# Posts by Swaastikaa

Total # Posts: 29

**Separation processes**

Can someone help me to clarify this question? I'm not sure whether the answer is a), d) or e). What is the definition of the bubble-point line? Select one: a. The line that shows when the liquid begins to boil/evaporate b. The vapour-liquid mixture region c. Saturated ...

**Chemistry**

Can someone please help to clarify this question? It is very urgent as the due is tomorrow. Thank you.

**Chemistry**

I have a question here: What is the definition of bubble-point line? a) The line that shows when the liquid begins to boil/evaporate b) The vapor-mixture liquid region c) Saturated liquid equilibrium line d) None of the above My textbook says it is saturated liquid equilibrium...

**Algebra**

Square of the 3rd side is the hypothenuse. If we square root 1025, we'll get 5sqrt(41). 5sqrt(41) - 20^2 = 625 = 25^2

**Algebra**

The answer is S. A right angle triangle follows Theorem Phytagoras rule. The sum of squares of 2 sides = length of the 3rd side For S, 25^2 + 20^2 = 1025

**Algebra**

Use distance formula: sqrt[(x1-x2)^2 + (y1-y2)^2] x1,y1 = (-2,2) x2,y2 = (4,-6) Substitute all values inside. The final answer is an even integer. Work it out! :)

**Chemistry**

The formula is Q = mc(theta), where theta is difference in temperature (final- initial) m = 43g, Cp = 0.90 J/g & theta = 25 degree C Substitute all the values into the equation above: Q = (43)(0.90)(25) = 967.5 J

**statistics**

Hi Shanice, Numbers in total : 1,2,3,4,5,6,7,8 In the first draw : 2 was selected, therefore the probability of drawing a 2 is 1/8. (since there is only one 2 in the list) In the second draw, 3 was selected. The probability is again 1/8. Therefore the overall probability is: 1...

**Math**

Hi Helen, this is easy! Solving the literal equation for 'a' means expressing the equation in terms of a. Let us see the solutions step by step: a) Multiplying the denominator a-b with y gives : y(a-b) = xab b)Expanding the parentheses y(a-b) gives ya-yb = xab c)Since ...

**algebra**

Multiple of 2 = 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30, 32,34,36,38,40,42,44,46,48,50 etc Multiple of 7 = 7,14,21,28,35,42,49,56,63,70 etc So x = 14,28,42,56,70,84,etc You should know the needed x values because you did not mention the range of x

**Algebra II, i don't get this??**

Hi Mary, Q30 : Yes you are correct. Vertex is the highest point of a graph. Moreover,the f(x) cannot be zero because if f(x) = 0, then 2|x| = -4 |x| = -2 ,which is undefined since |x|is always positive. Q21 : The answer is D. Try to substitute a number of x value and you'...

**Chemistry**

Hi Dee, this is ez! H3O+ is an hydronium ion, a Lewis acid and OH-, hydroxide ion is a Lewis base. Reaction between hydronium and hydroxide yields water molecules H3O+ + OH- ----> 2H2O This is called a neutralization reaction.

**math**

Hi Roger, For this problem, you have to cuberoot each of the element (64, x^5 & y^7) separately. For 64 , cuberoot of 64 is 4. x^5 , cuberoot is x^(5/3) y^7, the cuberoot is y^(7/3) Therefore the simplified cube radical form is 4x^(5/3)y^(7/3) Hope this helps you

**chemistry**

Thank you Dr.Bob, now I know my mistake.

**chemistry**

Hi Brittney, The solution is as follows: Always start with the basic equation: H2 + O2 -----> H2O(l) Balancing the equation above gives: 2H2 + O2------> 2H2O(l) Since 200 molecules of H2 & O2 are involved,just multiply the equation above with 200, 200(2H2 + O2)---->...

**algebra**

I disagree that the answer is c < 4. The correct answer is c > 4. Lets see the steps again: x^2 + 4x + c = 0, b^2 - 4ac < 0 4^2 - 4(1)(c) < 0 16 - 4c < 0 16 < 4c 4c > 16 Therefore c > 4

**Chemistry**

Assume ideal gas law PV = nRT Since the question mentions constant mass and temperature, P1V1 = P2V2 (1.75)(10.7) = P2(20.0L) P2 = ?

**Chemistry 12**

Use M1V1 = M2V2 12 mols/ L X 1 L/1000 mL X V1 = 0.2 mols/L X 1 L/1000 mL X 500 mL Figure out V1 (in mL) .

**chemistry**

Easy! Using Q = mc(delta) where delta = difference between final and initial temperature Given m = 47 kg Q = 3.40 X 10^2 kJ Since heat is being absorbed into the system, this is an endothermic reaction. c for water is 4.2 kJ/kg.C Substituting Q,m,c & initial temperature of ...

**Algebra**

The answer is the same anyway :)

**Algebra**

Hi Ruth,this is easy! Imagine a right angle triangle. In this case, the length of the hypothenuse is 12'.Given the angle of elevation 68 degrees. Since it is a right angle triangle,one of the remaining two angles is 90 degrees. So the third angle is 180-90-68 = 22 degrees...

**Math - Triangles**

The answer should be c). The sum of angles for a triangle is 180 degrees. Since this is an isosceles triangle, it must have two equivalent angles. Therefore 180-26 = 154 degrees. When we divide 154 by 2, we get 77 degrees. So the possible degree measure is 78.

**Chemistry**

Which one of the following cobalt complexes should be the most stable? a. [Co(NH3)6]2+ b. [CO(NH3)6]3+ c. [Co(en)3]3+ d. [CoF6]3– I think the answer is c, but not really sure. Can Dr.Bob explain ? Thanks

**Chemistry**

If the base sequence along a segment of DNA were TCGTA,what would be the antisense oligonucleotide synthesised from this sequence?

**chemistry**

For the reaction: H2PO4- + HAsO42- ---> HPO42- + H2AsO4- Which pair exists as base in the equilibrium? H2PO4- & H2AsO4- are proton donors,therefore they are conjugate acids. HPO42- & HAsO42- are proton acceptors,therefore they are the base pairs asked in the question.Is it ...

**Chemistry**

So,the answers are HAsO42- & HPO4- rite? Because from what I found,HAs04 2- is weakly basic and HPO4 2- is a conjugate base. So the bases are these two species above. M I rite?

**Chemistry**

The reaction: H2PO4- + HAsO42 ---> HPO4- + H2AsO4- Which one of the sets above lists both of the base species involved in the equilibrium? I'm confused and couldn't identify the conjugate acids and bases properly. Could Dr.Bob explain abt this problem ? Thank you

**Chemistry**

But why I can't ignore the 2x? Could Dr.Bob please explain?

**Chemistry**

The following system is at equilibrium,at 699K in a 5L container. H2(g)+I2(g)--->2HI(g) Kc = 54.9 Initially,the system had 2.50 moles of HI.What is the moles of H2 at equilibrium? Can Dr.Bob check if my steps are correct? My solution: Initially,the concentrations of H2 & I2...