrong.

**AC circuits**

I = VR/R = 10/4 = 2.5A. = Current through all components(R,L, and C). VL = I*XL = 2.5 * 6 = j15.0 Volts. Vc = I*Xc = 2.5 * 8 = -j20.0 Volts. Z = R + j(XL-Xc)) = 4 + j(6-8) = 4 - j2 = 4.47 Ohms[-26.6o]. Es = I*Z = 2.5 * 4.47 = 11.2 Volts. Pf = Cos(-26.6) = 0.894 = Power factor...

**Physics**

There are errors in your problem that makes it difficult to understand. X = 3 km/h. Y = 10 km/h. Tan A = Y/X = 10/3 = 3.33333. A = 73.3o N. of E. = 16.7o E. of N. d1 = 5/Tan73.3 = 1.50 km downstream. d2 = Sqrt(1.5^2 + 5^2) = 5.22 km to cross. 2. Direction to offset affect of ...

**Physics**

L = 40 + 12*10^-6/Co(T-20) = 40.01. 40 + 12*10^-6T - 240*10^-6 = 40.01. 40 - 0.00024 + 12*10^-6T = 40.01. 39.99976 + 12*10^-6 = 40.01. 12*10^-6T = 40.01 - 39.99976 = 0.01024. T = 853.333 Degrees C.

**math**

post it.

**Physics**

Ws = M*g = 150*9.8 = 1470 N. Fp = 1470*sin40 = 945 N.=Force parallel to the ramp. Fn = 1470*Cos40 = 1126 N. = Normal force Fk = u*Fn = 0.54 * 1126 = 608 N. = Force of kinetic friction. Fp-Fc-Fk = M*a. 945-Fc-608 = M*0 = 0. 337-Fc = 0. Fc = 337 N. = Force of the curator. a. ...

**Math**

3x - 5x = 18. 2x = 18. X = 9. 3x = 3*9 = 27 = 1st number. 5x = 5*9 = 45 = 2nd number.

**MATH**

7.48*10^5.

**math**

I = 280/40 * 4 = 28 Amps. or E = I*R = 4*280 = 1120 v. I = E/R = 1120/40 = 28 Amps.

**PreCalculas**

2. D(3/4,-3), V(h,-3), F(5/4,-3). 1/2a = 5/4-3/4 = 2/4 = 1/2. 2a = 2, a = 1. 1/4a = 1/(4*1) = 1/4. h = 3/4 + 1/4a = 3/4 + 1/4 = 4/4 = 1. X = a(y-k)^2 + h. X = (y+3)^2 + 1, Vertex form. X = y^2 + 6y + 10, Standard form.

**PreCalculas**

1. V(2,5), F(2,-3). 1/4a = -3-5 = -8. 4a = -1/8. a = -1/32. Y = a(x-h)^2 + k. Y = (-1/32)(x-2)^2 + 5, Vertex Form

**physics**

See previous post: Tue, 12-1-15, 12:30 PM.

**physics**

a football thrown at 45o has max range: Range = Vo^2*sin(2A)/g=36^2*sin(90)/9.8 = 132.2 m.

**math**

6*Cos x + 2.46*Cos x - 1.72*sin x = 7*Cos x. 8.46*Cos x - 1.72*sin x = 7*Cos x. 8.46*Cos x - 7*Cos x = 1.72*sin x. 1.46*Cos x = 1.72*sin x. Divide by Cos x: 1.72*sin x/Cos x = 1.46. Replace sin x/Cos x with Tan x: 1.72*Tan x = 1.46. Tan x = 1.46/1.72 = 0.84848. X = 40.3 Degrees.

**physics**

V^2 = Vo^2 + 2g*h. Vo = 0. g = 9.8 m/s^2. h = 3 m. V = ?

**pysics**

Vo = 200m/s[35o]. Yo = 200*sin35 = 114.7 m/s. Y^2 = Yo^2 + 2g*h. Y = 0. g = -9.8 m/s^2. h = ?

**Physics Check My Work Please**

g is used when the motion is vertical. The block is moving horizontally. Therefore, the acceleration must be calculated: Fk = Ma, a = Fk/M = -12/8 = -1.5 m/s^2. V^2 = Vo^2 + 2a*d. a = -1.5 m/s^2. Fk is negative, because it opposed the motion.

**Math**

N = 4*8 = 32 Students.

**Physics**

PE = KE Mg*h = 0.5M*V^2. M*g = 45*9.8. h = ?

**Physics**

See previous post: Tue, 12-1-15, 12:33 PM.

**algebra**

-7y^2-4y+6 = 7y^2-4y-4-2y^2+2y+6. -12y^2-2y+4 = 0. Divide by -2: 6y^2 + y - 2 = 0. A*C = -12 = 4*(-3) 6y^2 + (4y-3y) - 2 = 0. (6y^2+4y) - (3y+2) = 0. 2y(3y+2) - (3y+2) = 0. (3y+2)(2y-1) = 0. 3y+2 = 0, Y = -2/3. 2y-1 = 0, Y = 1/2.

**Science**

Unless otherwise indicated, all angles are measured CCW from +x-axis. Vr = 725m/s[131.2o] + 106.7m/2[68.2o]. X = 725*Cos131.2 + 106.7*Cos68.2= -438 m/s. Y = 725*sin131.2 + 106.7*sin68.2 = 645 m/s. Tan A = Y/X = 645/-438 = -1.47162. A = 55.8o N. of W. Vr = Y/sin A = 645/sin55.8...

**Science**

Vp = 725m/s[W.48.8oN] + 106.7[E68.2N] = -725*Cos48.8+725*sin48.8 + 106.7*Cos68.2 +106.7*sin68.2 = -478+546i + 39.6+99.1i = -438.4 + 645.1i = 780m/s[W55.8oN] = 780m/s[N34.2oW].

**Algebra plz help**

1. Correct. 2. Correct. 3. Incorrect. See previous post: Mon, 11-30-15, 9:08 PM.

**math**

Proportion: S/m = 2/11. 16/m = 2/11, m = 88 min. 19/m = 2/11, m = 104 min.

**Physics**

Need more INFO.

**Physics**

V = 60,000/3600s = 16.7 m/s. C = pi*D = 3.14 * 0.75m = 2.36 m. Va = 16.7m/s * 6.28Rad/2.36m=44.3 Rad/s.

**physics**

Vo = 172.5m/s[30o]. Xo = 172.5*Cos30 = 149.4 m/s. Yo = 172.5*sin30 = 86.25 m/s. a. Yf^2 = Yo^2 + 2g*h. h = -(Yo)^2/2g = -(86.25)^2/19.6 = 379.5 m. b. Y = Yo + g*Tr = 0. Tr = -Yo/g = -86.25/-9.8 = 8.80 s. = Rise time. NOTE: In your Eq, use (-)9.8 for g.

**Physics**

Vo = 5.2m/s[56o]. Xo = 5.2*Cos56 = 2.91 m/s. Yo = 5.2*sin56 = 4.31 m/s. h=-Yo^2/2g + 1.1=-(4.31)^2/-20 + 1.1 = 2.03 m. Above gnd. Y^2 = Yo^2 + 2g*h = 0 + 20*2.03 = 40.6 Y = 6.37 m/s. X = Xo = 2.91 m/s.

**Physics**

Eq1: Xo = Vo*Cos A = Speed at max h. Vo = 6.8Xo. In Eq1, replace Vo with 6.8Xo: Xo = 6.8Xo*Cos A. Divide by 6.8Xo: Cos A = 1/6.8 = 0.14706 A = 81.5 Degrees.

**Physics**

Vo = 29.6m/s[46.9o]. Xo = 29.6*Cos46.9. = m/s. Yo = 29.6*sin46.9 = m/s. Y = Yo + g*Tr. Y = 0. g = -9.8 m/s^2. Tr = Rise time. Tr = ? Y^2 = Yo^2 + 2g*h. Y = 0. h = ? 0.5g*Tf^2 = h + 32. g = 9.8 m/s^2. Tf = Fall time. Tf = ? D = Xo*(Tr+Tf).

**waves andoscillation**

F = 0.13m * 130N/m = 16.9 N. a = F/M = 16.9/0.60 = 28.2 m/s^2.

**PHYSICS**

Displacement = 1000i +1000i + 200[225o] = 1000i + 200*Cos225 + 200*sin225 = 1000i - 141.4 - 141.4i = -141.4 + 858.6i = 870m[99.4o]CCW = 80.6o N. of W. V = D/t = 870m[99.4o]/960s = 0.91 m/s.

**Algebra**

(3/2,-2), (-3,7/3). Slope = (y2-y1)/(x2-x1). Slope = (7/3-(-2))/(-3-3/2) = (7/3+2)/(-6/2-3/2) = (7/3+6/3)/(-9/2) = (13/3)/(-9/2) = 13/3 * (-2/9) = -26/27.

**science**

The signal rides on a higher frequency called the carrier frequency. The carrier is modulated in the transmitter and demodulated in the radio. To demodulate means to separate the voice or music from the carrier. The carrier may be Frequency Modulated (FM) or Amplitude ...

**Math**

d1 = V1*T1 = 40 * 3 = 120 mi. d2 = V2*T2 = 55 * T2 = 55T2. Vavg. = (d1+d2)/(T1+T2) = 50 mi/h. (120+55T2)/(3+T2) = 50. 120 + 55T2 = 150 + 50T2. 5T2 = 30. T2 = 6 Hours.

**PHYSICS**

V = d/t = (300 + 100)/(60+20) = 5 m/s.

**Math**

A function crosses a vertical line only once. Your relation crosses a vertical line twice:(-8,-6), and (-8,1). The x-coordinate shows twice; that is the clue. Therefore, it is not a function.

**Math**

Correct.

**geometry**

a^2 + b^2 = c^2. a^2 + 48^2 = 80^2. a = ?

**physics**

X = 6 mi/h = Velocity of the current. Y = 13 mi/h = Velocity of the boat. Tan A = Y/X = 13/6 = 2.16666. A = 65.2o N. of E. = 24.8o E. of N. Due to the current. Direction: Head 24.8o W. of N. To offset affect of the current. Tan A =

**math**

A. h = 30Ft * 1.26cm/Ft = 37.8 cm. = Ht. of the model. 37.8cm * 1toothpick/6.3cm = 6 Toothpicks B. 37.8cm/7.6 =

**Math**

Db + Dc = 510 mi. Vb*t + Vc*t = 510. Vb*t + (Vb+33.4)t = 510. t = 8.5 hrs. Vb = ? Vc = Vb + 33.4.

**algebra**

V = y(5y^2+31y+6). A*C = 5*6 = 30 = 1*30. V = y(5y^2+(y+30y)+6) = 0. y(5y^2+y)(30y+6) = 0. y*y(5y+1)6(5y+1) = 0 6y^2(5y+1)(5y+1) = 0. 6y^2 = 0, Y = 0. 5y+1 = 0, Y = -1/5.

**physics**

Mg*h = 0.5M*V^2. h = 0.5V^2/g = 0.5*8.5^2/9.8 = 3.69 m. V^2 = Vo^2 + 2g*h. Vo = 1.5 m/s. g = 9.8 m/s^2. V = ?

**Physics**

F2*d2 = F1*d1. F2*6 = 4*3 = 12. F2 = 2 N.

**math**

X1 = ? X2 = 200. h = X1*Tan45 = (X1+200)*Tan30.

**algebra**

Width = X Ft. Length = (2x-4) Ft. Square: Each side = x + (2x-4). 2x+2(2x-4) + 4(x + 2x-4) = 264 Ft. 2x+4x-8 + 4x+8x-16 = 264. 18x - 24 = 264. 18x = 288. X = 16 Ft. Rectangle = 2*16 + 2(2*16-4) = 88 Ft. Square = 4(16+32-4) = 176 Ft. So the shorter piece of wire = 88 Ft.

**Business Math**

a. P = Po*r*t/(1-(1+r)^-t). r = 6%. Po = 0.8 * 193,000 = $154,400 = Amount financed. r = (6%/12)/100% = 0.005 = Monthly % rate expressed as a decimal. t = 30yrs * 12mo/yr. = 360 Months. P = 154,400*0.005*360/(1-1.005^-360) = $333,254.16. Int. = P-Po = 333,254.16-154,400 = $178...

**math-unit rates**

Jeff hikes 1/4 mile every 2/5 hour. John hikes 1/2 mile every 1/7 hour. A) Who hikes farther in one hour. Show work. B) Who walks faster, Jeff or John. Explain your reasoning

**math**

M(-4,4), P(x,y), N(6,-2). x - (-4) = 3/4(6 - (-4). x + 4 = 3/4(6+4). X + 4 = 30/4 = 7 1/2. X = 7/2 = 3 1/2 = 3.5 y-4 = 3/4(-2-4). y-4 = -18/4 = -4 1/2. Y = -1/2 = -0.5 P(3.5,-0.5).

**physics**

h = Vo*t + 0.5g*t^2 = 80 m. -5*t + 4.9*t^2 = 80. 4.9t^2 - 5t - 80 = 0. Use Quadratic Formula: t = 4.58 s.

**physics**

k = 251N./0.488m = 514 N/m.

**physics**

a = F/M = 19.6/2.25 = 8.71 m/s^2. V^2 = Vo^2 + 2a*d. Vo = 0. V = ?

**Algebra**

I don't see the inequality sign.

**Physics**

h = 15.2*sin22 = 5.69 m. V^2=Vo^2 + 2g*h = 0 + 19.6*5.69 = 111.6 V = 10.6 m/s.

**algebra**

Your problem doesn't make sense; please check the wording.

**Physics**

X = 1.5 m/s = Velocity of water. Y = 2.2 m/s = Velocity of the swimmer. Tan A = Y/X = 2.2/1.5 = 1.46667. A = 55.7o N. of E. Direction = 55.7o N. of W. = 34.3o W. of N.

**Math**

Sale Price = 0.96 * 850 = $816. Cost = 0.80 * 816 = $652.80

**math**

Your number is 32. 32 = 1*32. 32 = 2*2*2*2*2. Sum of its' digits = 3+2 = 5.

**geometry**

2268Ft^3 * 7.5gal./Ft^3 = 17,010 Gallons T = 17,010gal * 1min/11gal. = 1546 Min. = 27.8 Hours.

**physics**

KE = PE = M*g*h = 5*9.8*10 =

**math**

A. Correct. B. Cos15 = 22.5/L1. L1 = 22.5/Cos15 = 23.3. Length = L1 + L2 = 23.3 + 23.3 = 46.6

**science**

I did a physics experiment and now i need help with the matlab fit. can someone tell me how to do this fit in matlab? a1*[sin(a2(x-a3))/(a2(x-a3)]^2*[cos(a4(x-a3))]^2 i have a program that fits a graph to a function i just ask how to write this function.

**science**

M*V = 10 * 15 = 150.

**physics**

Incomplete.

**1Physics**

a. k=F/(L2-L1)=2*9.8/(15-10) = 3.92N/cm = 392N/m. b. F = 3.92N/cm * (20-10)cm = 39.2 N. a = F/M = 39.2/2 = 19.6 m/s^2. c. V^2 = Vo^2 + 2a*d = 0 + 2*19.6*0.10 = 3.92. V = 1.98 m/s. d.

**electron theory and ohm law**

I = E/R.

**PHYSICS**

F = M*a, M1 = F/a = 72/5 = 14.4 kg. M2 = 5/20 * M1 = 5/20 * 14.4 kg = 3.6 kg a = F/(M1+M2) = 72/(14.4+3.6) =

**physics**

Change in V. = 110km/h[S25oE] - 110km/h[S25oW]. X = 110*Cos25 - (-110*Cos25) = 199.4 m/s. Y = -110*sin25 - (-110*sin25) = 0. Change in V. = X = 199.4 m/s. The above angles are referenced to the y-axis. If the angles were referenced to the x-axis: X = 93 m/s, Y = 0. The angles ...

**physics**

0.4Vo = Vo + g*t. 0.4Vo = Vo + (-9.8*3). 0.6Vo = 29.4. Vo = 49 m/s. Vf^2 = Vo^2 + 2g*h. Vf = 0. g = -9.8 m/s^2. h = ?

**Physics**

Vf^2 = Vo^2 + 2g*h. h = ?

**Math**

X adult tickets: $3.50 ea. Y child tickets: $1.25 ea. Eq1: x + y = 37. Eq2: 3.5x + 1.25y = $73.25. Multiply Eq1 by -3.5 and add the Eqs.

**Physics**

d = Vo*t + 0.5*a*t^2 = 1000 m. Vo*34.3 + 0.5*0.0377*34.3^2 = 1000 m. 34.3Vo + 22.2 = 1000 34.3Vo = 978. Vo = 28.5 m/s.

**physics**

Tan A = Y/X = 0.165/(31/2) = 0.01065. A = 0.61 Degrees = B = Angle the wire makes with the hor. -T2*Cos 0.61 + T1*Cos 0.61 = 0. T1*Cos 0.61 = T2*Cos 0.61. T1 = T2. T2*sin 0.61 + T1*sin 0.61 = M*g. Replace T2 with T1: T1*sin 0.61 + T1*sin 0.61 = 1.54*9.8 2*T1*sin 0.61 = 15.1 N...

**Physics**

See previous post: Mon, 11-23-15, 1:20 PM.

**Physics**

3a. Momentum conserved. b. Ma*Va + Mb*Vb = Ma*V + Mb*V. 0.50*0.40 + 0.750*0 = 0.50V + 0.75*V. V = ? c. Before: KE = 0.5Ma*Va^2. After: KE = 0.5(Ma+Mb)*V^2. KE will be less after the collision.

**Algebra**

1a. Fr = 3 - 0.5L/20km * d. Fr = 3 - 0.025d. Fr = Fuel remaining in liters. d = Distance traveled in km. b. Fr = 3 - 0.025*55 = 1.625 Liters. c. No. When d equals 130 km, Fr is negative which means the tank empties before 130 km is reached. The max distance can be calculated ...

**College physics**

In an inelastic collision, the bodies stick together. Therefore, their velocities are equal. M1*V1 + M2*V2 = M1*V + M2*V. 2500*15[90o] + 1600*16[225o]=2500V + 1600V. 37,500[90o] + 25,600[225o] = 4100V. 37,500i - 18,102 - 18,102i = 4100V. -18,102 + 19,398i = 4100V. 28443[-47o...

**Science**

Mass = 15Lb * 0.454kg/Lb = 6.81 kg. d = 2Ft * 1m/3.3Ft = 0.606 m. Work=F*d = Mg * d = 6.81*9.8 * 0.606 m = 40.4 J.

**Physics**

k = 100N./0.150m = 667 N/m.

**Maths**

Vo = 20m/s[30o]. Xo = 20*Cos30 = 17.3 m/s. Yo = 20*sin30 = 10 m/s. Yf = Yo + g*Tr. Yf = 0. g = -9.8 m/s^2. Tr = Rise time = ?. h = 15 + Yo*Tr + 0.5g*Tr^2 = Meters above sea level. g = -9.8 m/s^2. h = 0.5g*Tf^2. g = 9.8 m/s^2. Tf = Fall time = ?. Tr + Tf = Time in air. Dx = Xo...

**science**

1750 - 500 = 1250g = Wt. of oil. Density = 1250g/0.5L = 2500g/L.

**math**

1. C = 7p + 1.50. 2. C = 7*4 + 1.50 = 3. C = 7p + 1.50. C = 43.50. p = ?

**physics**

P = 0.2/0.8 * 100W. = 25 W.

**Physics**

1. Vf^2 = Vo^2 + 2g*h. Vf = 0. Vo = 12 m/s. g = -9.8 m/s^2. h = 2. V = 90,000m/3600s = 25 m/s. Vo = 126,000m/3600s = 35 m/s. V = Vo + a*t. a = (V-Vo)/t = (25-35)/t = -10/t. V^2 = Vo^2 + 2a*d. 25^2 = 35^2 + 2(-10/t)*800. 625 = 1225 + (-16,000)/t. -600 = -16000/t. 600t = 16000. ...