# Posts by helper

Total # Posts: 1,867

**Algebra**

Please see your 1st post for response.

**Algebra**

C = 6000/(200 - 2x) C = 6000/(200 - 2(75)) C = 6000/(200 - 150) C = 6000/50 C = 120 mil 120,000,000 million or, is it C = 6000/(200 - 2(.75)) C = 6000/(200 - 1.5) C = 6000/198.5 C = 30.2267 mil 30,226,700 million I think it's the first, but I am not a tutor

**Algebra**

Re-check your problem. I think you are missing a part here. pollution in a lake modeled by ?

**algebra**

I don't think this problem is correct or that it can be solved. Either that, or the problem is poorly worded (to me). If they are each saving to buy the same CD's and Juan is only short $3.00, how can it be that when they combine their money they still do not have ...

**Math**

FIFO-first in, first out 300 @ 11.00 150 @ 10.50 200 @ 10.75 175 @ 10.00 100 @ 12.00 Beginning Inventory Total = 925 Ending Total = 300 Difference = sold = 625 FIFO-first in, first out Items sold are assumed to be subtracted from the first ones purchased. Go down from the top ...

**algebra**

x = lbs of cheaper coffee 10x = value of cheaper coffee 4 = lbs of better coffee 4 * 20 = 80 = value of better coffee 20 + x = lbs of mixture 5(20 + x) = value of mixture 10x + 80 = 5(20 + x) Solve for x

**Math**

Simplify 7sqrt(3/6) Breakdown the radicals 7 (sqrt3)/(sqrt6) 7 (sqrt3)/(sqrt3)(sqrt2) 7/(sqrt2) Rationalize the denominator 7/(sqrt2)*(sqrt2)/(sqrt2) 7/2 (sqrt2) or 7(sqrt2)/2

**chemistry**

Have you attempted to do any of the problems you have posted? Post your work and explain where you are stuck and someone will help you. Tutors do not do your homework for you.

**Algebra**

f(x)=8x2+4*4x you need to use parentheses do you mean? 8x^2 + 4*4x or? f(x)=(8x^2 + 4)*4x

**College Algebra**

What in particular do you need help with? Use long division as you would with any other long division problem. If you post your answer I can check it for you.

**beginning algebra**

(u - 1)^2 = 2u^2 - 3u - 29 u^2 - 2u + 1 = 2u^2 - 3u - 29 u^2 - u - 30 = 0 This does not factor. Solve by using the quadratic formula or the method of completing the square. Post your answer and someone will check it for you.

**beginning algebra**

15v^4w^8 and 9vw^5x^4 You need to find the least common factors that these two expressions have in common. LCM = 3vw^5

**beginning algebra**

2 + 7/y = 3/5 Get rid of the denominators Multiply both sides by y 2y + 7 = 3/5 y Multiply both sides by 5 10y + 35 = 3y Subtract 10y from both sides 35 = -7y Divide both sides by -7 -5 = y y = -5

**Algebra 1B**

incomplete problem. are you sure you are not missing part of the problem? your problem cannot be solved as stated.

**computers**

see the first two links below under related questions. this exact question was posted and answered below. also, you might want to look at some of the links supplied within these posts.

**algebra**

reread your post, not enough info is given and it doesn't make sense. copy the problem exactly from your book.

**algebra1**

yes, that is correct

**xacc280**

post the subject in the 'school subject' box' along with your specific question. What is "week 2, day 7 assignment"?

**phy**

see 1st link below under related questions. a very similar question was answered.

**Geometry**

sorry, I didn't know that. you should have said that in your 1st post above. the tutors would see that this question was answered and refer you to the original answer.

**Geometry**

This was answered by DrRuss on 1/21 at 6:39 am. I can't link so I pasted his answer below. I would start with a drawing as I do for most problems. Draw a reactangle 4x one side and b the other. The perimeter is then 4x+b+4x+b=11 8x+2b=11 if this is folded to a tube then ...

**biology**

see 1st link below under related questions. this exact question was posted recently. a link is provided with info that you might find useful.

**geometry**

and? please recheck your problem. not enough info.

**Physics**

see link 1 below under related questions. a very similar problem was answered.

**algerbra**

not enough info, please re-check your problem.

**ALGEBRA**

see your first post below, I solved it for you and explained

**maths**

P = a + b + c add the three sides P = 8x - 7w + 3x + 9y + 3y + 5w combine like terms

**math**

by the cofunction property cos B = sin A so, if angle B = 33 angle A = ?

**precalc**

Sine is an odd function, sin(-Î¸)= -sin Î¸

**precalculus**

2 rads to converts radian to degrees, multiply by 180/pi 2 * 180/pi = (2 * 180)/3.14 = ?

**algebra**

3x + 9y = 18 y = mx + b solve for y, 9y = -3x + 18 y = -3x/9 + 18/9 simplify the equation

**Math**

A = pi r^2 pi = 3.14 r = 5 A = (3.14)*(5^2) A = (3.14)*(25) A = ? m^2 do the multiplication for your answer I don't know what this sentence means. Is this the same as the surface area and it would be 10m?

**ALGEBRA**

I followed that 3 + x(12*4) = 24 multiply 12*4 3 + 48x = 24 subtract 3 from both sides 3 - 3 + 48x = 24 - 3 48x = 21 divide both sides by 48 48x/48 = 21/48 x = 21/48 reduce fraction x = 7/16

**ALGEBRA**

what is 'pemdas'?

**ALGEBRA**

3 + x(12*4) - 24 if that is the problem then, 3 + 48x - 24 48x - 21 48x = 21 x = 21/48 x = 7/16 you can only combine 'like terms' x terms can only be added to other x terms, constant terms can only be added to other constant terms. do you understand?

**ALGEBRA**

I need to see the original problem first to help you. why did you add 48x + 3 to equal 51x? then the 'x' is gone in the next line?

**Statistics**

see 1st link below under 'Related Questions' for this exact problem

**Taxes**

No. Each partner includes his or her share of the partnership's income or loss on his or her personal tax return.

**5th grade**

17,13,27,33,25 put the numbers in order, from smallest to largest 13, 17, 25, 27, 33 the median is the number in the middle so, the median would be 25 for the mean, add all the numbers and then divide the sum by the number of numbers that you added. 13 + 17 + 25 + 27 + 33 = ? ...

**Algebra -- Help**

Train A has a lead of 12 min. RT = D T = time train B T + .20 = time train A 90T = distance train B 80(T + .20) = distance train A 80(T + .20) = 90T 80T + 16 = 90T 16 = 10T T = 1.6 hours train B overtake train A = 1.6 hours

**geomitry**

x = 1st angle 90 - x = 2nd angle 5x - 16 = 3rd angle x + 90 - x + 5x - 16 = 180 solve for x

**math**

what is the figure? square, cube, sphere, etc?

**algebra**

-6m + 3/11 = 77/11 to solve subtract 3/11 from both sides then divide both sides by -6

**Pre-algebra**

A = 1/2 bh multiply both sides by 2 2A = bh to find h, divide both sides by b can you finish this?

**math**

sketch a right triangle A = 55 degrees c = 50 a = unknown (kite height) sin 55 deg = a/c = a/50 = 0.8192 solve for a

**help math ahhhh**

9. 5x + 4y = 1 3x ? 4y = 7 what does ? mean ?

**mathematics**

simplify 2/(x^(-3/2))= 2x^(3/2)

**AiMS MATH**

Natural numbers are the counting numbers, 1, 2, 3, etc Integers are the counting numbers, together with their opposites and zero. whole numbers are the counting numbers without the zero. Rational numbers are the set of all numbers that can be written as quotients, ie, 1/2. ...

**math**

yes, correct good job! :)

**math**

5 * (thirdrt 48) - (thirdrt 750) breakdown the radicals 5 * (3rt 8)(3rt 6) - (3rt 125)(3rt 6) can you do this now?

**math i need help please**

B. what are you having trouble with? did you find r (common ratio)? post what you found for r and the first term so I can understand what part of this you don't understand.

**MATH I NEED HELP PLEASE!**

Reposting a problem in all caps is rude. it's like you are shouting.

**Analytical Geometry**

(sin^2 x)/(sec^2 x - 1) (sin^2 x)/(tan^2 x) (sin^2 x)/(sin^2 x/cos^2 x) (sin^2 x) * (cos^2 x/sin^2 x) cos^2 x therefore, (sin^2 x)/(sec^2 x - 1) = cos^2 x

**geometry**

is this a triangle? is this a right triangle? need more specific info to solve

**MATH HELP ME NOW PLEASE!!**

see your above latest post

**algebra**

w = width 4w + 6 = length P = 2w + 2L 42 = 2w + 2(4w + 6) Solve for w

**algebra**

y = 2x + 5 y = 3x substitute, y = 3x in y = 2x + 5 y = 2x + 5 3x = 2x + 5 solve for x, use x value to find y What do the "?" mean? I see them in most of your posted problems. In this case, the "?" in this problem are part of the answer, so it didn't ...

**arithmetic**

Add 17 + 5 = 22 therefore, 17/18 + 5/18 = 22/18

**math**

G = Glen's present age B = Ben's present age B = 4/7 G G + 15 + B + 15 = 63 substitute, B = 4/7 G G + 15 + 4/7 G + 15 = 63 Solve for G

**Trig**

cos^2 x = 1 take square root of both sides +- cos x = 1 cos x = 1 cos x = -1 for what angle value is cos = 1 and cos = -1 ?

**physics**

should have added above, 1 mi = 5280 feet 1 mi = 1609.344 meters 1 mi/min = 60 mi/hr 1 mi/min = 88 ft/sec 1 mi/min = 26.8224 meters/sec sorry for the confusion. I wish there was a 'do over' button. :)

**physics**

1.00 mi in 4.00 min 1 mile/min = 60 mph 1 mile/4 min = 0.25 mi/min 1. 0.25 x 60 mi/hr = ? mph 2. 0.25 x 88 ft/sec = ? ft/sec 3. 0.25 x 26.8224 meters/sec = ? meters/sec

**Math**

circles that form E? how can a circle form an E? I don't understand

**alg2**

3x âˆ’ 7 (sqrt x) + 2 = 0 -7(sqrt x) = -3x - 2 divide both sides by -7 (sqrt x) = 1/7(3x + 2) square both sides x = 1/49 (3x + 2)^2 expand the right side you will have a quadratic equation that can be solved either by completing the square or using the ...

**alg 2**

x^3/4 * x^3/4 * x^3/4 = x^9/64

**5th grade math**

w = 78 L = 68 p = 2w + 2L p = 2(78) + 2(68) can you do this now?

**algebra 2**

v^2 + 8v + 6 = 0 this cannot be factored either complete the square or use the quadratic formula to solve

**algebra 2**

quadratic formula x = (-b +- (sqrt(b^2 - 4ac))/2a 5x^2 + 3 = -7x 5x^2 + 7x + 3 = 0 a = 5, b = 7, c = 3 plug these into the formula and solve

**alg. 2**

2.25 + .15x = 1.50 + .18x solve for x

**math**

incomplete problem

**Junior Math**

(t^2-1)/(t^2+7t+10) - (2t+4)/(t^2-t-6) factor the denominators first (t^2-1)/(t+2)t+5) - (2t+4)/(t-3)(t+2) LCD is (t+2)(t+5)(t-3) Now, can you combine over the LCD?

**ALGEBRA**

x + 2y - 4 = 0 x + 2y = 4 to find x-intercept, y = 0 x + 2(0) = 4 x = 4 x-intercept = (4.0) slope intercept form (which you got right above) y = mx + b for Line A is y = -1/2 x + 2 slope m = -1/2 If two lines are perpendicular, the slope of one is the negative reciprocal of ...

**math**

5/4 x + 1/8 = 5/8 + x 5/4 x = 4/8 + x multiply both sides by 8, (LCD of 4 and 8) then solve for x

**math**

you need to use parentheses 5/4x1 divided by 8x = 5/8 + x ? what is "4x1"?

**Algebra 1**

you're very welcome :)

**Algebra 1**

f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ? 5^2 = 5 x 5 = 25 f(5) = 5^2 + 3 f(5) = 25 + 3 f(5) = 28

**Algebra 1**

No, f(5) does not = 10 f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ? 5^2 = ? 5^2 + 3 = ? show me how you got 10

**Algebra 1**

f(x) = x^2 + 3 f(2) = 2^2 + 3 f(2) = ? 2^2 = 4 f(2) = 2^2 + 3 f(2) = 4 + 3 f(2) = 7 the answer for f(2) is 7 when x = 2, the function value = 7 now, you do the other one

**Algebra 1**

just plug in the values for x and solve f(x) = x^2 + 3 f(2) = 2^2 + 3 f(2) = ? f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ?

**math 5th grade**

5/5 * 2/3 = ? 100, 10, 1, 1/10

**Math**

I = PRT 525 = 3500 *.06 * T Solve for T (time) this is simple interest

**rectangular area**

you're welcome

**rectangular area**

A = Lw 240 = 24w w = ?

**To helper**

I do when they post more than one of the same type problem, but I understand and will only set up for now on

**Cylinder Height**

r = radius 3r = height (h) SA = 2(pi)(r)(h) + 2(pi)(r^2) SA = 2(pi)(r)(3r) + 2(pi)(r^2) SA = 6(pi)(r^2) + 2(pi)(r^2) SA = 8(pi)r^2 402 = 8(pi)r^2 402 = 8(3.14)r^2 402 = 25.12r^2 16.00318 = r^2 rounding 16.00318 = 16 16 = r^2 r = 4 height = 3r = 3(4) = 12

**algebra**

|x + 5| > 9 remove absolute value sign x + 5 > 9 x > 4 -x - 5 > 9 -x > 14 when you divide by a negative, reverse the sense of the inequality x < -14 x > 4 x < -14

**math**

(3xy - 10) - (xy + 5) 3xy - 10 - xy - 5 2xy - 15

**TO Helper**

I figured those were yours. I'm going through those now (and others). I try to help everyone I can. I don't exactly understand the donut problem either because the equation doesn't seem to work if all donuts were sold. I'm hoping REINY or another math tutor ...

**TO Helper**

the screen name "Anonymous" belongs to anyone who left the name field blank, so I have no idea which posts are yours. I scan all problems and help where I can. I am not a tutor so I only help on problems I am sure of.

**MATH ALGEBRA**

2x- 3y + 30 = 0 ? to find x and y intercepts, put equation in the form ax + by = c x intercept = (c/a, 0) y intercept = (0, c/b) to find x-intercept, y = 0 2x - 3(0) = -30 2x = -30 x = -15 x intercept = (c/a, 0) x intercept = (-15, 0) to find y-intercept, x = 0 2(0) - 3y = -30...

**4th Grade**

2/9 * 36 = 72/9 = 8

**Algebra 1**

-0.2x < -10 divide both sides by -0.2 when dividing by a neg, reverse the sense of the inequality x > 50

**algerbra**

yes, you are correct

**alg. 2**

x^2 - 16x + 4 = 0 x^2 - 16x = -4 (-16^2)/4 = 256/4 = 64 x^2 - 16x + 64 = -4 + 64 x^2 - 16x + 64 = 60 (x - 8)^2 = 60

**MATH_ALGEBRA**

you're welcome :)

**MATH_ALGEBRA**

(1) F + 1000P = 32 (2) F + 3500P = 44.50 you have to solve these 2 equations simultaneously By elimination method, to eliminate F, multiply one of the equations by -1 -1(F + 1000P = 32)= -F - 1000P = -32 Now ADD these two equations together -F - 1000P = -32 F + 3500P = 44.50 0...

**MATH-ALGEBRA**

y = 2/5x - 3 P (0,5) parallel lines have equal slopes slope intercept form of an equation y = mx + b m = slope, b = y-intercept parallel to y = 2/5x - 3, and through P(0, 5) m = 2/5 y intercept = 5 so, the equation would be D. y = 2/5x + 5

**math**

A = B + 5 B = C + 7 C = THE DIFFERENCE BETWEEN 13 AND 9 D = A - B C = 13 - 9 = 4 B = C + 7 = 4 + 7 = 11 A = B + 5 = 11 + 5 = 16 D = A - B = 16 - 11 = 5 A = 16 B = 11 C = 4 D = 5

**algebra**

quadratic formula x = (-b +- (sqrt(b^2 - 4ac)))/2a 1) x^2 = 9 x^2 - 9 a = 1, b = 0, c = -9 x = 0 +- (sqrt(0^2 - 4(1)(-9)))/2(1) x = + - (sqrt(0 + 36))/2 x = +- (sqrt36)/2 x = +- 6/2 x = +- 3 x = 3, -3 you try number 2

**math**

Supplementary angles: two angles whose measures total 180 deg x = 1st angle 3x - 4 = 2nd angle x + 3x - 4 = 180 solve for x to find the angles