# Posts by Steve

Total # Posts: 52,117

**math**

sounds right, if you want your angle in degrees.

**sir steve reiny bob damon need help maths**

sure is hard to interpret your prose. If x is the input, then it appears that you are saying (16/25) * 1/(4x^2)*(1+12x/5) = 1 somewhere there should be a subtraction, since you use the word "difference" but I can't figure out what, unless maybe there's a (12/...

**College - Unweighted GPA**

total GPA It does not say anything about senior year only. Although, it occurs to me that my high school only reported my senior year's GPA. That's what HS counselors are for. Talk to yours.

**Math**

2 * 3 ?x = 5 ?y 6?x = 5?y 36x = 25y Since 36 and 25 have no factors in common, we must have x=25 and y=36

**Math-Algebra**

just write the words as math. If the tens digit is t and the units digit is u, then: t = 2u+2 10u+t = 5+3(t+u) solve for t and u

**math**

rewrite as b = -(a+1)/c b = -(1+ac) b = -(c+1)/a Now eliminate b: -(a+1)/c = -(1+ac) -(c+1)/a = -(1+ac) Now eliminate c, and you end up with a = -2 or 1

**PreCal**

since the coefficients are all real, the complex roots must come in conjugate pair. So the minimum polynomial would be y = (x-(1+?3 i))(x-(1-?3 i)) = ((x-1)-?3 i)((x-1)+?3 i) = (x-1)^2 - (?3 i)^2 = x^2-2x+1 + 3 = x^2-2x+4

**algebra**

turn the words into math: m+a = 35 2/3 m + 3/4 a = 25 now just crank it out

**algebra**

logx + logy = 6 logx - logy = 2 Now just solve as usual for logx and logy. Then raise whatever base you are using (probably 10) to the respective powers.

**Science**

3*2pi/8 = ? m/s

**satistics**

you can play around with Z table stuff here: http://davidmlane.com/hyperstat/z_table.html

**Math**

Assuming all the cards are to be used, 564 = 2^2 * 3 * 47 Looks like 2,3,6 divide 564 evenly.

**Math**

each cycle uses 6 beads, in the ratio 1:3:2 = 7:21:14 You can see that 7 cycles will use up all the reds, with others left over.

**math**

250/1200 = .2083 = 20.83%

**maths lit**

5000(0.15)(90/365) = ?

**math**

10??3

**Physics 11**

just google optics plane mirror and select "images" and you will find lots of ray diagrams

**ALGEBRA 1**

as written, you can't. If you mean -2n^2-8n+42=0 then get rid of the factor of -2, and you have n^2+4n-21 = 0 n = (-4±?(4^2+84))/2 ... Just use the formula and plug in your numbers. Sometimes it helps to factor something out, so you don't have to work with large...

**math-precalculus**

this can't be that hard. Just draw the lines. Starting at (0,0), he ends up at (-4,-2). So, how far is that?

**Algebra 1**

8a^2-a+2 = 0 x = (1±?(1^2-4*8*2)]/(2*8) = (1±?-63)/16 = (1±3?7 i)/16

**MATHS**

draw a diagram. Cut the chord in half with a radius drawn through its center. Now you can see that the radius r is r^2 = 10^2 + 12^2 If the radius is not what you want, then maybe you should have proofread your post...

**Algebra 2**

the period is 24, so y = sin(?/12 x) The temperature varies between 60 and 80, so the center-line is y=70, and the amplitude is 10 y = 10sin(?/12 x) + 70 I don't know what time the temperature is 70, but if it's at 6 am, then the horizontal shift is 6 hours, meaning y...

**Quantitative methods**

If 360 days counts as a year, then you want P such that 0.12*P = 934.20 If a year is counted as 365 days, then 0.12*(360/365)*P = 934.20

**Math**

if the number is 3xxx with x>5, then the minimum sum is 3633=15 so, that will not work If the number is 4xxx, then there must be 2 4's and 2 2's. That leaves only 4422 as a possibility.

**MATHS**

I guess if you discount B itself and Ø, then that leaves 254 "proper, non-null" subsets.

**maths**

5^(2?9) = 125^x 5^(2*3) = 125^x (5^3)^2 = 125^x 125^2 = 125^x 2 = x

**Economics(help!)**

revenue R = 60q profit P = R-C = 60q-(100+q^2) so find q such that dP/dq = 0

**math**

a+ar+ar^2 = 35 a*ar*ar^2 = 1000 now just solve for a and r.

**maths**

3xy^2 -4+2y=29 3y^2 + 6xyy' + 2y' = 0 at (1,3), we have 27+18y'+2y' = 0 y' = -27/20 So, now we have a point and a slope, so the tangent line there is y-3 = (-27/20)(x-1)

**Calc**

4xy+ln(x^2y)=7 4y + 4xy' + 1/(x^2y)(2xy+x^2y') = 0 4xy' + 1/y y' = -4y - 2/x y' = -2(2y + 1/x)/(4x + 1/y) = -2y(2xy+1) --------------- x(4xy+1) or, note that 4xy+ln(x^2y)=7 4xy + 2lnx + lny = 7 4y + 4xy' + 2/x + 1/y y' = 0 (4x+1/y)y' = -4y - 2/x...

**Calc**

x=sec(1/y) 1 = sec(1/y)tan(1/y)(-1/y^2) dy/dx so, dy/dx = -y^2 cos(1/y) cot(1/y) or, x=sec(1/y) 1/y = arcsec(x) y = 1/arcsec(x) y' = -1/[x?(x^2-1) arcsec(x)^2] you can see that they are the same, since cos(arcsec(u)) = 1/u tan(arcsec(u)) = ?(u^2-1)

**Calc**

just the good old chain rule and product rule d/dx e^u = e^u du/dx d/dx uv = u'v + uv' so, with y = x cosx + x^4 e^2x y' = (1)cosx + (x)(-sinx) + (4x^3)(e^2x) + (x^4)(e^2x)(2)

**MATHS**

arc = r? = 7(?/3) perimeter = 2r + arc

**Algebra**

h = -16t^2 + 60t = 4t(-4t+15) now work on B and C again.

**math**

since the y values differ by 0.6, and y(0)=4 y = 0.6x + 4

**Math**

very possibly, but unknown without further information.

**geometry**

reflection across what? I guess it doesn't matter, since any set of points PQRS will be transformed to some P'Q'R'S' ...

**maths**

x(x-3) = 18 Work the algebra, but it should be easy to tell which two factors of 18 differ by 3.

**Math**

40

**Math**

0x50=0 1x50=50 2x50=100 so, what do you think?

**Math**

see related questions below

**Maths**

w+a+b = 100 50w+10a+b = 500 The equations don't work out too well, so let's play around with some values that add up to Rs500, and see whether we can wind up with 100 fruits: (b,a,w) 90,1,8 = 500 91,1,8 = 501 50,40,1 = 500 50,30,3 = 500 Since the first line shows 99 ...

**Math**

r^2 = 162/18 = 9 Now you can find the 1st term, and then S8 = a(r^8-1)/(r-1)

**Aptitude**

draw a diagram. It will show 4 identical rectangular areas that are not paved. Find the area of one of those, multiply by 4, and subtract that from the total 1500m^2 area. That will be the area of the paved parts.

**maths**

a+ar = 28 ar^2+ar^3 = 252 solve for a and r, and then choose the values which make ar^6 positive

**maths**

a+7d = 5(a+2d) a+6d = a+3d+9 solve for a and d, and then you can write the sequence.

**Math**

false

**Geometry**

Do we assume that there is a single triangle, of fixed size, which we are manipulating? That is, its sides are of fixed length?

**Calculus**

if we let the base have length 20, then the altitude of the triangle is h = 15sin? so the area is a = 1/2 bh = 75sin? da/dt = 75cos? d?/dt when ? = ?/3, then da/dt = 75(1/2)(?/90) = 5?/12 m^2/s

**physics**

two postings, still no coherent question.

**Algebra**

A. factor out a 4t B,C. just plug in the value for t. C should be easy to explain if you think of what H=0 means.

**Math**

for the perimeters, just find the lengths of the sides and add them up. The areas are a bit trickier, but (a) once you get the sides, you will see that it is a right triangle, so the area is easy. (b) is easy, since it is easy to see that it is isosceles, with base=4 and ...

**Trigonometry**

1/(sin^2x-cos^2x) = 1/[(sinx-cosx)(sinx+cosx)] so, using a common denominator, 1/(sin^2x-cos^2x) - 2/(cosx-sinx) = 1/[(sinx-cosx)(sinx+cosx)] + 2(sinx+cosx)/[(sinx-cosx)(sinx+cosx)] = (1+2sinx+2cosx)/(sin^2x-cos^2x) I see several typos in your posting. If I have interpreted ...

**Math**

m/w = 3/7 w = m+12 ...

**Physics**

(5,?/2) it's right up the y-axis...

**science**

google is your friend: https://www.google.com/search?q=hachure+line+inside&ie=utf-8&oe=utf-8

**Math**

GCD(20,30) = 10 so, 10 bags, each with 2 blueberries and 3 grapes not much of a snack, eh?

**Maths**

in real math, that is 14/?6 - ?5 - ?11 to get a rational denominator, multiply top and bottom by ?6, giving 14?6/6 - ?5 - ?11 = (14?6 - 6?5 - 6?11)/6

**Physics 1st paper**

use the law of cosines: x^2 = 8^2 + 8^2 - 2*8*8*cos(60°)

**geometry**

I'd say enough to cover 1000 ft^2

**Calculus**

?dx/(x-2) = ln(x-2) first off, ln(x-2) is not defined for x < 2. So, some like to evaluate it as ?[1,3] dx/(x-2) = ln|x-2| [1,3] = ln|3-2|-ln|1-2| = ln1 - ln1 = 0-0 = 0 That is because the graph is symmetric about (1,0) so the upper and lower areas cancel out.

**Algebra**

yes

**Math**

uh, 51 ?

**Math**

50

**Math**

well, every digit except the 8 must be 9, right?

**Math**

After x months they will be equal if 310-15x = 90+15x Now, try to make some effort on the other problems, ok? The idea of this site is not to do your homework assignments. We can help, but expect you to bring something to the table, especially when several problems are similar...

**English**

#1 not #2,3 are both ok.

**English**

yes, but I've never heard, nor would I say #3 That phrase is usually reserved for nouns with superlative adjectives, as in your other example. Such as ... far and away the tallest mountain the best student the unluckiest man on earth

**Calculus**

Because sin^2? = 1-cos^2?, the logical choice is x = 2sin? 4-x^2 = 4-4sin^2? = 4cos^2? ?(4-x^2) = 2cos? dx = 2cos? d? Now your integral becomes ?3x?(4-x^2) dx = ?3*2sin? * 2cos? 2cos? d? = 24?cos^2? sin? d? Now let u = cos? and the integral is just = -24?u^2 du = -24(1/3 u^3...

**Math**

so, what are the even multiples of 13, less than 100?

**geometry**

OK - I may have misread it again, assuming that the base of the triangle is parallel to the x-axis. This is much trickier than it looks, unless the size of the triangle is somehow determined.

**geometry**

Nah - that's just too complicated. Take a look at an equilateral triangle, and slice off the top of it. (That's the piece of the x-axis between the sides of the triangle.) That small cap of the big triangle is also an equilateral triangle, and always has the same base ...

**geometry**

so, two of its vertices are (-h,-k) and (1+h,-k) Thus, the length of the base is (2h+1) That means the altitude is (1/2 + h)?3, making its coordinates (3/2, k+(1/2 + h)?3) See whether you can work out the relationship between h and k, and thus the equation for the path ...

**math**

those sure look like primes to me

**Algebra 2**

A: you have the starting value, and the decay factor, so v(t) = 250 * 0.98^t where t is the years since 2000 B: just plug in t=11 C: all pure exponentials look just the same, up to scaling.

**Calculus**

well, you are still vague. I assume you mean to revolve the triangle around the y-axis. So, revolve the small triangle. The volume is v = ?[1,2] 2?rh dx where r = x and h = y-1 = 2x-2 v = ?[1,2] 2?x(2x-2) dx = 10?/3 to verify, do it again with discs of thickness dy, where v...

**Calculus**

revolve around what? And why reflect it as well? I will say that the line from (1,1) to (2,3) is y = 2x-1 You can use that when doing the volume of a shell, which is v = 2?rh dx

**Mathematics-Integration**

Hmmm. That's a possibility. You might also try doing integration by parts twice to yield the recursive sequence derived here: https://math.stackexchange.com/questions/416162/a-recursive-formula-for-a-n-int-0-pi-2-sin2nxdx-namely-a-n

**maths**

Hmmm. That's not what I get. (1+(1/2.7176022)) = 1.36797 1.36797^3.7176022 = 2.20537 (2000/1999)^1999 = 2.7176022 close, but not nearly correct. (1+1/e)^(e+1) = 3.20527 I get a solution at x = -2000 (1+(1/-2000))^(-2000+1) = 2.7176022

**Algebra 1B**

enter your polynomials here and see all the details http://calc101.com/webMathematica/long-divide.jsp

**Maths**

or, doubling the first equation, 2x+4y = 18 2x-4y = 2 now just add the two equations, and y goes away...

**physics**

(200-11.6)/14.9 = ?

**Mathematics-Integration**

how about this: x = sin? ?(1-x^2) = cos? dx = cos? d? so, d? = dx/cos? = dx/?(1-x^2) Then the integrand is ln((2sin?+3)cos?) d? Unfortunately, that doesn't integrate any better. We can't use the same trick from before, since we don't have a definite integral. If we...

**Math**

well 10 is 5 times 2, so the distance will also be 5 times as big x/25 = 10/2

**MATHS**

see related questions below

**Geometry**

fast!

**math**

This is clearly an exercise in completing the square. 3x^2 - 6x - 2 3(x^2-2x) - 2 now add and subtract 3, leaving the value unchanged: 3(x^2-2x+1) - 2 - 3 3(x-1)^2 - 5

**Algebra 2 read plz**

what you need to do is recognize the special angles with known trig values. ?/6 is one of those angles. sin(5?/6) = sin(?/6) = 1/2 the real question is: why did you calculate (5-pi)/6 instead of just doing 5pi/6 ? If your function is f(x)=15.3sin(?x6)+44.1 propagating your ...

**Algebra 2**

stuck how? Just replace x with 5 and evaluate! too bad you could not be bothered to show us what you did. f(x) = 15.3sin(?x/6)+44.1 f(5) = 15.3sin(5?/6)+44.1 = 15.3(1/2)+44.1 ...

**Maths**

well, distance = speed * time, so 70x + 80*0.5(x+3) = 460 ...

**maths**

w*4w = 1024 w^2 = 256 ...

**Maths**

naturally the number of steps will not be measured in meters. Each 3 steps, she advances 0.5 meters (0.5+0.5-0.5) So, after 2*3*19 = 114 steps, she has advanced 19 meters. On the 116th step she has gone the last meter, and does not need to step back again.

**math**

well, surely that is 0.125 * 13650 = ?

**math**

even if you fix the mismatched parentheses, I don't see an easy algebraic way to solve this. You'd better use a graphical or numeric method. What tools do you have?

**Math**

I'd say it depends on the set. Do you have some further context?

**math**

c = ks/?m plugging your numbers, c = 55k/4 If you have an actual value for c, then you can find k.

**math- ouch!**

I got that wrong. The angles are not in the same ratio as the sides. The sines of the angles are. So, you can still draw the triangle, but then you need to circumscribe it. You can easily find online the relationship between the radius and the sides. In this case, with sides ...

**Math**

so, draw the circle. The central angles subtended by the sides will be 100,120,140 degrees. It is easy to construct a 120° angle, so you can draw the side of length 6x first. Then from its ends draw arcs of radius 5x and 7x. They will intersect at the third vertex.

**physics**

draw the velocity vectors. The resultant speed has magnitude v=?(2^2+8^2) It drifts downstream by an angle ? such that tan? = 2/8 without knowing the distance across the river, it's hard to say how far downstream it will have drifted. Also, you don't define exactly ...

**Science**

mass(g) = density(g/cm^3) * volume(cm^3)