# Posts by Henry

Total # Posts: 14,127

**maths**

Juice = x Liters. Lemonade = 4x Liters. x + 4x = 1 Liter. X = 0.2 Liters. 4X = 4*0.2 = 0.8 Liters. = a. Cost = 0.2*6 + 0.8*0.5 $1.60. b. Profit = Sale Price-Cost = 2.00-1.60 = 0.40. %Profit = (Profit/Cost)*100 =

**Maths**

d = (3 3/4km)/Lap * 4 1/2Laps. d = 15/4 * 9/2 = 135/8 = 16 7/8 km.

**physics**

Ro + Ro*0.0068/oC*(T2 -T1) = 1.15Ro. Divide both sides by Ro: 0.0068/oC*(T2-20) = 1.15, T2-20 = 169, T2 = 189oC. %Increase = ((T2-T1)/T1)*100% %Increase = ((189-20)/20)100 = 845%.

**As physics**

See your previous post: Thu, 11-30-17, 7:02AM.

**Physics**

Vs = 332 + 0.6T. 341 = 332 + 0.6T, T = 15 degrees Celsius.

**Physics**

All angles are measured CCW from +x-axis: Fr = 10m[135o] + 20m[30o] + 35m[270o]. Fr = (-7.07+7.07i) + (17.32+10i) + (0-35i), Combine like-terms and convert to polar form: 10.25 - 17.93i = 20.7m[-60o] = 20.7m[60o] S. of E.

**physics**

Incomplete.

**physics**

In.etcomple

**Finance**

The answer is b.

**Physics**

d = 325m/s * 3.10s = 1008 m. = Hor. distance traveled by sound. d = 1008/Cos22 = 1087 m. V = 1087m/3.1s = 350.5 m/s. = Speed of the plane.

**Physics**

Fo = ((Vs+Vo)/(Vs-Vh)*Fh. Fo = ((343+22)/(343-35))*1500 - 1777.6 Hz. Fo = Freq. heard by the observer(slower driver). Vs = Speed of sound. Vo = Speed of the observer(slower driver). Vh = Speed of the horn(faster driver). Fh = Freq. of the horn.

**Finance**

My answer is b.

**physics**

b. 40rad/s * 1rev/6.28rad * 5s = 31.85 rev.

**prealgebra**

What question?

**Algebra 1**

(x-1)^2+5 = 10. (x-1)^2+5-10 = 0, x^2-2x+1-5 = 0, x^2-2x-4 = 0, Cannot be factored. Use the quadratic formula.

**Algebra 1**

4x^2-7x = x. 4x^2-7x-x = 0, 4x^2-8x = 0, Factor out 4x and finish the problem.

**Algebra 1**

Use AC method of factoring. 25x^2-30x+9 = 0. A*C = 25*9 = 225 = 3*75 = (-15)*(-15). Select the set of factors whose sum = -30. 25x^2 + (-15x+(-15x)) + 9 = 0. (25x^2-15x) + (-15x+9) = 0, 5x(5x-3) + -3(5x-3) = 0, (5x-3)(5x-3) = 0, 5x-3 = 0, X = 3/5.

**Algebra 1**

5x^2 = 80. 5x^2-80 = 0, 5(x^2-16) = 0, 5(x-4)(x+4) = 0, Divide both sides by 5: (x+4)(x-4) = 0, x+4 = 0, X = -4. x-4 = 0, X = 4.

**As physics**

See Similar Questions: College math, Thu, 4-28-11, 3:04PM.

**As Physics**

A. M1*V1 + M2*V2 = M1V + M2V. 5*10^4 * 2.50 + M2*0 = 5*10^4V+4*10^4V, 7.5*10^4 + 0 = 9*10^4V, V = 0.833 m/s. B. Before collision: KE1 = 0.5*M1*V1^2. KE1 = 0.5*5*10^4 * (2.50)^2 = 3.125*10^4 Joules. After collision: KE2 = 0.5*M1*V^2 + 0.5*M2*V^2, KE2 = 0.5*5*10^4*V^2 + 0.5*4*10...

**As Physics**

Conservation of kinetic Energy. 0.5*M2*V^2 = 0.5*M1*V^2 + 0.5*M2*V^2. 0.5*0.25*0.2^2 = 0.5*0.3V^2+0.5*0.25V^2 0.005 = 0.15V^2 + 0.125V^2, =.005 = 0.275V^2, V^2 = 0.0182, V = 0.135 m/s.

**algebra**

Incomplete.

**physics**

Incomplete.

**physics**

All calculations are done with the assumption that the resistance of the light bulbs remain constant. P = E^2/R. 200 = 120^2/R, R = 72 Ohms. P = 60^2/72 = 50 Watts = Power dissipated by each bulb.

**Physics**

a. Fn = M*g - Fap = 5*9.8 - 30 = 19 N. = Normal force. b. F = 30N./5 = 6N.

**Science - Physics**

P = F*d/t = Mg*d/t = 50*9.8 * 0.50/60s*40 = 163.3 J/s = 163.3 Watts.

**Advanced Algebra**

P = Po + Po*r*t =925 + 925*(0.187/12)*1 = 939.41 0.035 * 939.41 = $32.88 Pay 32.88 because it greater than $30.00.

**Physics**

a. Range = Vo^2*sin(2A)/g. 114 = Vo^2*sin(70)/9.8, Vo = 34.5 m/s. b. Xo = Vo*cos35 = 34.5*cos35 = 28.2 m/s. = Hor. component. Yo = 34.5*sin35 = 19.8 m/s = Ver. component. Y = Yo + g*Tr. 0 = 19.8 -9.8Tr, Tr = 2.02s. = Rise time. = Time to reach the wall. h = ho + Yo*Tr + 0.5g*...

**Math**

r = 3.6%/yr. * 12yrs. = 43.2%

**Physics**

KE = 0.5M*V^2. 360 = 0.5*5000*V^2, V = ?.

**physics**

V = 175mi/h * 1600m/mi * 1h/3600s = 77.8 m/s. V = Vo + a*t. 77.8 = 0 + a*2, a = 38.9 m/s^2. Fap = M*a. 4.2*10^6 = M*38.9, M = ?.

**Physics**

M*g = 890, M = 890/9.8 = 90.8 kg. Fn = Mg*cos 0-T*sin30 = 890 - 0.5T. Fk = u*Fn = 0.2(890-0.5T) = 178-0.1T. T*Cos30-Fk = M*a. 0.866T-(178-0.1T) = 90.8*0.8, 0.866T-178+0.1T = 72.64, T = 259.5 N. = Tension in the string.

**math**

P = Po(1+r)^n. r = 0.028/365days = 7.67*10^-5/day. n = 365Comp./yr. * 23yrs. = 8395 Compounding periods. 44,800 = Po(1.0000767)^8395, Po = $23,529.44 = Initial investment. I = P-Po.

**Math (unit rates)**

d =r*t = 65mi/h * 45/60 = 48.75 miles.

**business finance**

I. P = Po + Po*r*t. P = 75000 + 75000*0.14*5 = II. 150,000 = 75000 + 75000*r*5. r = ?.

**business finance**

P = Po(1+r)^n. r = 0.11/yr. * 0.25yr. = 0.0275/qtr. n = 4 comp./yr. * 4yrs = 16 Compounding periods. P = 65000(1.0275)^16 = $100,328.11 in 4 yrs. 90 days = approx. 1/4 of a yr.

**physics**

M1 = 0.405 kg, M2 = 71.5 kg. M1*V1 + M2*V2 = M1*V + M2*V. 0.405*11.5 + 71.5*0 = 0.405V + 71.5V. 4.66 + 0 = 71.905V, V = 0.0467 m/s. = 4.67 cm/s. v 8

**Physics**

B. Work = F*d = 28 * (0.19-0.162) = 32.8 Joules. C. Length = 1m/1000N * 56N = 0.056 m. or 56N/(1000N/m) = 0.056 m.

**intro to physics**

a. V^2 = Vo^2 + 2g*h. V^2 = 0 + 19.6*5 = 98, V = 9.90 m/s. b. Fn = Mg*Cos A = 2.25*9.8*Cos 0 = 22.1 N. = Normal force.

**Physics**

Fr = 8N[0o] + 6N{45o] + 10N[200o]. Fr = 8 + (6*Cos45+i6*sin45) + (10*cos200+i10*sin200), Fr = 8 + (4.24+4.24i) + (-9.40-3.42i), Fr = 2.84 + 0.82i = 2.96N[16.1o]. = Resultant force. 16.1o Above +x-axis.

**Physics**

See previous post: Today, Wed, 11-22-17. 1:04 AM.

**physics**

Vo = 26m/s[45o]. Xo = 26*Cos45 = 18.38 m/s. = Hor. comp. Yo = 26*sin45 = 18.38 m/s. = Ver. comp. a. Y^2 = Yo^2 + 2g*h. 0 = 18.38^2 + (-19.6)*h, h = ?. Range = Vo^2*sin(2A)/g. Range = 26^2*sin(90)/9.8, b. Range = Xo*T. T = ?.

**Physics**

M*g = 5 * 9.8 = 49 N. = Wt. of container. Fp = 49*sin28 = 23.0 N. = Force parallel to the incline. Fn = 49*Cos28 = 43.3 N. = Normal force. Fk = u*Fn = 0.4 * 43.3 = 17.3 N. = Force of kinetic friction. a. Fp-Fk = M*a. 23-17.3 = 5*a, a = 1.14 m/s^2. b. d = 0.5a*t^2. t = ?.

**Science**

V^2 = Vo^2 + 2a*d. 0 = 30^2 + 2a*50, a = -9 m/s^2. -F-Fk = M*a. -F-295 = 880*(-9), F = ?.

**physics**

All angles are measured CCW from +x-axis. Disp. = 300km[120o] + 400km[30o]. Disp. = (300*Cos120+300*sin120)+(400*Cos30+400*sin30), Disp. = (-150+260i) + (346.4+200i). Combine like-terms and convert to polar form.

**Physics**

L = Lo + Lo*(T-To)oC*u. L = 73.8 + 73.8(-45.3-15.7)1.24*10^-5. L = 73.8 + (-.0558) = 73.74 m.

**physics**

h = 2.5*sin18. PE = M*g*h.

**Physics**

a. Disp. = -1 + 2i + 4 = 3 + 2i = 3.61. Blocks. b. Tan A = 2/3 = 0.66667. A = 33.7o = Direction.

**Physics**

Circumference = pi*2r = 3.14 * 3*10^11 = 9.42*10^11 m. d = 9.42*10^11m/rev * 1rev/6.28rad * 7.29*10^-5rad/s * 3600s/h * 24h/da * 365da/yr. * 4*10^9yrs = 1.379*10^24 m.

**Physics**

a. Circumference = pi*D = 3.14 * 0.85 = 2.67 m. 1rev/2.67m * 45m/s * 60s/min = 1012 rev/min.

**physics**

V^2 = Vo^2 + 2a*d. 0 = 2^2 + 2*a*2/3, a = -3 m/s^2. Fap-Fk = M*a. 0-Fk = -3M, Fk = 3M. = Force of kinetic friction. uk = Fk/Fn = Fk/Mg = 3M/10M = 0.30 Fn = Normal force.

**physics**

Ma*Va + Mb*Vb = Ma*V - Mb*V. Ma*Va + Mb*0 = V(Ma-Mb), Divide both sides by V: Ma*Va/V = Ma-Mb, Divide both sides by Ma: Va/V = 1-Mb/Ma, Mb/Ma = 1 - Va/V.

**science**

I'm assuming the body is brought to rest in 5 sec. Vo = 60km/h = 60,000m/3600s. = 16.67 m/s. V = Vo + a*t. 0 = 16.67 + a*5, a = -3.33 m/s^2. Fap = M*a. =200 = M*(-3.33), M = 60.0 kg.

**Math help**

n/-3 + 5 > 4. Multiply both sides by(-3) and reverse the inequality sign: n -15 < -12, n < 3. When an inequality is multiplied or divided by a negative number, the inequality sign should be reversed.

**Physics**

Wavelength = V/F. V = The speed of light. F = Frequency. The wavelength is inversely proportional to the frequency. In other words, if the frequency is doubled; the wavelength is cut in half.

**physics**

All angles are measured CCW from +x-axis. Disp. = 65km[58o] + 42km[21o]. (65*Cos58+65*sin58) + (42*Cos21+42*sin21 = (34.44+55.12i) + (39.21+15.05i) = 73.65 + 70.17i = 101.7km[43.6o].

**math**

1. V = Vo(1-r)^t. Vo = Initial value of car. r = 0.08/12mo. = 0.0067/mo. t = Time in months. V = Vo(1-0.0067)^1 = 0.9933Vo. 2. V = Vo(1-r)^t. r = 0.08/52wks. = 0.00154/wk. t = Time in weeks. V = Vo(1-0.00154)^1 = 0.9985Vo. 3. V = Vo(1-r)^t. r = 0.08/365da. = 0.000219/day. V = ...

**physics**

A. t = 6.50h * 3600s/h = 23,400 s. Po = W/t = 5.50*10^6J/2.34*10^4s = 235 J/s = 235 Watts. B. Work = F*d = Mg*d = 1850*9.8 * 1.2 = 21,756 J. t = 21,756J./(235J/s) = 92.6 s.

**financial - simple interest**

Pa = 1.0976 * 8000. = Principal after 4 yrs. Pb = 1.1464 * 7000 = Principal after 5 yrs.

**financial - simple interest**

Investment A: Rate = r. Po = $8000. T = 4 yrs. Ia = Po*r*T = 8000*r*4 = 32,000r = Int. of Investment A. Investment B: Rate = 1.5r. Po = $7,000. T = 5 yrs. Ib = Po*1.5r*T = 7000*1.5r*5 = 52,500r = Int. of investment B. Ib = Ia+2000 52,500r = 32,000r + 2000. 20,500r = 2000 r = 0...

**Physics**

M*g = 35 * 9.8 = 343 N. = Wt. of the desk = Normal force(Fn). A. Fap-Fs = M*a. 275-Fs = 35*0 275-Fs = 0 Fs = 275 N. = Force of static friction. us = Fs/Fn = 275/343 =[ B. Fap-Fk = M*a. 195-Fk = 35*0 Fk = 195 N. = Force of kinetic friction. uk = Fk/Fn = 195/343

**math**

post it.

**math**

25x - 16 >= 234. 25x >= 234 + 16 25x >= 250 X >= 10 years.

**Math**

d = -8200 - (-6500) = -1700 Ft. So the six-gill shark swims 1700 Ft. below the fang-tooth fish.

**Math**

Slope(m) = 2, P1(3,8), P2(x,y). m = (y-8)/(x-3) 2 = (y-8)/(x-3) Cross multiply: 2(x-3) = (y-8) 2x-6 = y-8 Eq: Y = 2x + 2. Check: Y = 2*3 + 2 = 8.

**Physics**

A. F = Fap/Cos A = 290/Cos40 = 379 N. = Force parallel with the ramp. Work = F*d = 379 * 20 B. F-Fk = M*a. 379 - 65 = 20*a. a = ?. d = 0.5a*t^2. d = 20m, t = ?.

**physics**

Correction: Fr = -Ft = -7.47*10^5N.

**physics**

Yes, the net force is 0, but the book did not ask for the net force; it asked for the force exerted on the tanker by the water. M*g = 1.57*10^8 * 9.8 = 15.4*10^8N. = Wt. of the tanker(Ft) = Normal force(Fn). Fr = u*Fn = 15.4*10^8u. = Resistive force of the water. Ft + Fr = M*a...

**physics**

F1 * d1 = F2 * d2. 16.4 * 0.590 = F2 * 0.470. F2 = ?

**physics**

F' = F*Cos A = 65*Cos31 = 55.7N = Hor. component = Component that pulls the wagon. Work = F'*d.

**physics**

F = M*g = 0.077 * 9.8 = 0.755 N. Work = F*d.

**physics**

In Scientific notation, the number on the left side of the decimal is always less than 10(a single digit number): F = 139,712. = 1.39712*10^5. If I had placed the decimal between 13 and 9, that would not be in scientific notation; because 13 is not a single digit number. After...

**physics**

Vo = 89 km/h = 89,000m/3600s = 24.72 m/s. A. V^2 = Vo^2 + 2a*d. 0 = 24.72^2 + 220a. a = -2.78 m/s^2. F = M*a = 1070 * (-2.78) = -2972 N. or 2972 N. of opposing force. B. V^2 = Vo^2 + 2a*d. 0 = 24.72^2 + 4.68a. a = -130.6 m/s^2. F = M*a = 1070 * (-130.6) = -139,712 N. Ratio = ...

**Physics**

I will give you the meaning of the abbreviations, but you will have to write them into the equations. F = Force in newtons. 2. M = Mass in kilograms. 3. g = Acceleration due to gravity in m/s^2. 4. d = Distance in meters. 5. J = Joules. 6. s = Time in seconds. 7. Pin = Power ...

**Physics/**

I. F = M*g = 850 * 9.8 = 8330 N. = Tension in the cable. II. Po = F*d/t = 8330 * 12/40 = 2499 J./s = 2499 Watts. = Power out. Pin = Po/Eff. = 2499/0.60 = 4165 Watts. = Input power.

**Physics**

See previous post: yesterday, 9:38PM.

**Physics**

M*g = 22.5 * 9.8 = 220.5 N. = Wt. of object = Normal force(Fn). Fk = u*Fn = 0.44 * 220.5 = 97 N. = Force of kinetic friction. Fap-Fk = M*a. 0-97 = 22.5a a = -4.3 m/s^2. V = Vo + a*t. 0 = 4.2 - 4.3t t = ?.

**Finance**

a. RATIO = 911/6045 = 0.151 = 15.1%. The max allowed is 43%. So 15% is very good. b. RATIO = (911+300)/6045 = 0.200 = 20%. The ratio is still good. Therefore, they could easily purchase another vehicle.

**Math**

b. Y = mx + b. Y = 0.5x + 3.30. The slope-intercept form is a perfect fit for this transaction. c. Slope(m) = Cost per mile. y-intercept(b) = Flat fee. Y = Total cost. x = The number of miles driven.

**Physics**

M*g = 180,000 * 9.8 = 1,764,000 N. = Wt. of locomotive = Normal force(Fn). Fr = ur*Fn = 0.002 * 1,764,000 = 3528 N. = Force of rolling friction. A. Fap-Fr = M*a. 0-3528 = 180,000*a a = -0.0196 m/s^2. V = Vo+a*t. 0 = 19 - 0.0196t. t = 969.4s. B. V^2 = Vo^2 + 2a*d. 0 = 19^2 - 2*...

**Physics**

M*g = 4500 * 9.8 = 44,100N. = Wt. of the truck. Fp = 44,100*sin7 = 5374 N. = Force parallel with the slope = Friction force required to prevent the truck from moving.

**Chemistry **

Hello this is my first experiment I've ever done before and it was fun but I gotta figure out what NaCl produced and what it yielded in percentage. Can someone double check my work. Na2CO3+2HCl=2NaCl+H2O+CO2 Mass of empty crucible & cover: 33.076g Mass of sodium carbonate ...

**Algebra 2**

1. A = (13pi/30)/(2pi) * 360o. A = 13pi/30 * 1/2p1 * 360 A = 13/30 * 1/2 * 360 = 78o. 2. d^2 = (8-4)^2 + (7-4)^2 = 25. d = 5. 3. Y = (x+8)^2 - 2. Y = x^2 + 16x + 64 - 2 = x^2 + 16x + 62 (-8,-2). 4. Opens Upward. 5. pi radians = 180o. 9. csc B = 5sqrt(3)/5sqrt(2) = sqrt(3)/sqrt...

**physics**

a. F = M*a. a = F/M = -8000/1000 = -8m/s^2. V^2 = Vo^2 + 2a*d. 0 = 40^2 - 16d d = 100m. to stop. b. V^2 = Vo^2 + 2a*d. V^2 = 40^2 - 16*45 = V = ?.

**Math**

Mark's age = X years. Jack's age = X+4 years. Dave's age = (X+4)-8 = X-4 years. J*D = (x+4)(x-4) = x^2-16. a. M*P = (x+4)(x-4)+16 = x^2-16+16=X^2 = x*x. Therefore, Mark and Paul are each X years old and twins.

**Chemistry**

Can someone help me find the grams of what I produced. This is my first experiment I've ever done before and it was fun. Na2CO3 + 2HCl = 2NaCl + H2O + CO2 Empty crucible is: 33.076g I Started with 0.575 Na2CO3 How do I set this up to find how much NaCl that I produced with...

**Maths**

100% - 20% + 8% = 88% = 0.88. Cost = 0.88 * 4000 = $3,520.

**Math**

John's sale = $X. Steve's sale = $3X. Paul's sale = $12X. Charlie's sale = $8X. x + 3x + 12x + 8x = 4*$200. X = ?. 3X = ?. 12X = ?. 8X = ?.

**Math**

Multiply both sides by 8/7: 8/7*3/10in = 8/7*7/8mile. 24/70in = 1 mile 12/35in = 1 mile. 0.343in = 1 mile.

**Estimating the product of decimal and a whole numb**

0.5 * 50 = 25.

**Math**

50cm = 0.50m. Yes. 3m/0.50m = 6 Pieces.

**Trigonometry**

Circumference = pi*D = 3.14 * 10 = 31.4 ft. Va = 1rev/31.4ft. * 6.28rad/rev * 45ft./s = 9 rad/s. Va = 9rad/s * 1rev/6.28rad =

**Trigonometry**

Circumference = pi*D = 3.14D ft. Vp = Vb, Vp is velocity of the pulley, and Vb is velocity of the belt. 3.14D ft/rev * 360rev/60s = 40. D = 2.12 Ft. = Diameter of the pulley.

**Physics**

h = 0.5g*t^2. 2.80 = 16t^2 t = 0.424s = Fall time. a. d = Xo*t. 12.75 = Xo*0.424. Xo = 30.1 ft/s = Initial hor. velocity of the ball. Xo = 30.1ft/s * 1mi/5280ft * 3600s/h = 20.52 mi/h. b. Y^2 = Yo^2 + 2g*h. Y^2 = 0 + 64*2.80 = 179.2 Y = 13.40 ft./s. = Ver. component of final ...

**Pre Algebra**

1. -36x^2y^3z. 2. -4yz. 3. 4x^2-10x. 4. -4x^2+10x.

**physics**

All angles are measured CCW from the +x-axis. Fr = 30N[145o] + 40[205o] + 50[220o]. Fr = (-24.57+17.21i) + (-36.25-16.90i) + (-38.30-32.14i) -99.12 - -31.83i = 104.11N[17.8o] S. of W. = 104.11N[197.8o]CCW. = resultant force. To keep the body in equilibrium, F4 must be equal in...

**physics**

What is the direction of the 3rd force?

**Physics**

400-Fk = M*a. 400-Fk = M*0 = 0 Fk = 400 N.

**PHYSICS**

(44.9cm/210cm) * 135N. =

**Science**

Vo = 800m/s[-30o]. Xo = 800*Cos330 = 693 m/s. Yo = 800*sin(-30) = -400 m/s. Y^2 = Yo^2 + 2g*h. Y^2 = (-400)^2 + 19.6*150 = 162,940 Y = 404 m/s. = Final velocity of ver. component. Y = Yo + g*Tf. 404 = -400 + 9.8Tf Tf(Fall time) = ?