Posts by azmeerahim
Total # Posts: 4
Express the non linear equation in its linear form; y=nx^(1/2)+kx
The sixth term of an arithmetic progression is 265 and the sum of the first 5 terms is 1445. Find the minimum value of n so that the sum of the first n terms is negative.
a=0.05 r=4 S8=0.05(4^8-1)/3=1092.25 S4=0.05(4^4-1)/3=4.25 Sum from 5th term to 8th term is S8-S4=1088
Given a geometric progression: 0.05, 0.2, 0.8, ... Find the sum from the 5th term to the 8th term?