Posts by Henry
Total # Posts: 14,538

math
Correct. 
Math
P = Po(1+r)^n. r = 0.085/365 = 0.000233 = daily % rate. n = 13 Compounding periods. P = 5000(1+0.000233)^13 = $5015.17 Int. = P  Po = 5015.17  5000 = $15.17. 
Algebra
1.X Lbs. of almonds. Y Lbs. of cashews. Eq1: x + y = 7 Eq2: 5x + 12y = 56. 2. Multiply Eq1 by 5 and add the Eqs.: 5x  5y = 35 +5x + 12y = 56 Sum: 7y = 21 Y = 3 Lbs. In Eq1, replace Y with 3: x + 3 = 7 X = 4 Lbs. 
Pre algebra
8^7 * 8^2 = 8^9 = 134,217,728. 
math
5.99*10^12mi/Lightyr. * 4.2Lightyrs. = 2.516*10^13 Miles. If you had divided, your units would not have been miles. I hope this helps. 
math
1. 5.2*10^5mi/2.5*10^4mi/rev = 2.08*10^1 = 20.8 Rev. or times around. Your answer is 20.8 revolutions; however, if you had multiplied, your answer would have been (mi)^2/rev. which does not make sense for your problem. 
SAT math
(0,0), (6,m), (m,54). slope = m/6 = 54/m. m/6 = 54/m, m^2 = 324, m = 18. 
Physics
V = 60mi/h * 1600m/mi * 1h/3600s = 26.7 m/s. Work = 0.5M*V^2 Joules. 
Physics
V = Vo + a*t =38. 19 + a*0.01 = 38. a = ? It will be negative. F = M*a. 
Physics
Given: M1 = m, V1 = 485 m/s. M2 = 13m, V2 = 0. V3 = Velocity of proton(M1) after collision. Momentum before = Momentum after. M1*V1 + M2*V2 = M1*V3 + M2*V4. m*485 + 13m*0 = m*V3 + 13m*V4, 485m + 0 = m*V3 + 13m*V4, Divide both sides by m: 485 = V3 + 13V4, V3 = (V1(M1M2) + 2M2*... 
Math
75*2 + 75t = 125t, t = 3h. d = 125 * 3 = 375 Miles. 
math
4, 1, 1, 2, 2. They added 3, 2, 1, Then I added 0. 
physics
D = 4m[0o] + 4m[60o]. X = 4*Cos0 + 4*Cos60 = 6 m. Y = 4*sin 0 + 4*sin = 60 = 3.46 m. D = sqrt(X^2 + Y^2) = 6.93 m. Displacement. 
math
Vector Q makes an angle of 60o with the Xaxis. Vector R makes an angle of 60o with the +Xaxis. Each vector forms a 6030 right triangle. Using vector R, Cos60 = X/r = X/10, X = 10*Cos60 = 5 km. sin60 = Y/r = Y/10, Y = 8.66 km. = Ver. component of R and Q. Using Vector Q, ... 
Precalculus 11
The Discriminant is greater than zero(100); therefore, we have 2 real roots. 
math
8x = 4010 = 30, X = 30/8 = 15/4 = 3 3/4. 
Math
X buttons in bag A, x+18 buttons in bag B, 3(x+18) buttons in bag C. x + (x+18) + 3(x+18) = 4342, 
Math
[(4^2)^2]^2 = [4^4]^2 = 4^8. 
Trig
The angles are referenced to the Yaxis. so we'll assume CW rotation from +Yaxis. F1 = 100Lbs[79o] E. of S. = 18079 = 101o CW, F2 = 60Lbs[68o] E. of N. = 68o CW. Fr = 100[101o] + 60[68o] = Resultant force, X = 100*sin101 + 60*sin68 = 153.8 Lbs. Y = 100*Cos101 + 60*Cos68... 
Physics
V = Vo + a*t = 17 m/s, 18 + a*4*10^4 = 17, a = ?. (It will be negative.) F = M*a. 
Math
4x/15 = 500, X = $1875/mo. 1875/mo. * 12mo./yr. = $22,500/yr. 
Trig
Correction: Replace 39.9 with 32.9: d^2 = (32.9)^2 + (42.33)^2 = 2874.24, d = 53.61 miles which agrees with Daniel and Reiny's answer. 
Trig
Ship #1: 12mi/h[11o] W. of S. = 12mi/h[191o] CW, Ship #2: 9mi/h[75o] E. of N. = 9mi/h[75o] CW. d = 36mi[191o]  27mi[75o], X = 36*sin191  27*sin75 = 32.9 mi, Y = 36*Cos191  27*Cos75 = 42.33 mi, d^2 =(39.9)^2 + (  42.33)^2 = 3383.84, d = 58.2 miles apart. 
physics
d = 8 + 6 = 14 km = Travel distance. D^2 = 8^2 + 6^2 = 100, D = 10 km = Displacement. 
physics
d = 8 + 6 = 14 km = Travel distance. D^2 = 8^2 + 6^2 = 100, D = 10 km @ 37o. = Displacement = Straight line distance from starting point. 
math
(4/9)^2 * (3/8)^2 = 16/81 * 9/64 = (9*16)/(81*64) = 9/81 * 16/64 = 1/9 * 1/4 = 1/36. 
Maths
210m/lap * 5laps = 1050 m. = 1.05 km. 
math
a. Speed = 27mi/h * 5280Ft/mi * 1h/3600s = 39.6 Ft/s. b. d = 39.6Ft/s * 2s = 
Physics
M*g = 15 * 9.8 = 147 N. = Wt. of box, Fp = 147*sin A = Force parallel to the hill, Fn = 147*Cos A = Normal force, Fs = u * Fn = 0.45 *147*CosA = 66.2*CosA = Force of static friction, FpFs = M*a, 147*sin A  66.2*CosA = 15*0, 66.2*CosA = 147*sinA, 147*sinA/CosA = 66.2, sinA/... 
science
Fp = 12*sin20 = 4.1 N. = Force parallel with incline, Fn = 12*Cos20  7.35*sin10 = 10 N. = Normal force, Fk = u * Fn = 0.2 * 10 = 2 N., F = 7.35*Cos10  Fp  Fk = 7.24  4.1  2 = 1.14 N. = Net force, Work = F * d = 1.14 * 2 = 2.28 J. = Increase in KE. 
Science
V^2 = Vo^2 + 2a*d = 0, 60^2 + 2a*0.5 = 0, a = 3600 m/s^2. V = Vo + a*t = 0,?. 60 + (3600)t = 0, t = ?. 
Math
y + 3 <= 5, y <= 5  3, y <= 2. 
Math
D = 115km[48o] + 75km[120o], X = 115*sin48 + 75*sin120 = 150.4 km, Y = 115*Cos48 + 75*Cos120 = 39.45 km, D = 150.4 + 39.45i = 155.5km[75.3o] = Distance from X to Z. Tan A = X/Y For bearing notation. A = 75.3o. 
Chemistry
Help me with this; For the second part of the analysis,you will be provided with hydrated crystal of oxalic acid (H2C204. 2H2O). weigh out accurately about 1.575g of oxalic acid in a weighing bottle. Dissolve the acid in a beaker, then transfer the solution completely to ... 
Maths
V = Vo + a*t = 0, 30 + (1.5)t = 0, t = 20 s. 
Math
A triangle is formed: base = 2000 m., A = 180  (37+49) = 94o, B = 37o, C = 49o, Use Law of Sine to solve triangle: sin94/2000 = sin37/b, b = 1207 m. = 1.207 km, sin94/2000 = sin49/c, c = 1513 m., d = V*t, t = d/V = 1.207/170 = 0.0071h = 25.6 s. 
Physics
WL = wavelength, WL = V * T = V * (1/F) = 3*10^8 * (1/F) = 2.5*10^9 m, 3*10^8/F = 2.5*10^9, F = 1.2*10^17 Hz. = 1.2e17 Hz. 
geometry
angle A = X degree, angle B = 2x24 degrees, A + B = 90o, x + (2x24) = 90, X = 38o, 2x24 = 2*38  24 = 52o. 
physics
A large bar magnet (mass of 0.4 kg) exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away. Calculate the force exerted by the small bar magnet on the large one. 
physics
One coulomb of charge passes through a point in an electric circuit every ten seconds. What is the current of the circuit? 
physics
How close must two 1.0 C charged objects be for their mutual force to exceed 1.0 N? Compare that distance to something in your everyday life. 
physics
Two insulating spheres with charges of 7.0 ?C and 12 ?C, are located 10.0 cm apart. What is the force between them? In what direction does it act? 
physics
Two positivelycharged objects are located 0.1 m apart. How does the value of their mutual electric force change if the distance between them is doubled? (A) quadruples (B) doubles (C) same (D) halved (E) onefourth How does the value of their mutual electric force change if ... 
math
Thanks to Millie for help with the question and Kiera for posting this up or I will have failed. Thank you very much guys. 
math
At our school we can help each other. It is due Monday the 18th for me I need help with 3D for the math challenge. Please 
math
(12/300) * 100% = 4% tagged, 0.04s = 150, S = 3,750 Squirrels, total. 
Math
4 years ago: Joy was X years old, Paul was x + 20 years old, (x+20)/x = 7/3, 3x + 60 = 7x, X = 15. x + 20 = 15 + 20 = 35 years, Today: Paul's age = 35 + 4 = 39. 
Math
Mean = (60+42+48+46)/4 = 49, (60+42+48+46+x)/5 = 49, (196+x)/5 = 49, 196+x = 245, X = 49. 9 ( 
Physics
a. V^2 = Vo^2 + 2a*d = 0, 40^2 + (20)d = 0, d = 80 m. b. V = Vo + a*t = 0, 40 + (10t = 0, t = 4 s. 
Physics
2. d = 0.5a*t^2, t = 5min. = 300 s. 
PreCalculus Help? Vectors?
B. The direction will change 180o, and the magnitude will decrease. I'm assuming you mean pi/4. 
Algebra, substitution method
Eq1: x + 5y = 10 Eq2: 2x  6y = 8 Multiply both sides ofEq1 by 2 and add the Eqs: 2x + 10y = 20 2x  6y = 8 Sum: 4y = 12, Y = 3. In Eq1, replace Y with 3 and solve for X: x + 5*3 = 10, X = 5. 
Math
(9m + 6) + (5m6) = 9m+6 + (5m) 6 = 4m + 0 = 4m. 
physics asap
1. V^2 = Vo^2 + 2g*h = 0, 4.7^2 + (19.6)h = 0, h = 1.127 m. above the platform. 3.8 + 1.127 = 4.93 m. above gnd., V^2 = Vo^2 + 2g*h = 0 + 19.6*4.93 = 96.57, V = 9.83 m/s. 2. V^2 = Vo^2 + 2g*h = 0 + 19.6*11.6 = , V = ?. 
Math
The vertical distance across the semicircle = Dia./2 = 20/2 = 10 m., The width of the rectangle = 20 m., The length of the rectangle = 4010 = 30 m., A = pi*r^2/2 + L*W = (3.14*10^2/2) + 30*20 = 757 m^2. P = Pi*Dia./2 + 2L + W = (3.14*20/2) + 2*30 + 20 = 111.4 m. 
Physics
(800/900) * 60N = 53.33 N. = Wt. lost, Wt. in wax = Wt. in air  Wt. lost = 60  53.33 = 
Physics
Tf = 0.5 * 4 = 2 s. = Fall time, h = 0.5g*Tf^2. 
Quadratic Functions and Equations
A = 2 * 25 * 100 = 5000 Sq. Yds. = Area of the lawn, A = L * W = 5,000, 100W = 5,000, W = 50 Yds. 
mathematics
Error = 10.60  10.06 = 0.54. 
math
72p  (1/8)72p = 72p  9p = 63p. 
math
A. V = Vo + g*t = 0, 40 + (32)t = 0, t = 1.25 s. B . h = 16*1.25^2 + 40*1.25 + 6 = 31 Ft. 
maths
h1 = 2760*Tan26 = 1346 Ft. = Ht. of hill above gnd., h2 = Ht. of tower above top of hill, h1+h2 = 2760*Tan32, h2 = 2760*Tan32  h1 = 1725  1346 = 379 Ft. 
maths
h = d*Tan68 = (d+70)*Tan43, d*Tan68 = (d+70)*Tan43, d = (d+70)*0.38, d = 0.38d + 26.6, d = 42.9 Ft., A = 68o. h = d*Tan68. 
physics
M*g = 400 * 9.8 = 3920 N. = Wt. of slab, Fp = 3920*sin35 = 2248.4 N. = Force parallel to incline, Fn = 3920*Cos35 = 3211 N. = Normal force, Fk = u*Fn = 0.6 * 3211 = 1927 N. = Force of kinetic friction, FpFk = M*a, 2248.4  1927 = 400*a. 
algebra
2*sqrt(5) + 3*sqrt(49) = 2*sqrt5 + 3*7 = (2*sqrt5) + 21. 
math
2. P = Po + Po*r*t = $230,000, Po + Po*0.075*2 = 230,000, 1.15Po = 230,000, Po = 
math
36/24 * 2/3 = 3/2 * 2/3 = 6/6 = 1 Cup of butter. 
Math
Triangle #1: a = 3, b = 4, c = 5. Similar Triangle: d = 6, e = 8, f = 10. Both triangles have the same shape as required but different size. The ratios of the corresponding sides are equal: a/d = 3/6 = 1/2, b/e = 4/8 = 1/2, c/f = 5/10 = 1/2. 
Math
P = Po(1+r)^n, P = $20M, Po = Initial investment, r = 0.06/4 = 0.015 = Quarterly % rate expressed as a decimal, n = 4 comp./yr. * 4yrs. = 16 Compounding periods. 
Chemistry
a hydrocarbon is burnt completely in excess oxygen. it is found that 1.00g of the hydrocarbon gives 2.93g carbon dioxide and 1.80g water. find the empirical formula of the hydrocarbon (H=1,C=12,O=16) 
physics
A. k = F/d = 30N./9cm = 3.33 N/cm. B. F = 3.33N/cm * 18cm = 60 N, Work = F * d = 60 * 18 Joules. 
Math
28. P = Po(1+r)^n, Po = $1500, r = 0.085/12 = 0.0071 = Monthly % rate. n = 1comp./mo. * 36mo. = 36 Compounding periods. 
Math
23. 52,400 + 52,400*0.2*5 = 24. 36,725 + 36,725*0.11*6 = 25. 82,302  82302*05*4 =. I believe it should be 5% instead of 58%. Check textbook. 26. Same procedure #25, but change 1yr. to 12 mo. 27. P = Po(1+r)^n, Po = $5,000, r = 0.04/4 = 0.01 = quarterly % rate. n = 4 Comp./yr... 
Math
Ao = Ar + Ar*r*t, Ao = 12,345 + 12,345*(0.06/360)*120 = $12,591.90 = Amt. owed or taken out. 
physics
In the circuit at right, two resistors are connected in parallel. What is the voltage across the 4 ? resistor? What is the voltage across the 12 ? resistor? 
physics
A circuit is powered by a 5 V battery and has 0.2 A of current through it. If the circuit contains two resistors connected in series and one of the resistors has a resistance of 5 ?, what is the resistance of the other resistor? 
algebra 2
a. Tan (theta) = 0, Theta = 0. b. Theta = 90o. 
physics
I = E/(R1+R2) = 10/(10+20) = 
physics
R = 200 + 200 = 
math
P = Po + Po*r*t = 28,500 + 28,500*(0.08/360)*118 = 
physics
M*g = 9.8M = Wt. of vehicle = Normal(Fn). Fp = Mg*sin A = 9.8M*sin 0 = 0. = Force parallel with surface. Fk = u*Fn = 0.7 * 9.8M = 6.86M N. = Force of kinetic friction. Fp  Fk = M*a, 0  6.86M = M*a, a = 6.86 m/s^2. V^2 = Vo^2 + 2a*d = 0, Vo^2  13.72*24 = 0, Vo = 18.1 m/s. 
physics
M*g = 100 * 9.8 = 980 N. = Wt. of crate = Normal (Fn), Fk = u*Fn = u * 100 = 100u = Force of kinetic friction, F  Fk = M*a, 300  100u = 100*0 = 0,, u = 3. 
Math
You are welcome. 
Math
4. (sqrt3+sqrt2)^2  3 + 2*sqrt(3*2) + 2 = 5 + 2*sqrt(6). 
Math
1. sqrt(3c^2)/sqrt(27) = c*sqrt(3)/sqrt(9*3) = c* sqrt(3)/3*sqrt(3) = c/3. 2. sqrt(27)*sqrt(3) = sqrt(9*3)*sqrt(3) = 3*sqrt(3) * sqrt(3) = 3 * 3 = 9. 3. sqrt(75)  4*sqrt(75) = 3*sqrt(75) = 3*sqrt(25*3) = 3*5*sqrt(3) = 15 * sqrt(3). The student should do #4. 
Math & science?
F = 1/P = 1/6.8 = 0.147 cycles/s = 0.147 Hz. 
Algebra 1
A = L * W, A = L*(x + 4) = 2x^3  29x + 12, L = (2x^3  29x + 12)/(x+4), Use longhand division, L = 2x^2  8x + 3. 
Math
(1200/2400) * 1h = 0.5h = 30 min. to print 1200 blackand white posters, 50  30 = 20 min. to print 500 colored posters, (60min/20min) * 500 = 1500 colored posters in 1 hour. 
math
A1 = 2(L*h) + 2(W*h) + 2(L*W) = Surface area when ht. = 1in , A2 = 2(L*h) + 2(W*h) + 2(L*W) = Surface area when ht. = 2 in, A2  A1 = The increase in surface area. 
math
Fraction = n. n*0.9/0.5 = 1.8n. 1.8n/n = 1.8 = 180%, Change = 180%  100% = 80%. 
math
By what percent will a fraction change if its numerator is decreased by 10% and its denominator is decreased by 50%? 
Algebra
P = Po(1+r)^n, Po = $2600, r = 0.04/yr. n = 1comp./yr. * 7yrs. = 7 Compounding periods. P = 2600(1.04^7) = 
science
d = V * t = 102 = 8, V * 4 = 8, V = 2 m/s. 
Math
P = Po + Po*r*t = 1000 + 1000*0.16*1 = $1,160, 1160  (350 + 200 + 400) = $210 Due on 1 Jan. 2003. 
Math
P = Po + Po*r*t = 1,000 + 1000*0.145*1 = $1,145, 1145  (200 + 400) = $545 = Bal. due in 1 yr. 
Physics
Incomplete. 
finance
Use same Eq I used in your 12:38 AM post. 
finance
750/mo. * 360mo. = $270,000 = Total cost, P = (Po*r*t)/(1(1+r)t) = 270,000, r = 0.04/12 = 0.000328/mo. a. (Po*0.000328*360)/(11.000328^360) = 270,000, (Po*0.1180)/(0.1114) = 270,000, 1.059Po = 270,000, Po = $254,898.31 = Max. amount that can be borrowed. b. 254,898.31 + 20... 
Math
You are right! 
algebra 2
1. x^2  (y12)^2 = 144, and Y = x^2. x^2  (y^2  24y + 144) = 144, Replace x^2 with y: y  y^2 + 24y 144 = 144, y^2 + 23y  144 = 144, y^2 + 23y  288 = 0, Use Quadratic Formula: Y = (23 + sqrt(529  1152))/(2) , Y = (23 + 24.96i)/(2) = 11.5  12.5i, and 11.5 + ...