Posts by Steve
Total # Posts: 53,643
93330/229000 days, so multiply that 24
just look for the proper bracket for her income, and add up the taxes for all the brackets there and below, both federal and provincial.
N is as far from M as M is from A. That is, AM = M-A = (1,2)-(-6,-6) = (7,8) AM = MN, so AN = M+AM = (1,2)+(7,8) = (8,10)
If they take x hours together, 1/x = 1/100 + 1/80 This is just a typical work problem. Forget the 10,000 envelopes. It's just 1 job. P can do 1/100 of the job in an hour, and H can do 1/80. So, add up the amounts they do.
f(x) = x^3 g(x) = 6x-5 h(x) = f(g(x)) = g^3 = (6x-5)^3
2+x is the sum of 2 and the number.
well, 5/6 = 10/12 so, what do you think?
Math - woefully incomplete
depends on the interest rate and the original amount in the account, and whether the interest is simple or compound.
V = 1/3 Bh 3V = Bh 3V/h = B
4(20+12)/(4-3) 4(32)/(1) 128
If you mean to change bases, then 1279 = 411x 9^2+2*9+7 = 4x^2+x+1 4x^2+1 = 81+18+7 = 106 4x^2-105 = 0 Nope, I guess that's not it. x has to be an integer.
First, balance the equation: 2SO2 + O2 -> 2SO3 equal moles of SO2 and SO3 So, how many moles of SO2 in 28.6 grams?
131*13/500 = 3.4 so, you will need 4 reams...
why all the words? Your keyboard has math symbols on it. A rectangular prism of length 3 1/2 ft, width 3 1/8 ft, and height 4/5 ft is shown. 3 1/10 ft^3 3 2/5 ft^3 6 5/8 ft^3 8 3/4 ft^3 since volume = length * width * height. v = (3 1/2)(3 1/8)(4/5) = (7/2)(25/8)(45) = (7*25*4...
try entering your numbers here, to see all the steps https://www.calculatorsoup.com/calculators/math/longdivision.php
Your choice has sides 3,4,5 whose sum is 12 If you can find vertices making sides of 6,8,10 then that will work. Luckily it is a right triangle, with a horizontal side and a vertical side. It's easiest if you plot the points on graph paper.
Algebra 2 A
so, what do you know? g+j+h = 9 2g+3j+3h = 23 g = 2j Can you take it from there?
Algebra 2 A
The region has vertices at (0,6) (0,8) (4,4) (8,8) So, evaluate z at each vertex.
9+x = 3
|-5| = 5 -|-5| = -5 -|-5| < 5
Not quite -3 > -|4|
?y/?x = 3/4 ?x = 6, so ?y = 9/2 (0,y) = (0,14.5)
this is just a typical mixture problem. If $x is at 4%, then the rest (7000-x) is at 7%. So, adding up the interest, you have .04x + .07(7000-x) = 420
since the height:shadow ratio is constant, you have h/100 = 1.57/10
Since the angles of an n-gon sum to 180(n-2) you have 180(n-2) = 5040 n-2 = 28 n = 30
No way to tell, unless the triangle is a right triangle, in which case the third side is either ?(7^2-4^2) = ?33 or ?(7^2+4^2) = ?65 All we really can say is that if the third side has length x, then 7-4 < x < 7+4 3 < x < 11
Construct the angle, with vertex at O Draw a circle with center at O so it intersects the sides of the angle at A and B. (Extend the sides if necessary) Place the compass on B and draw a circle of radius BA. Circle B intersects circle O at C. Since the arcs BA and CB are equal...
So, how far have you gotten? The instructions seem pretty clear; surely to have been given such an assignment means you know some java programming. If you like SPIM, look up INTERCAL!
surely you realize that the y-intercept is where the graph crosses the y-axis!?! That is, where x=0... f(0) = (-1)/(-4) = 1/4 Since the degree of the numerator is greater than that of the denominator, there is no horizontal asymptote. A simple division shows that f(x) = x + (...
why not write 3/12? Much more like math... Anyway, 3/12 = 1/4 1 + 1/4 = 5/4
(6a^2+a+5)-(2a^2+3) = 6a^2+a+5-2a^2-3 = 6a^2-2a^2 + a + 5-3 = 4a^2+a+2
the effective rate is 3%, so you need t such that 1.03^t = 2 t = log2/log1.03 = ?
If GI bisects DGI, then the two halves are equal, right? So x-3 = 2x-13 ...
(6y^2+2y^2+2y+4)-(4y^2-1) = (8y^2+2y+4)-(4y^2-1) = 8y^2+2y+4-4y^2+1 = 4y^2+2y+5 No idea where the 5y came from, unless there's a typo.
The line segment goes from -9 to 7, for a distance of 16 So, -9 + (3/8)*16 = -9 + 6 = -3 -7 is only 1/8 of the way along.
(6*r)*7 = 6*r*7 = 6*7*r = 42*r = 42r
240.5 mph @ E32.3°N
If the dimensions are x,y,z of a right rectangular prism, then all we know is that xyz = 36 I'm sure you can see that there are many many possibilities, even with integers. What have you left unsaid?
82.4/72.6 = 1.1349 or 13.45%
(-3a)x = ?(7x)+3 divide by -3x and you have a = (?(7x)+3)/(-3x) = ?(7x)/(-3x) - 1/x Now assuming that x >= 0 (so ?(7x) is real) = -1/3 ?(7/x) - 1/x An odd sort of problem. As given here, it really has very little to do with simplifying square roots. Or, given x = -1/4, ?(7x...
$2.10/gal * 12.73peso/$ * 1gal/3.785L = 7.06 peso/L
it has increased by 1/8 = 12.5%
Java Programming I
math Please help!!
#1 ok #2 Since A and B are equivalent, and D is obviously false, it must be C. #3 only C and E Since 2 is not a perfect square, its square root must be irrational B is not a repeating decimal. Its groups of digits keep getting longer, and it does not terminate. #4 also B. ...
I believe Damon meant to say y = (5/3)x
or, just to make things complete, factor and then use the product rule: f(x) = x(1-x)(1+7x^2) f'(x) = (1-x)(1+7x^2) + x(-1)(1+7x^2) + x(1-x)(14x) = 1 - 2x + 21x^2 - 28x^3
If the pre-tax price is p, then we have 1.08p = 19000
sorry - integers and whole numbers are also rational numbers. If a number is not rational, it is, well, irrational, right?
all of them. Any repeating decimal represents a rational number.
The percent paid is just (0.65)(0.90)(0.80) = .468 = 46.8% So, the price paid is .468 * 90
there are a few basic integer-sided right triangles you would do well to learn. These start with 3-4-5 5-12-13 8-15-17 7-24-25 and all multiples of these, such as 6-8-10, 10-40-50, ... However, to solve the problem in general, the hypotenuse is c^2 = a^2+b^2 In your case, we ...
just multiply tops and bottoms. For example, #3 is 1 3/5 * -3/4 = 8/5 * -3/4 = -24/20 = -6/5
1/2 + 1/4 = 3/4 so, the remaining x/4 = 4 x = 16
well, for any n, |-n| = |n| so, which two follow that pattern?
A diagram and review of the basic trig functions will show that the distance d flown by the plane between observations is d = 400 cot 1.5° - 400 cot 5° = 10700m = 10.7km 10.7km/2min * 60min/hr = 321 km/hr
2 1/4 hr = 135 min 55/135 = 11/27
the air we breathe is about 80% nitrogen.
Fix your equation before trying to pick an answer.
(5*1.2):(7*1.4):(8*1.5) = 6:9.8:12 or, 60:98:120 = 30:49:60
v = visitor's score v + 19 = 80 v = 61
math Please help!!
If you are using  as an alternative to (), then -[-5] = +5 If you are using them to mean "absolute value" you really ought to use the proper symbol, |-5| = 5 s0, -|-5| = -(5) = -5 < 5
math Please help!!
hint: both addition and multiplication are involved
math Please help!!
Looks like time to review these basic concepts. 1A 2C |-8| = 8
a linear pair make up a straight angle. So, 2n+21 + 4n+15 = 180 ...
extra credit: use the more accurate parabolic trajectories to arrive at your answer. So, the real question here is -- how close to a straight line are the bounces, really? I suspect not very close, depending on the speed with which the ball was first thrown.
basically the same way. You have an angle ?, such that tan? = 1.4/3 Then, using the same angle, tan? = 1.2/d you can either solve for ?, or eliminate it, producing the proportion used.
Since the angle of incidence is the same as the angle of reflection, we have two similar triangles. Thus, the distance d from the bounce to the second student is found by d/1.2 = 3/1.4
Is the graph piecewise straight segments? If so, then since the two segments have different slopes near (3,2) you need to pick the segment with the smaller slope, since that will produce a larger value of ? to make |f(x)-2| < 0.5
a linear pair sums to a straight angle. So, you need 3x-8 + 5x+4 = 180 Solve for x, and use that to get the angle measures.
If there are two angles of measure x, then we have x + x + 2x-4 = 180 Now just find x, and you're almost done.
nope. The mixed solution is of uniform contents.
clearly not. "Missing" energy almost always winds up as heat.
Go with bobpursley -- I misread the problem, connecting the parallel R across both series resistances.
For each branch, P = E^2/R Currently (no pun intended), we are dissipating 240^2/(25+5) = 1920 watts So, we want to dissipate 3840 watts in the other branch. 240^2/R = 3840 R = 15 ohms
You need to avoid using "x" as both a variable and the symbol for multiplication. Most people use "*" for that online. So, I'll do a few of these, and you can come back if you get stuck, rather than dumping your whole assignment at us at once. a] 6x = 6...
when you spend money, you subtract it from what you have, right? 18-2 = 16
these are just like the first one you posted. Do it in the same way.
well, just add them together, right? x+8
#1 is most common, and means that some soup was made, probably for you to eat. #2 makes sense only if several different kinds of soup were made, maybe for a taste comparison.
This is not a GP, but an AP, with a=6 d=3 and T8 = a+7d ...
just use your formula. Here, you clearly have a=2 r=3 S5 = a(r^5-1)/(r-1) = 2(3^5-1)/(3-1) = 242
since the height h = 10t - 4.9t^2, you want t when h=0. similarly, v = 10-9.8t
well, 2800 is 20^2 * 7 so ab = 140
yes. 3y = 5x y = (5/3)x
the slope is -14x/(x^^2+3)^2, so at (2,1) the slope is -28/49 = -4/7 Now you have a point and a slope, so the line is y-1 = -4/7 (x-2) See the graphs at http://www.wolframalpha.com/input/?i=plot+y%3D7%2F(x%5E2%2B3),+y+%3D+-4%2F7+(x-2)%2B1
just get out your calculator, put it in radian mode, and hit the buttons.
hint: gatos is plural.
2D ?2 is not rational zero is not only rational, it is an integer! 1 and (I guess) 3 are ok For #3, all are rational and real. C has more significant figures, but that's not a "type" of number.
clearly they meant "spilt" not "split"
The mosese parted the water and walked straight across!
well, using the equation, 1 mole of N2 and 6 moles of Na are produced. That means six times as many moles of Na are produced as N2.
24-a = a-6 a = 15, b=9 ab=k, so we want 5b = 15*9 b = 27
huh? Is it compounded twice a year? If so, (1+r/2)^(2*1.5) = 216/125 (1+r/2)^3 = (6/5)^3 1+r/2 = 1.2 r/2 = .2 r = .4 or 40%
the complement of any angle x° is (90-x)°
nice repost. so what now?
I assume you want the distance between the huts. If you draw a diagram and review your basic trig functions, it should be clear that the distance is 150 cot60° + 150 cot45°
4 and 5 are both ok.
1A 2C 3:3,5
55*20*0.5 = 550 ft^3 Now multiply by 7.48gal/ft^3
Math Help me
type in your text here. I've done the first one. http://www.wolframalpha.com/input/?i=x-y+%3C%3D+3