# Posts by Scott

Total # Posts: 2,501

**Maths**

6 pts total per event 24 pts total awarded...so 4 events Betty has three 1st's and a 2nd Cathy has a 2nd and three 3rd's

**physics**

momentum (as usual) is conserved .05 * v = (5 + .05) * 10

**applied physics**

g = -980 cm/s^2 the object reaches its peak at 2 s average velocity is 980 cm/s ... so peak height is 1960 cm time up equals time down

**Physics**

KE = 1/2 m vB^2 6 KE = 1/2 * m/2 * vA^2 12 = (vA / vB)^2

**Physics**

twice the force, twice the stretch

**Math**

what design?

**Algebra**

the general equation is ... x = a(y - k)^2 + h the vertex is at the origin, so h and k are both zero a = 1 / 4p ... where p is the distance from the vertex to the focus b) the center depth is the value of x at the edges of the dish (where y equals ±7)

**Physics**

the acceleration (j) of the jet and gravitational acceleration (g) are two sides of the triangle j / g = tan(25º) ... j = 9.8 m/s^2 * tan(25º) multiplying j by 11 s will give the takeoff speed

**Psychics**

d = 1/2 a t^2 88.3 = 1/2 * 23.6 * t^2

**Math**

your "weird" answer is correct

**Math**

An = [10 * 3^(n-1)] + 1

**Technology**

the moments about the fulcrum must be equal for balance moment = mass * distance from fulcrum

**university physics**

momentum is conserved with the pellet/block find the velocity of the pellet/block the KE of the p/b is the work that compresses the spring 1/2 m v^2 = 1/2 k x^2

**Differential calculus**

the general vertex form is ... y = a(x - h)^2 + k ... (h,k) is the vertex a = 1 / 4p ... p is the distance from the directrix to the vertex

**Trig**

use Pythagoras (a^2 + b^2 = c^2) to find the angle functions then use the trig identity to find the tangent

**Advanced physics**

the period of the swing (pendulum) is related to its length the speed is not a factor

**Algebra**

a = 2 b 3(a + b) = 90

**Chemistry**

an interesting question will probably make for a lively class discussion a couple of pertinent facts ... normal exhaled air is about 15% O2 ... humans can "survive" in air down to about 6% O2

**Physics**

the work (energy) is equal to the KE of the object f d = 1/2 m v^2 123 * 45.6 = 1/2 * 10.0 * v^2

**Maths**

12 ... 4/10

**Math (Derivative)**

a) y = 6 x^-1 ... dy/dt = -6 x^-2 dx/dt ... dy/dt = (-6 / 64) * 12 b) missing y a typo?

**Math**

p(p + 1) = 3192 p^2 + p - 3192 = 0

**Science**

yes certainly if 180º apart

**Physics**

work (energy) to stop the wagon ... w = 42 * g * .18 * 16 w equals the initial KE of the wagon ... 1/2 * 42 * v^2 = w the speed of the boy is the same as the initial speed of the wagon

**Chemistry**

you are correct

**Maths**

eight "3" cards gives 24 ... 7 shy of 31 replace four "3" cards with three "5" cards and a "4" card

**Physics**

d = 1/2 a t^2 t = ?(2 * d * a)

**Physics**

the period (of the pendulum) is dependent on the length the speed of the "bob" is not a factor

**math- Trigonometry**

looks good...TALL lighthouse

**Chemistry**

.325 L * .05 M/L * 55.8 g/M

**Math**

time is inversely proportional to the number of machines and directly proportional to the number of raviolis t = 15 min * 15/75 * 6000/500

**science**

would call this a "trick" question circular path means radial (centripetal) acceleration there is no tangential component

**Math**

d = 6 233 - 53 = 180 ... so, 31 terms s = (233 + 53) * 31 / 2

**Physics**

1 kcal = 4184 joules m g h = 300 * 4184 h = (300 * 4184) / (1000 * g)

**Physics**

the gravitational potential energy becomes kinetic energy m g h = 1/2 m v^2 v = ?(2 g h)

**Physics**

20º is 1/18 of a circle (20/360) the length of the arc is ... 1/18 * 2 * ? * 1 m

**Physics**

momentum is conserved the smaller mass is 1/3 of the larger ... so it must have 3 times the speed

**Math**

check the related questions

**Physics**

f = m a ... a = f / m a = (33 - 12) / (6 + 15)

**physics**

time up equals time down h = 1/2 g t^2 = 1/2 * 32 ft/s^2v * (2 s)^2

**math**

the x-coordinate doesn't change the sign of the y-coordinate is reversed drawing a picture can help

**Math**

complex roots (zeros with i) occur in conjugate pairs f(x) = (x-6+3i)(x-6-3i)(x^5)

**math**

i = 7400 * [1 - (1 + .06/4)^(4*4)]

**algebra**

try again on the 1st one the slope formula does work

**physics**

the frictional force is ... 5 * 9.8 * .4

**Physics: Centre of Mass**

(4 * 4) + (8 * 5) > 7 * 5 ... so the CM is > 0 [4*(4-x)]+[5*(8-x)]-[7*(5+x)] = 0

**Math**

Tom has a 40 km head start ... 80 km/h * .5 h Cindy is catching up at 20 km/h ... 100 km/h - 80 km/h

**Physics**

the velocity is the vector sum of the horizontal and vertical components horizontal ... 88 m / 3.8 s vertical ... time up equals time down ... (3.8 s / 2) * 9.8 m/s^2 the max height is half the initial vertical component, multiplied by half the flight time

**Math**

distributing the 10 ... 40x + 30 - 9x

**Math**

undefined slope means the line is vertical the equation is of the form ... x = ?

**Physics**

a = v^2 / r r = v^2 / a = (54 m/s)^2 / 90 m/s^2

**Physics**

the object is moving at 20 m/s when the force is removed, the object will be decelerated to a stop (over some distance) by friction find the frictional force (m * g * .2) find the deceleration ... a = f / m find the stopping time ... t = v / a = 20 / a find the stopping ...

**pre-calc.**

100 = 10^2 10 = 10^1 logarithms are exponents -- powers of some base regardless of the base, the logarithm of 100 will always be twice the logarithm of 10

**Pre-Calc**

the values for sine and cosine are limited to the range ±1

**physics**

h = 1/2 g t^2 40 = 1/2 * 9.8 * t^2

**Physics**

gravity follows an inverse square relation two radii above the surface is three times the distance from the center (of mass) to the surface so the force would be ... g / (3^2)

**physics**

Pi * Vi / Ti = Pf * Vf / Tf the T is absolute (Kelvin) temperature

**physics**

you're adding two vectors 2^2 + 4^2 = s^2

**Physics**

need the drawing for a solution or, at least, more data

**Physics**

(b) f = m a ... a = f / m = 900 / 1800 a = .5 m/s^2 so it takes 40 s to stop ... 20 / .5 ave velocity is ... (20 + 0) / 2 distance = v * t

**Algebra**

.12 x + .10(7500 - x) = 890 .02x + 750 = 890

**Science Psysics**

the gravitational potential energy at the top of the ramp becomes kinetic energy at the bottom of the ramp (minus the work done by friction) m g h - f d = 1/2 m v^2 [6 * 9.8 * 3.5 sin(31º)] - (17 * 35.) = 1/2 * 6 * v^2

**Algebra 2**

x^2 - 8x + 14 = 0 use the quadratic formula to find x x = {8±?[64-(4 * 1 * -14)]} / (2 * 1)

**Algebra 2**

use the quadratic formula to find the value(s) of x

**physics**

momentum is conserved (1200 * 14) + (2000 * 25) = ... (1200 + 2000) * v

**Chemistry**

8 half-lives 625 * (1/2)^8

**Chemistry**

3 half-lives m * (1/2)^3 = 6

**Chemistry**

2 days (48 hr) is 8 half-lives 10.0 * (1/2)^8

**Chemistry**

5 / 20 = 1/4 = (1/2)^2 2 half-lives

**Algebra 2**

3 half-lives 345 * 1/2 * 1/2 * 1/2

**Need help with math**

people who own both (b) will be counted in both groups (laptop owners and desktop owners) when you count all of the households, the "both" group is only counted once 130 + 30 + 50 + b = 250

**Mathematics**

the area is side times altitude 30 * 15 = 25 * x

**Math**

8 oz per cup

**Science**

switching the electrical polarity also switches the magnetic polarity

**Science 7**

switching the wires changes the magnetic polarity of the coil

**algebra 2**

3000 = 2000 [1 + (.038 / 2)]^(2t) ... t is the number of years 1.5 = 1.019^(2t) log(1.5) = 2t * log(1.019)

**Physics**

the gravitational potential energy becomes work driving the pipe m g h = f d 450 * g * 1.5 = f * .45

**Math**

y^2 + 5y - 6 = y^2 - 5y + 6 + 8 5y + 5y = 6 + 8 + 6

**Math**

(x + 2)^2 - x^2 = 44 x^2 + 4x + 4 - x^2 = 44 4x + 4 = 44

**Math**

28x - 7y = -119 ... add to 1st eqn

**math**

draw a Venn diagram of three intersecting circles enclosed in a box label the circles S, F, and G S/F/G -- 2 ... these are in all the two way intersections S/F -- 10 + (2) S/G -- 4 + (2) F/G -- 6 + (2) S -- 19 + (2) + (10) + (4) F -- 13 + (2) + (10) + (6) G -- 10 + (2) + (4...

**Math**

A = 3M A - 3 = 4 (M - 3) = 4M - 12 3M = 4M - 9

**Math**

18 r^5 = 2/27 9 r^5 = 1/27 r^5 = 3^-3 / 3^2 = 3^-5

**Math Grade 9**

square rooting implies that the yard is square ... from the result of your answer, this is not the case the "perimeter" in this problem, is only three sides A = L * W = 50 P = L + 2W a good investigation might consist of a table comparing L, W, and P ... remember, ...

**Algebra**

p + r = 18 35p + 49r = 728 solve the system by substitution or elimination

**math**

10 is a factor ... ?????0 The hundred thousands and ten thousands digit are the same and are odd ... must be less than 3, and odd ... 11???0 The sum of the hundreds and the thousands digits is 10 ... neither one can be zero The tens digit is a cube number and is one more than ...

**Physics**

the blocks accelerate at ... 60/18 = 10/3 m/s^2 the force necessary for b ... 15 * 10/3

**Science**

you think right

**College Calculus**

the max height is on the axis of symmetry of the parabola ... t = -b / 2a ... -96 / (2 * -16) ... plug into the equation to find s velocity is ds/dt ... solve for t when s is zero ... plug into the 1st derivative of s(t)

**math**

24 / 5 m = 30 / x m 24 x = 150

**Math/7th**

3 / 2 = 14 / x 3x = 28 x = 28/3 = 9 min 20 sec

**physics**

900 watts is 900 joules per sec 5 min is 300 sec 900 * 300 = 270 kJ

**Physics**

the car goes through a quarter of a circle in 10 s, at a speed of 15 m/s so the circumference of the circle is ... 10 * 15 * 4 = 600 m ... the radius is ... 600 / 2π the centripetal force (which causes the car to travel in a curved path) is ... m v^2 / r when the car is ...

**Science/Physics**

n = c / (.612 c) = 1 / .612

**algebra**

p = 94 e^(.06 * 4)

**Math**

suppose that 8 of Maggie's hours coincided with Gina's 8 hours that would complete 1/3 (8/24) of the project Maggie then finishes the remaining 2/3 in 22 hours (30 - 8) so Maggie would take 33 hours alone ... she does 24/33 or 8/11 working 24 hours with Gina Gina does ...

**math**

3S + 10 = 2L 2S + 2L = 100 3S + 10 = 100 - 2S 5S = 90

**math**

S + L = 50

**Physics**

a = 75/360 * π * r^2 da/dt = 75/360 * π * 2r dr/dt da/dt = 75/360 * π * 2 * 6 * 0.3

**math please help**

42 / (r + 6) = 10 / r 42 r = 10r + 60