Posts by Henry

Total # Posts: 14,538

  1. math

    Correct.
  2. Math

    P = Po(1+r)^n. r = 0.085/365 = 0.000233 = daily % rate. n = 13 Compounding periods. P = 5000(1+0.000233)^13 = $5015.17 Int. = P - Po = 5015.17 - 5000 = $15.17.
  3. Algebra

    1.X Lbs. of almonds. Y Lbs. of cashews. Eq1: x + y = 7 Eq2: 5x + 12y = 56. 2. Multiply Eq1 by -5 and add the Eqs.: -5x - 5y = -35 +5x + 12y = 56 Sum: 7y = 21 Y = 3 Lbs. In Eq1, replace Y with 3: x + 3 = 7 X = 4 Lbs.
  4. Pre algebra

    8^7 * 8^2 = 8^9 = 134,217,728.
  5. math

    5.99*10^12mi/Light-yr. * 4.2Light-yrs. = 2.516*10^13 Miles. If you had divided, your units would not have been miles. I hope this helps.
  6. math

    1. 5.2*10^5mi/2.5*10^4mi/rev = 2.08*10^1 = 20.8 Rev. or times around. Your answer is 20.8 revolutions; however, if you had multiplied, your answer would have been (mi)^2/rev. which does not make sense for your problem.
  7. SAT math

    (0,0), (6,m), (m,54). slope = m/6 = 54/m. m/6 = 54/m, m^2 = 324, m = 18.
  8. Physics

    V = 60mi/h * 1600m/mi * 1h/3600s = 26.7 m/s. Work = 0.5M*V^2 Joules.
  9. Physics

    V = Vo + a*t =-38. 19 + a*0.01 = -38. a = ? It will be negative. F = M*a.
  10. Physics

    Given: M1 = m, V1 = 485 m/s. M2 = 13m, V2 = 0. V3 = Velocity of proton(M1) after collision. Momentum before = Momentum after. M1*V1 + M2*V2 = M1*V3 + M2*V4. m*485 + 13m*0 = m*V3 + 13m*V4, 485m + 0 = m*V3 + 13m*V4, Divide both sides by m: 485 = V3 + 13V4, V3 = (V1(M1-M2) + 2M2*...
  11. Math

    75*2 + 75t = 125t, t = 3h. d = 125 * 3 = 375 Miles.
  12. math

    -4, -1, 1, 2, 2. They added 3, 2, 1, Then I added 0.
  13. physics

    D = 4m[0o] + 4m[60o]. X = 4*Cos0 + 4*Cos60 = 6 m. Y = 4*sin 0 + 4*sin = 60 = 3.46 m. D = sqrt(X^2 + Y^2) = 6.93 m. Displacement.
  14. math

    Vector Q makes an angle of 60o with the -X-axis. Vector R makes an angle of 60o with the +X-axis. Each vector forms a 60-30 right triangle. Using vector R, Cos60 = X/r = X/10, X = 10*Cos60 = 5 km. sin60 = Y/r = Y/10, Y = 8.66 km. = Ver. component of R and Q. Using Vector Q, ...
  15. Precalculus 11

    The Discriminant is greater than zero(100); therefore, we have 2 real roots.
  16. math

    8x = 40-10 = 30, X = 30/8 = 15/4 = 3 3/4.
  17. Math

    X buttons in bag A, x+18 buttons in bag B, 3(x+18) buttons in bag C. x + (x+18) + 3(x+18) = 4342,
  18. Math

    [(4^2)^2]^2 = [4^4]^2 = 4^8.
  19. Trig

    The angles are referenced to the Y-axis. so we'll assume CW rotation from +Y-axis. F1 = 100Lbs[79o] E. of S. = 180-79 = 101o CW, F2 = 60Lbs[68o] E. of N. = 68o CW. Fr = 100[101o] + 60[68o] = Resultant force, X = 100*sin101 + 60*sin68 = 153.8 Lbs. Y = 100*Cos101 + 60*Cos68...
  20. Physics

    V = Vo + a*t = 17 m/s, 18 + a*4*10^-4 = 17, a = ?. (It will be negative.) F = M*a.
  21. Math

    4x/15 = 500, X = $1875/mo. 1875/mo. * 12mo./yr. = $22,500/yr.
  22. Trig

    Correction: Replace 39.9 with 32.9: d^2 = (-32.9)^2 + (-42.33)^2 = 2874.24, d = 53.61 miles which agrees with Daniel and Reiny's answer.
  23. Trig

    Ship #1: 12mi/h[11o] W. of S. = 12mi/h[191o] CW, Ship #2: 9mi/h[75o] E. of N. = 9mi/h[75o] CW. d = 36mi[191o] - 27mi[75o], X = 36*sin191 - 27*sin75 = -32.9 mi, Y = 36*Cos191 - 27*Cos75 = -42.33 mi, d^2 =(-39.9)^2 + ( - 42.33)^2 = 3383.84, d = 58.2 miles apart.
  24. physics

    d = 8 + 6 = 14 km = Travel distance. D^2 = 8^2 + 6^2 = 100, D = 10 km = Displacement.
  25. physics

    d = 8 + 6 = 14 km = Travel distance. D^2 = 8^2 + 6^2 = 100, D = 10 km @ 37o. = Displacement = Straight line distance from starting point.
  26. math

    (4/9)^2 * (3/8)^2 = 16/81 * 9/64 = (9*16)/(81*64) = 9/81 * 16/64 = 1/9 * 1/4 = 1/36.
  27. Maths

    210m/lap * 5laps = 1050 m. = 1.05 km.
  28. math

    a. Speed = 27mi/h * 5280Ft/mi * 1h/3600s = 39.6 Ft/s. b. d = 39.6Ft/s * 2s =
  29. Physics

    M*g = 15 * 9.8 = 147 N. = Wt. of box, Fp = 147*sin A = Force parallel to the hill, Fn = 147*Cos A = Normal force, Fs = u * Fn = 0.45 *147*CosA = 66.2*CosA = Force of static friction, Fp-Fs = M*a, 147*sin A - 66.2*CosA = 15*0, 66.2*CosA = 147*sinA, 147*sinA/CosA = 66.2, sinA/...
  30. science

    Fp = 12*sin20 = 4.1 N. = Force parallel with incline, Fn = 12*Cos20 - 7.35*sin10 = 10 N. = Normal force, Fk = u * Fn = 0.2 * 10 = 2 N., F = 7.35*Cos10 - Fp - Fk = 7.24 - 4.1 - 2 = 1.14 N. = Net force, Work = F * d = 1.14 * 2 = 2.28 J. = Increase in KE.
  31. Science

    V^2 = Vo^2 + 2a*d = 0, 60^2 + 2a*0.5 = 0, a = -3600 m/s^2. V = Vo + a*t = 0,?. 60 + (-3600)t = 0, t = ?.
  32. Math

    y + 3 <= 5, y <= 5 - 3, y <= 2.
  33. Math

    D = 115km[48o] + 75km[120o], X = 115*sin48 + 75*sin120 = 150.4 km, Y = 115*Cos48 + 75*Cos120 = 39.45 km, D = 150.4 + 39.45i = 155.5km[75.3o] = Distance from X to Z. Tan A = X/Y For bearing notation. A = 75.3o.
  34. Chemistry

    Help me with this; For the second part of the analysis,you will be provided with hydrated crystal of oxalic acid (H2C204. 2H2O). weigh out accurately about 1.575g of oxalic acid in a weighing bottle. Dissolve the acid in a beaker, then transfer the solution completely to ...
  35. Maths

    V = Vo + a*t = 0, 30 + (-1.5)t = 0, t = 20 s.
  36. Math

    A triangle is formed: base = 2000 m., A = 180 - (37+49) = 94o, B = 37o, C = 49o, Use Law of Sine to solve triangle: sin94/2000 = sin37/b, b = 1207 m. = 1.207 km, sin94/2000 = sin49/c, c = 1513 m., d = V*t, t = d/V = 1.207/170 = 0.0071h = 25.6 s.
  37. Physics

    WL = wavelength, WL = V * T = V * (1/F) = 3*10^8 * (1/F) = 2.5*10^-9 m, 3*10^8/F = 2.5*10^-9, F = 1.2*10^17 Hz. = 1.2e17 Hz.
  38. geometry

    angle A = X degree, angle B = 2x-24 degrees, A + B = 90o, x + (2x-24) = 90, X = 38o, 2x-24 = 2*38 - 24 = 52o.
  39. physics

    A large bar magnet (mass of 0.4 kg) exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away. Calculate the force exerted by the small bar magnet on the large one.
  40. physics

    One coulomb of charge passes through a point in an electric circuit every ten seconds. What is the current of the circuit?
  41. physics

    How close must two 1.0 C charged objects be for their mutual force to exceed 1.0 N? Compare that distance to something in your everyday life.
  42. physics

    Two insulating spheres with charges of -7.0 ?C and -12 ?C, are located 10.0 cm apart. What is the force between them? In what direction does it act?
  43. physics

    Two positively-charged objects are located 0.1 m apart. How does the value of their mutual electric force change if the distance between them is doubled? (A) quadruples (B) doubles (C) same (D) halved (E) one-fourth How does the value of their mutual electric force change if ...
  44. math

    Thanks to Millie for help with the question and Kiera for posting this up or I will have failed. Thank you very much guys.
  45. math

    At our school we can help each other. It is due Monday the 18th for me I need help with 3D for the math challenge. Please
  46. math

    (12/300) * 100% = 4% tagged, 0.04s = 150, S = 3,750 Squirrels, total.
  47. Math

    4 years ago: Joy was X years old, Paul was x + 20 years old, (x+20)/x = 7/3, 3x + 60 = 7x, X = 15. x + 20 = 15 + 20 = 35 years, Today: Paul's age = 35 + 4 = 39.
  48. Math

    Mean = (60+42+48+46)/4 = 49, (60+42+48+46+x)/5 = 49, (196+x)/5 = 49, 196+x = 245, X = 49. 9 (
  49. Physics

    a. V^2 = Vo^2 + 2a*d = 0, 40^2 + (-20)d = 0, d = 80 m. b. V = Vo + a*t = 0, 40 + (-10t = 0, t = 4 s.
  50. Physics

    2. d = 0.5a*t^2, t = 5min. = 300 s.
  51. Pre-Calculus Help? Vectors?

    B. The direction will change 180o, and the magnitude will decrease. I'm assuming you mean -pi/4.
  52. Algebra, substitution method

    Eq1: x + 5y = 10 Eq2: -2x - 6y = -8 Multiply both sides ofEq1 by 2 and add the Eqs: 2x + 10y = 20 -2x - 6y = -8 Sum: 4y = 12, Y = 3. In Eq1, replace Y with 3 and solve for X: x + 5*3 = 10, X = -5.
  53. Math

    (9m + 6) + (-5m-6) = 9m+6 + (-5m) -6 = 4m + 0 = 4m.
  54. physics asap

    1. V^2 = Vo^2 + 2g*h = 0, 4.7^2 + (-19.6)h = 0, h = 1.127 m. above the platform. 3.8 + 1.127 = 4.93 m. above gnd., V^2 = Vo^2 + 2g*h = 0 + 19.6*4.93 = 96.57, V = 9.83 m/s. 2. V^2 = Vo^2 + 2g*h = 0 + 19.6*11.6 = , V = ?.
  55. Math

    The vertical distance across the semi-circle = Dia./2 = 20/2 = 10 m., The width of the rectangle = 20 m., The length of the rectangle = 40-10 = 30 m., A = pi*r^2/2 + L*W = (3.14*10^2/2) + 30*20 = 757 m^2. P = Pi*Dia./2 + 2L + W = (3.14*20/2) + 2*30 + 20 = 111.4 m.
  56. Physics

    (800/900) * 60N = 53.33 N. = Wt. lost, Wt. in wax = Wt. in air - Wt. lost = 60 - 53.33 =
  57. Physics

    Tf = 0.5 * 4 = 2 s. = Fall time, h = 0.5g*Tf^2.
  58. Quadratic Functions and Equations

    A = 2 * 25 * 100 = 5000 Sq. Yds. = Area of the lawn, A = L * W = 5,000, 100W = 5,000, W = 50 Yds.
  59. mathematics

    Error = 10.60 - 10.06 = 0.54.
  60. math

    72p - (1/8)72p = 72p - 9p = 63p.
  61. math

    A. V = Vo + g*t = 0, 40 + (-32)t = 0, t = 1.25 s. B . h = -16*1.25^2 + 40*1.25 + 6 = 31 Ft.
  62. maths

    h1 = 2760*Tan26 = 1346 Ft. = Ht. of hill above gnd., h2 = Ht. of tower above top of hill, h1+h2 = 2760*Tan32, h2 = 2760*Tan32 - h1 = 1725 - 1346 = 379 Ft.
  63. maths

    h = d*Tan68 = (d+70)*Tan43, d*Tan68 = (d+70)*Tan43, d = (d+70)*0.38, d = 0.38d + 26.6, d = 42.9 Ft., A = 68o. h = d*Tan68.
  64. physics

    M*g = 400 * 9.8 = 3920 N. = Wt. of slab, Fp = 3920*sin35 = 2248.4 N. = Force parallel to incline, Fn = 3920*Cos35 = 3211 N. = Normal force, Fk = u*Fn = 0.6 * 3211 = 1927 N. = Force of kinetic friction, Fp-Fk = M*a, 2248.4 - 1927 = 400*a.
  65. algebra

    2*sqrt(5) + 3*sqrt(49) = 2*sqrt5 + 3*7 = (2*sqrt5) + 21.
  66. math

    2. P = Po + Po*r*t = $230,000, Po + Po*0.075*2 = 230,000, 1.15Po = 230,000, Po =
  67. math

    36/24 * 2/3 = 3/2 * 2/3 = 6/6 = 1 Cup of butter.
  68. Math

    Triangle #1: a = 3, b = 4, c = 5. Similar Triangle: d = 6, e = 8, f = 10. Both triangles have the same shape as required but different size. The ratios of the corresponding sides are equal: a/d = 3/6 = 1/2, b/e = 4/8 = 1/2, c/f = 5/10 = 1/2.
  69. Math

    P = Po(1+r)^n, P = $20M, Po = Initial investment, r = 0.06/4 = 0.015 = Quarterly % rate expressed as a decimal, n = 4 comp./yr. * 4yrs. = 16 Compounding periods.
  70. Chemistry

    a hydrocarbon is burnt completely in excess oxygen. it is found that 1.00g of the hydrocarbon gives 2.93g carbon dioxide and 1.80g water. find the empirical formula of the hydrocarbon (H=1,C=12,O=16)
  71. physics

    A. k = F/d = 30N./9cm = 3.33 N/cm. B. F = 3.33N/cm * 18cm = 60 N, Work = F * d = 60 * 18 Joules.
  72. Math

    28. P = Po(1+r)^n, Po = $1500, r = 0.085/12 = 0.0071 = Monthly % rate. n = 1comp./mo. * 36mo. = 36 Compounding periods.
  73. Math

    23. 52,400 + 52,400*0.2*5 = 24. 36,725 + 36,725*0.11*6 = 25. 82,302 - 82302*05*4 =. I believe it should be 5% instead of 58%. Check textbook. 26. Same procedure #25, but change 1yr. to 12 mo. 27. P = Po(1+r)^n, Po = $5,000, r = 0.04/4 = 0.01 = quarterly % rate. n = 4 Comp./yr...
  74. Math

    Ao = Ar + Ar*r*t, Ao = 12,345 + 12,345*(0.06/360)*120 = $12,591.90 = Amt. owed or taken out.
  75. physics

    In the circuit at right, two resistors are connected in parallel. What is the voltage across the 4 ? resistor? What is the voltage across the 12 ? resistor?
  76. physics

    A circuit is powered by a 5 V battery and has 0.2 A of current through it. If the circuit contains two resistors connected in series and one of the resistors has a resistance of 5 ?, what is the resistance of the other resistor?
  77. algebra 2

    a. Tan (theta) = 0, Theta = 0. b. Theta = 90o.
  78. physics

    I = E/(R1+R2) = 10/(10+20) =
  79. physics

    R = 200 + 200 =
  80. math

    P = Po + Po*r*t = 28,500 + 28,500*(0.08/360)*118 =
  81. physics

    M*g = 9.8M = Wt. of vehicle = Normal(Fn). Fp = Mg*sin A = 9.8M*sin 0 = 0. = Force parallel with surface. Fk = u*Fn = 0.7 * 9.8M = 6.86M N. = Force of kinetic friction. Fp - Fk = M*a, 0 - 6.86M = M*a, a = -6.86 m/s^2. V^2 = Vo^2 + 2a*d = 0, Vo^2 - 13.72*24 = 0, Vo = 18.1 m/s.
  82. physics

    M*g = 100 * 9.8 = 980 N. = Wt. of crate = Normal (Fn), Fk = u*Fn = u * 100 = 100u = Force of kinetic friction, F - Fk = M*a, 300 - 100u = 100*0 = 0,, u = 3.
  83. Math

    You are welcome.
  84. Math

    4. (sqrt3+sqrt2)^2 - 3 + 2*sqrt(3*2) + 2 = 5 + 2*sqrt(6).
  85. Math

    1. sqrt(3c^2)/sqrt(27) = c*sqrt(3)/sqrt(9*3) = c* sqrt(3)/3*sqrt(3) = c/3. 2. sqrt(27)*sqrt(3) = sqrt(9*3)*sqrt(3) = 3*sqrt(3) * sqrt(3) = 3 * 3 = 9. 3. sqrt(75) - 4*sqrt(75) = -3*sqrt(75) = -3*sqrt(25*3) = -3*5*sqrt(3) = -15 * sqrt(3). The student should do #4.
  86. Math & science?

    F = 1/P = 1/6.8 = 0.147 cycles/s = 0.147 Hz.
  87. Algebra 1

    A = L * W, A = L*(x + 4) = 2x^3 - 29x + 12, L = (2x^3 - 29x + 12)/(x+4), Use long-hand division, L = 2x^2 - 8x + 3.
  88. Math

    (1200/2400) * 1h = 0.5h = 30 min. to print 1200 black-and -white posters, 50 - 30 = 20 min. to print 500 colored posters, (60min/20min) * 500 = 1500 colored posters in 1 hour.
  89. math

    A1 = 2(L*h) + 2(W*h) + 2(L*W) = Surface area when ht. = 1in , A2 = 2(L*h) + 2(W*h) + 2(L*W) = Surface area when ht. = 2 in, A2 - A1 = The increase in surface area.
  90. math

    Fraction = n. n*0.9/0.5 = 1.8n. 1.8n/n = 1.8 = 180%, Change = 180% - 100% = 80%.
  91. math

    By what percent will a fraction change if its numerator is decreased by 10% and its denominator is decreased by 50%?
  92. Algebra

    P = Po(1+r)^n, Po = $2600, r = 0.04/yr. n = 1comp./yr. * 7yrs. = 7 Compounding periods. P = 2600(1.04^7) =
  93. science

    d = V * t = 10-2 = 8, V * 4 = 8, V = 2 m/s.
  94. Math

    P = Po + Po*r*t = 1000 + 1000*0.16*1 = $1,160, 1160 - (350 + 200 + 400) = $210 Due on 1 Jan. 2003.
  95. Math

    P = Po + Po*r*t = 1,000 + 1000*0.145*1 = $1,145, 1145 - (200 + 400) = $545 = Bal. due in 1 yr.
  96. Physics

    Incomplete.
  97. finance

    Use same Eq I used in your 12:38 AM post.
  98. finance

    750/mo. * 360mo. = $270,000 = Total cost, P = (Po*r*t)/(1-(1+r)-t) = 270,000, r = 0.04/12 = 0.000328/mo. a. (Po*0.000328*360)/(1-1.000328^-360) = 270,000, (Po*0.1180)/(0.1114) = 270,000, 1.059Po = 270,000, Po = $254,898.31 = Max. amount that can be borrowed. b. 254,898.31 + 20...
  99. Math

    You are right!
  100. algebra 2

    1. x^2 - (y-12)^2 = 144, and Y = -x^2. x^2 - (y^2 - 24y + 144) = 144, Replace x^2 with -y: -y - y^2 + 24y -144 = 144, -y^2 + 23y - 144 = 144, -y^2 + 23y - 288 = 0, Use Quadratic Formula: Y = (-23 +- sqrt(529 - 1152))/(-2) , Y = (-23 +- 24.96i)/(-2) = 11.5 - 12.5i, and 11.5 + ...
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