# Posts by damon

Total # Posts: 30,127

PreCal
circumference = 2 pi R

Physics
as it crosses pole average speed = -20 m/s change in speed in one second = a(1) = -10 m/s so speed at top of pole = -15 m/s so how far did it fall to get to -19.5 -15 = -10 t t = 1.5 d= (1/2) g t^2 = 5(1.5)^2 19.361 h = (1/2)g t^2 = 5 * 2.25 = 11.25

Phyisic
amount dissolved (solubility) DEPENDS on temperature

Math
I do not know what a giant ine is but 2/8 + 5/8 = 7/8

Maths
http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html XN = 79+d(N-1) = -5 814 = N/2[ 2(79) + (N-1)d ] 814 = N/2 [ 79 -5 ] N = 1628/74 N= 22 then -5 = 79 +d(21) d = -84/21 = - 4

Physics
same m g h different m g h / t

Physics
M1 V1 + M2 V2 = ( M1 + M2) Vfinal You do not tell me if V2 is positive or negative, stern ramming or head on collision. initial ke = (1/2)M1 V1^2 + (1/2)M2 V2^2 final ke = (1/2)(M1+M2) Vfinal^2

Physics
v = k T^a M^b m/s = (kg m/s^2)^a (kg/m)^b m^1/s^1 = kg^a kg^b * m^a /m^b * 1/s^2a looks like a = .5 for s^-1 = s^-2a b must be -a for kg^(a+b) =kg^0 = 1 so b = -.5 now m m^1 = ?? m^.5/m^-.5 = m^(.5+.5)= m^1 yes so v = k T^.5 M^-.5 v = k sqrt (T/M)

Math
208.40 - x = 4 (150.20 - x)

Physics
at the top the velocity is indeed zero. so if you know the fall time, t" then v at the ground = - g t" the - sign is because v is down. YES, t = t' by symmetry it takes just as long to deaccelerate to the top as to accelerate down to the starting point. NO, t&...

Physics
assume hand at 17 meters height. t = rise time indeed t' = time to fall from top to 17 meters t" = time to fall from top to ground

Physics
suggest you check by doing it my way.

Physics
a = - g = -9.81 m/s^2 v = 15 - 9.81 t v = 0 at top so solve for t at top H = max height = 17 + 15 t - 4.9 t^2 now it falls from height H 17 = H - 4.9 t'^2 solve for t' , the fall time from top to 17, v here = -9.81 t' add t to t' to get flight time so far 0 = H...

Physics help!
f = k Q1 Q2 / d^2 change in Ke = 1/2 m v^2 = change in U = k Q1 Q2 (1/r2 -1/r1) r1 = 2*10^-14 + 8.22*10^-13 r2 = 2*10^-14

Physics help!
volume of drop = V = (4/3) pi r^3 mass of drop = m = 1000 * V gravity down = F = m g force up = Q E = F number of excess electrons = Q /e

Science
What would happen to your car engine if you connected the output of the oil pump directly to the inlet without routing it to the bearings etc.?

Math
-2 h^2 x / -4 h^2 = x/2

....and you should know that gravitational acceleration on the moon is about 1/6 that on the earth surface. Therefore earth weight = 6 times moon weight for the same mass.

Math
Rachel J/5 Rena (1/6)(4J/5) = 2 J/15 now remaining J - J/5 - 2 J/15 =15 J/15 - 3 J/15 - 2 J/15 = 10 J/15 = 2 J/5 now Rachel eats 2/5 *2 J/5= 4J/25 now have 2 J/5 - 4J/25 = 6 J/25 now Rena eats 2/3 so 1/3 * 6 J/25 = 2 J/25 left half of that = J/25 so 2 = J/25 J = 50

Precalculus 11
no actually you are multiplying first by 4b/4b and the second by 7a/7a so (4b/4b)[(8a-3b)/7a]-(7a/7a)[(2a+5b)/4b] ={4b[(8a-3b)]-7a[(2a+5b)]} /28ab

Physics
t = actual time racing along the road 22/60 = .367 hour tend - tbegin = (t +.367)hr and d/(t+.367) = 77.8 but d/t 89.5 so d = 89.5 t and 89.5 t/(t+.367) = 77.8 89.5 t = 77.8 t + 28.5 t = 2.438 hr driving t+ .367 = 2.805 hr = 2 hours and 49 minutes

PHYSICS
v = Vi + a t so at top 0 = 20 - 9.81 t solve for t at top T = time in air = 2 t h = h of hand + 20 t - 4.9t^2 solve for h v at hand = -20 by symmetry I do not know how high his hand was so can say nothing about ground

physics
radius = R = .5 m at top, m g = m v^2/R for contact force = 0 sso v^2/R = g so v = sqrt (g R) at top of circle which is height 2 R potential energy at top of plane = m g h potential energy at 2 R = 2 m g R loss of potential = m g h - 2 m g R = mg (h-2R) = Ke at top of circle...

Algebra
one flip in f(x) from 5 x^2 to - 6 x second from -6 x to +9 no flips in f(-x) = 2x^4 + 5x^2 + 6x + 9 so two or zero positive real roots check with http://www.emathhelp.net/calculators/algebra-1/descartes-rule-of-signs-calculator/

math
n , (n+2) 4/n - 1/(n+2) = 5/6 24/n - 6/(n+2) = 5 24(n+2) - 6 n = 5n(n+2) 24 n + 48 - 6 n = 5 n^2 + 10 n 5 n^2 - 8 n - 48 = 0 (5 n + 12)(n-4) so n = 4 n+2 = 6

Algebra
statement: reasons: Ray AC bisects <BAD (Given) m<BAC = 13x (Given) m<CAD = 6x + 21 ****GIVEN **** m<BAC = m<CAD (Definition of angle bisector) 13x = 6x + 21 SUBSTITUION OF VALUES 13x - 6x = 6x - 6x + 21 (Addition/Subtraction Property) 7x = 21 (Substitution ...

A is true, and I am sure that is what her aunt said. However the question is what is NOT true.

Yes, what I said agrees with her aunt luckily. Although my undergraduate degree is in physics my doctorate is in engineering and I was an engineering professor at MIT :)

1. NO! it is not B The atomic number is number of protons. The atomic mass is protons plus neutrons. The mass of electrons is tiny in comparison 2. If they were less stable in combined form why would they combine?

math
were the elements distributed uniformly in the set? Anything from 0 to ten

Math
So where is your attempt to do the problems?

typo
a = F/100

Physics
F = .4 * 100 * 9.81 a = 100 v = 15 - a t so t = 15/a average speed = 15/2 = 7.5 d = 7.5 t

Science
sqrt(9+16+144) 13

Physics
m v^2/r + m g = 7 m g v^2/r = 6 g r = (210)^2/(6*9.81) r = 749 meters

Science
1/f = 1/do + 1/di 1/20 = 1/30 + 1/di 60/20 = 60/30 + 60/di 3 = 2 + 60/di di = 60 cm

Science
C at 40 F at 20 object at 30, halfway between C and F so image is BEYOND C http://www.physicsclassroom.com/class/refln/Lesson-3/Image-Characteristics-for-Concave-Mirrors

statistics
95.45 % see: http://davidmlane.com/hyperstat/z_table.html I have no idea what the rule is.

Physics
height h at angle T = R - R cos T height h at 60 deg = R/2 height h at 120 deg = 3 R/2 kinetic energy (1/2)mv^2 + m g h = constant at 60 deg (1/2)v1^2 + g(R/2)=(1/2)v2^2 + g(3R/2) (v1^2 -v2^2) = 2 g R if it just makes it to the top then (1/2) m v1^2 = m g * 2R v1^2 = 4 g R (4 ...

Physics
If it is to make it around the circle then the velocity at the top must be positive. (1/2)m v^2 >/= m g (2R) if it is running around a track and can fall, then the centripetal acceleration at the top must be 1 g at least. mv^2/R >/= m g You do not say which.

physics
Ce is temp read error = e = Ce - C I assume error = e = m C + b then .7 = m(0) + b so b = .7 99.5 - 100 = -.5 = m(100) +.7 100 m = -1.2 m = -.012 at Ce = 30 e = 30 - C = -.012 C + .7 C-.012 C = 29.3 .988 C= 29.3 C = 29.7

Physics
Well the speed of light changes when passing through material, like air or water or glass, but not in a vacuum. What does temperature mean in a vacuum? Something really, really massive nearby can have an effect (Einstein, relativity, gravitational lens)

Physics

Physics
40 = u T so T = 40/u v = Vi - 9.8 t at top v = 0 t = Vi/9.8 at top. This is at time t = T/2 = 20/u so 20/u = Vi/9.8 u Vi = 196 now max range at 45 degrees so u = Vi Vi = sqrt 196 = 14 = sqrt(2 g h) 196 = 2 * 9.8 * h h = 10 meters why is range max at 45 degrees? http://www....

physic
particle 1 x = -21 + 8 t particle 2 x = 7 + 4 t so -21 + 8 t = 7 + 4 t 4 t = 28 t = 4 seconds x = 7 + 16 = 23

huh
Sorry, I do not think that A could make it back to the starting point. (even if no friction you would have to put external forces on)

Finance - Family Planning
we would get .75 * 7 % which is 5.25% if we chose the taxable account, so take the 6%

Economics - Finance
By the way, die right away to get the maximum if it stops at age 20. Best make it for 20 years after you die.

Economics - Finance
well, say we have the present value of an annuity. Usually the value goes up at interest rate r but in this case we have only inflation, negative interest (unrealistic of course, presumably your successor would deposit the insurance proceeds in an interest bearing account, ...

physics similar questions
coincidence? http://www.jiskha.com/display.cgi?id=1501514173

physics
in 2 seconds velocity decreases by 64.4 ft/s a = change in v/change in time = -64.4/2 = -32.2 ft/s^2 (which by the way is about g on earth) v = 67.8 - 32.2 (t-1) v = 100 -32.2 t

physics
(vi+v3)/2 = 12/3 = 4 and (v3+v6)/2 = 30/3=10 so v3 =8-vi and v3 = 20-v6 and v6=vi+6a so 8-vi = 20 -vi -6a or 6a = 12 a = 2 then vi + 3(2) = v3 and vi+v3 = 8 so vi+6 = 8-vi 2 vi = 2 vi = 1

physics
x = A cos (2 pi f t + pi} but cos (a+b) =cos a cos b -sin a sin b so x = A[ cos (2pift) cos pi - sin (2 pi f t) sin pi ] but cos pi = -1 and sin pi = 0 so x = -A oos 2 pi f t x = -.55 cos 35 t 2 pi f = 35 = omega 2 pi/T = 35 f = 35/2pi v = dx/dt = .55(35) sin 35 t v = 0 at t...

physics
T = sqrt(L/g) 5T = sqrt (4 L/gm) 5 sqrt (L/g) = sqrt (4 L/gm) 25 L/g = 4 L/gm gm = g [ 4/25 ]

physics
A = |A| cos thita i + |A| sin thita j B = x i + y j A dot B = 0 for perpendicular |A| x cos thita + |A| y sin thita = 0 if x = -sin thita and y = cos thita that works (also the opposite of course)

physics
average speed during stop = 15 m/s time to stop = 30/15 = 2 seconds a =change in speed/change in time= -30/2=-15 m/s^2

Physics
mu m g = 20 N mu (4)g = 20 mu = 5/g so about 0.5

Maths,physics,biology,english,arabic,chemistry
500 mL is HALF a liter. Therefore .5 + 40 = 20 grams

Science
http://socratic.org/questions/what-is-the-balanced-equation-of-c6h6-o2-co2-h2o

diploma applied physics1
3 in x direction 2 /sqrt 2 in x and 2/sqrt2 in y x force = 3 + 2/sqrt2 y force = 2/sqrt 2 }F} = sqrt [ (3 + 2/sqrt2)^2 + 9 ] tan angle above x axis = [ (2/sqt2)/(3 +2/sqrt2)]

diploma applied physics1
angle between = 2A F cos A + F cos A = F cos A = 1/2 angle we want = 2 A

math
total cents = 5 n + 25 q divide by ten ( 5 n + 25 q )/10 if the answer is an integer plus a fraction, truncate and just use the integer unless you have a saw to cut the next dime up.

Math
1 in^2 = 5 mi * 5 mi = 25 mi^2 2.5 in^2 (25 mi^2/in^2) = 62.5 mi^2

Physics
constant velocity no acceleration so F = m g Tension in cable = 400 * 9.80 = 3920 Newtons power = force * speed = 3020 * 0.6 m/s = 2352 Newton meters/sec or Watts

I do not see your drawing and do not know what your geometry is. Is the beam up at 45 from horizontal from a hinge at the wall. Is cable AB attached to the wall above and at 30 from the wall? is the 1200 at point B? is the 300 at beam center? I have no idea.

math
or 0 = 25 - 32 t t = .781 h = 5 + 25(.781) - 16(.781)^2 = 14.8

math
how about complete the square to find the vertex? 16 t^2 -25 t = -h + 5 t^2 -1.5625 t = -(1/16)h + .3125 (t - .78125)^2 = -(1/16 )h + .3125 +.61035 (t - .78125)^2 = -(1/16 )h + .923 (t - .78125)^2 = -(1/16 )(h - 14.8) t = .781 h = 14.8

Science
v =vi - 9.81 t at top 0 = 15 - 0.981 t t = 15/9.81 = 1.53 seconds rising h = 17 + 15(1.53) -4.9(1.53)^2 = 17 + 22.9 - 11.5 = 28.5 meters maxh how long to fall from there and hoe fast does it hit? 0 = 28.5 - 4.9 t^2 t falling = 5.81 seconds so totsl time = 5.81+1.53 = 7.34 s ...

math
1 -- * * * * * 6 3 -- * * * 4 * * 5 -- * 2 * * * * 3/(3*6 ) = 1/6

Physics
average speed = 402/4.7 = 85.5 m/s top speed = 2*85.5 = 171 m/s a = (171-0)/4.7 = 36.4 m/s^2

physics
approach speed = 60 + 40 = 100 km/hr so crash in 4 hours 60*4 = 240 km from T1

Physics
Maybe you mean: g = 4 pi^2 (L/T^2) simple pendulum length L, all mass m at end, small angle m g L theta = m L^2 omega^2 theta omega^2 = g/L but omega = 2 pi f = 2 pi/T 4 pi^2/T^2 = g/L g = 4 pi^2 L / T^2

Physics
Either way :)

Physics
acceleration = a = [ (2234-0) res/60s ] /.8s = 46.54 revs/s^2 revs = (1/2)a t^2 = (1/2)(46.54)(.64) = 14.9 revs

Physics
g = v^2/R

Calculus
I guess maybe assume straight shoreline running NW to SE

Algebra 2
in general though see: http://www.mathsisfun.com/algebra/matrix-determinant.html

Algebra 2
you could do (1*-3) - 7(0) = -3

Calculus
slope = 5 at x = 2 so y = 5 x + b -4 = 5 (2) + b -4 = 10 + b b = -14 so y = 5 x -14

Math
47+29 = 76 first one 47/76 second on 46/75 third one 45/74 fourth one 43/73 multiply :)

math
I assumed you put the first card back. If not then it becomes 12/51

math
The first draw is some suit. The probability that the second draw is that suit is 1/4 = 0.25

Physics
55 degrees with what?

Physics 30 meter rod?
Please proofread. Where does the string attach to the rod? What on earth do you mean by normal force on a string? Strings are usually in tension.

Physics
top at 3/2 = 1.5 s = t v = Vi - g t 0 = Vi - g t so g t = Vi = 9.81 * 1.5 = 14.7 h = Vi t -4.9 t^2 = 14.7 *1.5 - 4.9(2.25) = 22 - 11 = 11 meters note, same as average speed = 14.7/2 times 1.5 seconds

that depends
on what the total current is current = i = electron charge * electrons/second so electrons/second total = i/Qe per unit area i/(Qe area)

4.9 t^2 -24.5 t -29.4 = 0 t^2 - 5 t - 6 = 0 (t-6)(t+1) = 0 t = 6 seconds (the -1 second is before release :)

10 volts * C = q
but C times ten volts = q per capacitor

physics
C = q/V so q = C V so each stores 2.5 * 10^-12 C so we need 1.2*10^-6/2.5*10^-12 = .48*10^6 =480,000

Physics - Vectors/Forces
(6/10) 10 g = 6 g = 6*9.81 = 58.86 Newtons

Math
http://calc101.com/webMathematica/long-divide.jsp#topdoit 3 x - 1 and remainderr -4/(x+2) draw a diagonal

Math
[ 6*3 sqrt 3 - 3 sqrt 3 /4 ]^2 9*3 [6-1/4]^2 27 * 33.06 893

Physics
75 * g * 0.60

Math
5 * 5 = 25 .6 * 25 = 15 x^2 = 15 x = 3.873 meters

Physics
By the way those of us who do navigation have trouble with x, y rather than east, north

Physics
initial east,x, momentum = 7150(5) -1650(20)cos 30 = 7,171 initial north,y, momentum = 0 - 1650(20)sin 30 = -16,500 Those will not change during the collision so tan of angle south of east = 16500/7171 angle south of east = 66.5 deg Their answer, is 293.5 COUNTERCLOCKWISE from...

Math
15 x -20 y = 40 15 x + 9 y = 69 -------------------subtract -29 y = -29 y = 1 3 x - 4 = 8 3 x = 12 x = 4 x+y = 4 + 1 = 5

physics
omega = constant angular velocity v = omega r Ac = omega^2 r slips when mu m g = m omega^2 r or mu g = omega^2 r so the bigger r, the more likely the slip r = mu g/omega^2

SAT Math
You are welcome.

1. Pages:
2. 1
3. 2
4. 3
5. 4
6. 5
7. 6
8. 7
9. 8
10. 9
11. 10
12. 11
13. 12
14. 13
15. 14
16. 15
17. Next>>