Posts by Henry

Total # Posts: 14,493

  1. math

    (12/300) * 100% = 4% tagged, 0.04s = 150, S = 3,750 Squirrels, total.
  2. Math

    4 years ago: Joy was X years old, Paul was x + 20 years old, (x+20)/x = 7/3, 3x + 60 = 7x, X = 15. x + 20 = 15 + 20 = 35 years, Today: Paul's age = 35 + 4 = 39.
  3. Math

    Mean = (60+42+48+46)/4 = 49, (60+42+48+46+x)/5 = 49, (196+x)/5 = 49, 196+x = 245, X = 49. 9 (
  4. Physics

    a. V^2 = Vo^2 + 2a*d = 0, 40^2 + (-20)d = 0, d = 80 m. b. V = Vo + a*t = 0, 40 + (-10t = 0, t = 4 s.
  5. Physics

    2. d = 0.5a*t^2, t = 5min. = 300 s.
  6. Pre-Calculus Help? Vectors?

    B. The direction will change 180o, and the magnitude will decrease. I'm assuming you mean -pi/4.
  7. Algebra, substitution method

    Eq1: x + 5y = 10 Eq2: -2x - 6y = -8 Multiply both sides ofEq1 by 2 and add the Eqs: 2x + 10y = 20 -2x - 6y = -8 Sum: 4y = 12, Y = 3. In Eq1, replace Y with 3 and solve for X: x + 5*3 = 10, X = -5.
  8. Math

    (9m + 6) + (-5m-6) = 9m+6 + (-5m) -6 = 4m + 0 = 4m.
  9. physics asap

    1. V^2 = Vo^2 + 2g*h = 0, 4.7^2 + (-19.6)h = 0, h = 1.127 m. above the platform. 3.8 + 1.127 = 4.93 m. above gnd., V^2 = Vo^2 + 2g*h = 0 + 19.6*4.93 = 96.57, V = 9.83 m/s. 2. V^2 = Vo^2 + 2g*h = 0 + 19.6*11.6 = , V = ?.
  10. Math

    The vertical distance across the semi-circle = Dia./2 = 20/2 = 10 m., The width of the rectangle = 20 m., The length of the rectangle = 40-10 = 30 m., A = pi*r^2/2 + L*W = (3.14*10^2/2) + 30*20 = 757 m^2. P = Pi*Dia./2 + 2L + W = (3.14*20/2) + 2*30 + 20 = 111.4 m.
  11. Physics

    (800/900) * 60N = 53.33 N. = Wt. lost, Wt. in wax = Wt. in air - Wt. lost = 60 - 53.33 =
  12. Physics

    Tf = 0.5 * 4 = 2 s. = Fall time, h = 0.5g*Tf^2.
  13. Quadratic Functions and Equations

    A = 2 * 25 * 100 = 5000 Sq. Yds. = Area of the lawn, A = L * W = 5,000, 100W = 5,000, W = 50 Yds.
  14. mathematics

    Error = 10.60 - 10.06 = 0.54.
  15. math

    72p - (1/8)72p = 72p - 9p = 63p.
  16. math

    A. V = Vo + g*t = 0, 40 + (-32)t = 0, t = 1.25 s. B . h = -16*1.25^2 + 40*1.25 + 6 = 31 Ft.
  17. maths

    h1 = 2760*Tan26 = 1346 Ft. = Ht. of hill above gnd., h2 = Ht. of tower above top of hill, h1+h2 = 2760*Tan32, h2 = 2760*Tan32 - h1 = 1725 - 1346 = 379 Ft.
  18. maths

    h = d*Tan68 = (d+70)*Tan43, d*Tan68 = (d+70)*Tan43, d = (d+70)*0.38, d = 0.38d + 26.6, d = 42.9 Ft., A = 68o. h = d*Tan68.
  19. physics

    M*g = 400 * 9.8 = 3920 N. = Wt. of slab, Fp = 3920*sin35 = 2248.4 N. = Force parallel to incline, Fn = 3920*Cos35 = 3211 N. = Normal force, Fk = u*Fn = 0.6 * 3211 = 1927 N. = Force of kinetic friction, Fp-Fk = M*a, 2248.4 - 1927 = 400*a.
  20. algebra

    2*sqrt(5) + 3*sqrt(49) = 2*sqrt5 + 3*7 = (2*sqrt5) + 21.
  21. math

    2. P = Po + Po*r*t = $230,000, Po + Po*0.075*2 = 230,000, 1.15Po = 230,000, Po =
  22. math

    36/24 * 2/3 = 3/2 * 2/3 = 6/6 = 1 Cup of butter.
  23. Math

    Triangle #1: a = 3, b = 4, c = 5. Similar Triangle: d = 6, e = 8, f = 10. Both triangles have the same shape as required but different size. The ratios of the corresponding sides are equal: a/d = 3/6 = 1/2, b/e = 4/8 = 1/2, c/f = 5/10 = 1/2.
  24. Math

    P = Po(1+r)^n, P = $20M, Po = Initial investment, r = 0.06/4 = 0.015 = Quarterly % rate expressed as a decimal, n = 4 comp./yr. * 4yrs. = 16 Compounding periods.
  25. Chemistry

    a hydrocarbon is burnt completely in excess oxygen. it is found that 1.00g of the hydrocarbon gives 2.93g carbon dioxide and 1.80g water. find the empirical formula of the hydrocarbon (H=1,C=12,O=16)
  26. physics

    A. k = F/d = 30N./9cm = 3.33 N/cm. B. F = 3.33N/cm * 18cm = 60 N, Work = F * d = 60 * 18 Joules.
  27. Math

    28. P = Po(1+r)^n, Po = $1500, r = 0.085/12 = 0.0071 = Monthly % rate. n = 1comp./mo. * 36mo. = 36 Compounding periods.
  28. Math

    23. 52,400 + 52,400*0.2*5 = 24. 36,725 + 36,725*0.11*6 = 25. 82,302 - 82302*05*4 =. I believe it should be 5% instead of 58%. Check textbook. 26. Same procedure #25, but change 1yr. to 12 mo. 27. P = Po(1+r)^n, Po = $5,000, r = 0.04/4 = 0.01 = quarterly % rate. n = 4 Comp./yr...
  29. Math

    Ao = Ar + Ar*r*t, Ao = 12,345 + 12,345*(0.06/360)*120 = $12,591.90 = Amt. owed or taken out.
  30. physics

    In the circuit at right, two resistors are connected in parallel. What is the voltage across the 4 ? resistor? What is the voltage across the 12 ? resistor?
  31. physics

    A circuit is powered by a 5 V battery and has 0.2 A of current through it. If the circuit contains two resistors connected in series and one of the resistors has a resistance of 5 ?, what is the resistance of the other resistor?
  32. algebra 2

    a. Tan (theta) = 0, Theta = 0. b. Theta = 90o.
  33. physics

    I = E/(R1+R2) = 10/(10+20) =
  34. physics

    R = 200 + 200 =
  35. math

    P = Po + Po*r*t = 28,500 + 28,500*(0.08/360)*118 =
  36. physics

    M*g = 9.8M = Wt. of vehicle = Normal(Fn). Fp = Mg*sin A = 9.8M*sin 0 = 0. = Force parallel with surface. Fk = u*Fn = 0.7 * 9.8M = 6.86M N. = Force of kinetic friction. Fp - Fk = M*a, 0 - 6.86M = M*a, a = -6.86 m/s^2. V^2 = Vo^2 + 2a*d = 0, Vo^2 - 13.72*24 = 0, Vo = 18.1 m/s.
  37. physics

    M*g = 100 * 9.8 = 980 N. = Wt. of crate = Normal (Fn), Fk = u*Fn = u * 100 = 100u = Force of kinetic friction, F - Fk = M*a, 300 - 100u = 100*0 = 0,, u = 3.
  38. Math

    You are welcome.
  39. Math

    4. (sqrt3+sqrt2)^2 - 3 + 2*sqrt(3*2) + 2 = 5 + 2*sqrt(6).
  40. Math

    1. sqrt(3c^2)/sqrt(27) = c*sqrt(3)/sqrt(9*3) = c* sqrt(3)/3*sqrt(3) = c/3. 2. sqrt(27)*sqrt(3) = sqrt(9*3)*sqrt(3) = 3*sqrt(3) * sqrt(3) = 3 * 3 = 9. 3. sqrt(75) - 4*sqrt(75) = -3*sqrt(75) = -3*sqrt(25*3) = -3*5*sqrt(3) = -15 * sqrt(3). The student should do #4.
  41. Math & science?

    F = 1/P = 1/6.8 = 0.147 cycles/s = 0.147 Hz.
  42. Algebra 1

    A = L * W, A = L*(x + 4) = 2x^3 - 29x + 12, L = (2x^3 - 29x + 12)/(x+4), Use long-hand division, L = 2x^2 - 8x + 3.
  43. Math

    (1200/2400) * 1h = 0.5h = 30 min. to print 1200 black-and -white posters, 50 - 30 = 20 min. to print 500 colored posters, (60min/20min) * 500 = 1500 colored posters in 1 hour.
  44. math

    A1 = 2(L*h) + 2(W*h) + 2(L*W) = Surface area when ht. = 1in , A2 = 2(L*h) + 2(W*h) + 2(L*W) = Surface area when ht. = 2 in, A2 - A1 = The increase in surface area.
  45. math

    Fraction = n. n*0.9/0.5 = 1.8n. 1.8n/n = 1.8 = 180%, Change = 180% - 100% = 80%.
  46. math

    By what percent will a fraction change if its numerator is decreased by 10% and its denominator is decreased by 50%?
  47. Algebra

    P = Po(1+r)^n, Po = $2600, r = 0.04/yr. n = 1comp./yr. * 7yrs. = 7 Compounding periods. P = 2600(1.04^7) =
  48. science

    d = V * t = 10-2 = 8, V * 4 = 8, V = 2 m/s.
  49. Math

    P = Po + Po*r*t = 1000 + 1000*0.16*1 = $1,160, 1160 - (350 + 200 + 400) = $210 Due on 1 Jan. 2003.
  50. Math

    P = Po + Po*r*t = 1,000 + 1000*0.145*1 = $1,145, 1145 - (200 + 400) = $545 = Bal. due in 1 yr.
  51. Physics

    Incomplete.
  52. finance

    Use same Eq I used in your 12:38 AM post.
  53. finance

    750/mo. * 360mo. = $270,000 = Total cost, P = (Po*r*t)/(1-(1+r)-t) = 270,000, r = 0.04/12 = 0.000328/mo. a. (Po*0.000328*360)/(1-1.000328^-360) = 270,000, (Po*0.1180)/(0.1114) = 270,000, 1.059Po = 270,000, Po = $254,898.31 = Max. amount that can be borrowed. b. 254,898.31 + 20...
  54. Math

    You are right!
  55. algebra 2

    1. x^2 - (y-12)^2 = 144, and Y = -x^2. x^2 - (y^2 - 24y + 144) = 144, Replace x^2 with -y: -y - y^2 + 24y -144 = 144, -y^2 + 23y - 144 = 144, -y^2 + 23y - 288 = 0, Use Quadratic Formula: Y = (-23 +- sqrt(529 - 1152))/(-2) , Y = (-23 +- 24.96i)/(-2) = 11.5 - 12.5i, and 11.5 + ...
  56. Math

    post it.
  57. Math

    After 3 years: P = Po + Po*r*t + 500, P = 1200 + 1200*0.086*3 + 500 = $2009.60, After 6 years: P = 2009.60 + 2009.60*0.086*3 =
  58. Physic (store energy)

    T = 2pi * sqrt L/g, T^2 = 39.5*L/g = 1.44^2, 39.5 * 0.51/g = 2.074, 20.145/g = 2.074, g = 9.71 m/s^2.
  59. algebra

    h = 30 + 75*sin60 = 94.95 Ft. above water.
  60. math

    a. 3/7 + 2/5 = 15/35 + 14/35 = 29/35. b. 35/35 - 29/35 = 6/35.
  61. Maths

    1. 2x^2 - 4x + 1 = 0, X = (-B +- sqrt(B^2-4AC))/2A, X = (4 +- sqrt(16 - 8))/4 = 1.71, and 0.294. 2. 3x^2 + 4x - 7 = 0, B^2 - 4AC = 16 + 84 = 100, The discriminant is positive; therefore, we have 2 real solutions.
  62. Maths

    X goats. 4x Legs. ns. 45-x Chickens. 2(45-x) = 90 - 2x Legs. 4x + (90-2x) = 150 Legs. X = 30 Goats. 45-x = 45 - 30 = 15 Chickens. .
  63. Physics

    Given: M1 = 5kg, V1 = 0.1 m/s. M2 = 10kg, Vz = 0. V3 = Velocity of M1 after collision. V4 = Velocity of M2 after collision. Momentum before = Momentum after. M1*V1 + M2*V2 = M1*V3 + M2*V4. 5 * 0.1 + 10 * 0 = 5*V3 + 10*V4, Eq1: 5V3 + 10V4 = 0.5. V3 = ((V1(M1-M2) + 2M2*V2)/(M1+...
  64. physics

    Unless otherwise stated, the angle is measure CCW from the +x-axis. 150o CCW = 30o N. of W. Mg = 55 * 9.8 = 539 N. = Wt. of load = Normal force(Fn). Fk = u*Fn = 0.3 * 539 = 161.7 N. = Force of kinetic friction. F*Cos30-Fk = M*a. 600*Cos30 - 161.7 = 55*a, a = ? F*Cos30
  65. Math

    a. T = 9km/36km/h = 0.25h = 15 min. b. r = 2km/20min = 0.10 km/min = 6 km/h. c. r = d/T = 11km/(15+20)min. =
  66. Physics

    When all goes out , you don't know which one to replace!
  67. Finance Math

    X = total transactions. 3x/4 - 7 = 209.. X = ?
  68. Algebra

    Eq1: S + L = 7. Eq2: 0.2S + 0.3L = 1.8. Multiply both sides of Eq1 by -0.2 and add the Eqs: -0.2S - 0.2L = -1.4 0.2S + 0.3L = 1.8 Sum: 0.1L = 0.4 L = 4. In Eq1, replace L with 4 and solve for S.
  69. algebra

    Betty is X years old. Don is X+21 years old. Six years from now: Betty: X+6 years old. Don: (X+21) + 6. (X+21)+6 = 2(x+6). X = ? x+21 = ? don ; (
  70. math

    Do you mean "What was Jessica's speed in still air"? If so: Upstream: (V-3)*T1 = 40. Eq1: T1V - 3T1 = 40. Downstream: (V+3)*T2 = 40. Eq2: T2V + 3T2 = 40. Add Eq1 and Eq2: T1V - 3T1 = 40 T2V + 3T2 = 40 Sum: T1V + T2V = 80. V(T1+T2) = 80. T1 + T2 = 7 Hours. 7V = 80...
  71. math

    d = V*T = 40. V*7 = 40, V = 5.71 mi/h.
  72. Science

    A parallel circuit.
  73. Science please help ASAP

    1c. The reflection of sound waves.
  74. Math

    Meiling has X stickers. Kelly has 5x stickers. x + 5x = 300.
  75. Physics

    A. V^2 = Vo^2 + 2a*d. 0 = 25^2 + 2a*40 a = ?(It will be negative). B. F = M*a(F will be negative). C. Fn = M*g = 2000 * 9.8 = 19,600 N. = Normal force. Fk = u*Fn = 19,600u = Force of kinetic friction. F-19,600u = M*a. F = Value calculated in part B. a = Value calculated in ...
  76. physics

    A. V = Vo + a*t. 56.5 = 35 + a*5, a = ? B. F = M*a.
  77. Finance Math

    30-year Loan: P = Po*r*t/(1-(1+r)^-t). Po = $218,000. r = 0.049/12 = 0.004083 = Monthly % rate expressed as a decimal. t = 12mo/yr. * 30yrs. = 360 Months. P = (218,000*0.004083*360)/(1-1.004083^(-360)) = $416,514.14. I = P-Po = 416,514.14 - 218,000 = $198,514.14. 15-year Loan...
  78. math

    $Po invested at 4%. $(8000-Po) invested at 5% Po*0.04*1 + (8000-Po)*0.05*1 = 350. 0.04Po + 400 - 0.05Po = 350, Po = $5000. 8000-Po = 8000-5000 = $3000.
  79. Trig

    Disp. = Displacement which is the straight line distance from the starting point (A) to the destination. I used vector analysis and trig to solve it. The only remaining method is The Law of Sine and Cosines.
  80. Trig

    Disp. = 180mi[120o] + 80mi[210o]. X = 180*sin120 + 80*sin210 = 115.9 Mi. Y = 180*Cos120 + 80*Cos210 = -159.3 Mi. Disp. = Sqrt(X^2+Y^2).
  81. Physics

    d = V*t/2. V = 330 m/s.
  82. Physics

    V = Vo + a*t = 0.1 0 + a * 0.2 = 0.1, a = 0.5 m/s^2.
  83. physics - please help me!

    Y^2 = Yo^2 + 2g*h = 0. Yo^2 + (-19.6)16 = 0, Yo^2 = 313.6 Yo = 17.71 m. = Ver. component of initial velocity. Yo = Vo*sin50 = 17.71m. Vo = 23.12m/s[50o].
  84. physics - help!

    Vo = 22m/s[35o]. Yo = 22*sin35 = 12.62 m/s = Ver. component of initial velocity. Y = Yo + g*Tr = 0 at max. ht. 12.62 + (-9.8)Tr = 0, Tr = 1.29 s. = Rise time. = Fall time(Tf). T = Tr + Tf = 1.29 + 1.29 = 0*Tr = 0,
  85. maths

    (a,4), (5,-2), (3,b). 5-a = (3-a)/2. 10-2a = 3 - a, a = 7. -2-4 = (b-4)/2.
  86. Circuits 2

    Rp = (N1/N2)^2 * RL = (1/4)^2 * 50 = 3.125 Ohms = Primary resistance. Ip = Vs/Rp
  87. Circuits 2

    What is a and b?
  88. Circuits 2

    I1 = Vi/R1 = 10/20 = 0.5A. = RMS current on primary side. I2 = I1/10 = 0.5/10 = 0.05A = RMS current on secondary side.
  89. physics

    Given: M1 = 12,801kg, V1 = 19 m/s. M2 = 2445kg, V2 = 0. V3 = Velocity of M1 and M2 after collision. Momentum before = Momentum after: M1*V1 + M2*V2 = M1*V3 + M2*V3. 12,801*19 + 2445*0 = 12,801V3 + 2445V3, V3 = 15.953 m/s. M1*V1 = 12,801 * 19 = 243,219 = Momentum before ...
  90. phyiscs

    The procedure is the same as your previous post except the unknown will be M2 1nstead of the velocity.
  91. Physics

    F = ((Vs+Va)/(Vs-Ve)) * Fe. F = ((330+41.4)/(330-21.7)) * 3680 = 4433.2 Hz. Vs = Velocity of sound. Va = velocity of the aircraft. Ve = velocity of the eagle. Fe = Freq. emitted by the eagle.
  92. Algebra

    a. 2x/3 = (2*1/2)/3 = 1/3. b. x/3 + 1/4 = (1/2)/3 + 1/4 = 1/2*1/3 + 1/4 = 1/6 + 1/4 = 2/12 + 3/12 = 5/12. The student should do c, and d.
  93. Physics

    Va = 330 m/s. Vw = 1490 m/s. 3.52 = Va/F 3.52 = 330/F, F = 93.75 Hz. Wavelength = Vw/F = 1490/93.75 = 15.89 m.
  94. Circuits 2

    R1 = (N1/N2)^2 * R2 = 20. (1/10)^2 * R2 = 20, R2 = 2000 Ohms. V2 = 10 * V1 = 10 * 10 = 100 Volts. I2 = V2/R2 = 100/2000 = 0.05A.
  95. Math

    (4400/(4400+17,600)) * 100% = 20%.
  96. Physical

    Correction: Disp. = 15 km.
  97. Physical

    d = 60 + (60-15) = 105 km. Disp. = 60-15 = 45 km.
  98. math

    W = 2 - (-7) = 9. L = 5 - (-4) = 9. It is a square. Area = 9 * 9 = 81 Square units.
  99. algebra 2

    Invested $X at 2%. Invested $4x at 5%. Invested $(5000 - 5x) at 3%. I = Po1*r1*t + Po2*r2*t + Po3*r3*t = 202.50. x*0.02*1 + 4x*0.05*1 + (5000-5x)*0.03*1 = 202.50, X = ? 4x = ? 5000-5x = ?
  100. College Algebra

    1. P = Po(1+r)^n Po = $40,000. r = 0.07/4 = 0.0175. = Quarterly % rate. n = 4Comp./yr. * 10yrs. = 40 Compounding periods. P = ? 2. P = Po * e^rt. Po = $40,000. r * t = 0.065 * 10 = 0.65. P = ?
  1. Pages:
  2. 1
  3. 2
  4. 3
  5. 4
  6. 5
  7. 6
  8. 7
  9. 8
  10. 9
  11. 10
  12. 11
  13. 12
  14. 13
  15. 14
  16. 15
  17. Next>>