Posts by Henry

Total # Posts: 14,118

Physics
d = V*t = 3*10^8m/s * 2.37s/2 =

Math
post it.

Math
(8,9), (x,y), (-7,4). x-8 = 2/3(-7-8). x = -2. y-9 = 2/3(4-9). Y = 17/3 = 5 2/3.

Math
49km/7tanks = 7.00km/tank.

Math 6th grade
Width = 756ft/(280ft/in) = 2.7 1n.

Math/Physics
h = 100*sin20 = 34.2 m. V^2 = Vo^2 + 2g*h. V^2 = 5^2 + 20*34.2 = 709, V = 26.63 m/s.

Math
25x = 500. X = 20 Weeks to pay off the debt. Even though my choice is "a", I don't understand Greg's Eq. Are you sure it is correct? The amount owed increases as x increases. Could it be Y = 600-20x? If so, then Greg would pay off his debt in 30 weeks: Y = ...

Physics
My first post was done in error. Please disregard it.

Physics
Vo = 22.5m/s[19.3o]. Yo = 22.5*sin19.3 = 7.44 m/s = Ver. component of initial velocity. Y = Yo + g*Tr = 0 at max. ht. = 7.44 + (-9.8)Tr = 0, Tr = 0.759 s. = Rise time. T = 2*Tr = 2 * 0.759 = 1.52s = Time to return to top of roof. T + Tf = 3.5s. 1.52 + Tf = 3.5, Tf = 1.98s = ...

Physics
Vo = 22.5m/s[19.3o]. Yo = 22.5*sin19.3 = 7.44 m/s = Ver. component of initial velocity. Y = Yo + g*Tr = 0 at max. ht. = 7.44 + (-9.8)Tr = 0, Tr = 0.759 s. = Rise time. T = 2*Tr = 2 * 0.759 = 1.52s = Time to return to top of roof. T+Tf = 3.5s. 1.52 + T

physics
Va = 1200rev/60s * 6.28rad/rev = 125.6 rad/s = Angular velocity. Circumference = pi*2r = 3.14 * 0.12m = 0.377 m. d = 1200rev/60s * 3s * 0.377m/rev = 22.6 m.

Physics
No. When resistors are connected in series, the potential difference across each is the same only if the resistors are the same. So, if you connect two 1,000 Ohm resistors in series; the potential difference across each will be the same. I hope this helps.

Math
the 8th terms of a geometry progression is 640. if the first term is 5, find the common ratio and the 10th terms?

Math
the 3rd and the 9th terms of a geometry progression are 54 and 39, 366 respectively. find the 6terms

physics
V3 = 0.96 m/s = Velocity of M1 and M2 after the collision.

physics
Given: M1 = 0.0024kg, V1 = ?. M2 = 0.650kg, V2 = 0. V3 = 0.96 m/s = Velocity of M1 and M2 after the c024V1ollision. Momentum before = Momentum after: M1*V1 + M2*V2 = M1*V3 + M2*V3, 0.0024*V1 + 0.65*0 = 0.0024*0.96 + 0.65*0.96, V1 = ?.

Algebra 1
a. Correction: V = C(1-r)^t.

Algebra 1
a. V = C - C*(1-r)^t. V = Value. C = Cost. r = Depreciation rate. T = Time in years. b. V = 22,385(0.86)^10 =

Algebra 1
a(1)-b(1) = a - b.

Physics
Given: M1 = 0.17kg, V1 = 0.05 m/s. M2 = 0.16kg, V2 = 0. V3 = 0. = Velocity of M1 after the collision. V4 = ? = Velocity of M2(red ball) after the collision. Momentum before = Momentum after. M1*V1 + M2*V2 = M1*V3 + M2*V4. 0.17*0.05 + 0.16*0 = 0.17*0 + 0.16*V4, 0.16*V4 = 0.0085...

Physics
Momentum before = Momentum after: M1*V1 + M2*V2 = M1*V3 + M2*V4. 1.1*2.7 + 2.4*(-1.9) = 1.1*V3 + 2.4*V4, 1.1*V3 + 2.4*V4 = -1.59. Conservation of KE Eq: V3 = (V1(M1-M2) + 2M2*V2)/(M1+M2). V3 = (2.7(1.1-2.4) + 4.8*(-1.9))/(1.1+2.4) = -3.61 m/s = 3.61 m/s, west = Velocity of ...

math - bearings
When using Bearings, multiplying the distance by the Cos of the angle gives the vertical component instead of the usual hor. component. Displacement = 1.5km[30o] + 3.5[160] + 6.25[300]. Disp. = (1.3i+0.75) + (-3.29i+1.2) + (3.125i-5.41) = -3.46 + 1.14i = 3.64km[-18.2o] = 3....

math - bearings
When using bearings, multiplying the distance by the Cos of the angle gives the vertical component instead of the usual hor. component. We need the vertical component only. Displacement = 450km[320o] + 130[350o] + 330[50o]. Y = 450*Cos320 + 130*Cos350 + 330*Cos50 = 344.72 + ...

Math
Where are the problems?

Physics
h = 0.5g*t^2 = 10m. 4.9t^2 = 10, t = 1.43s. = Fall time. d = V*T = 1.1 * 1.43 = 1.57m from base of tree. d = V*t = 5-1.57 = 3.43m. V*1.43 = 3.43, V = 2.40 m/s.

Physics
d = Vo^2*sin(2A)/g. d = 10^2*sin(80)/9.8 = 10.05 m. No!

Real World Problem: Ratios
Skiers/Snowboarders = 2/3. X/(X+250) = 2/3. X = ?.

Math
2. 35/7 = 5 Million per day. 3. 135%/100 = 1.35. 1.35 * 300 = 405. 4. 2/3(x+7) = 5. Multiply both sides by 3: 2(x+7) = 15, 2x + 14 = 15, 2x = 15-14, 2x = 1, X = 1/2. 5. White grapes: $4.70/2.5Lbs = $1.88/Lb. Red grapes: $5.98/3.25Lbs = $1.84. 6. (55/44)*100% = = 125%, Change...

Math
1. 14.5 - 1.5 = 13 quarts needed. 13qrts./(3.25qrts./batch) = 4 Batches.

Math
(6^4*6^9/6^3)^3 = (6^13/6^3)^33 = (6^10)^3 = 6^30.

Math
L = 12 in. W = 6 in. h = 8 in. As = 2(W*h) + 2(L*W) + 2(L*h) = Surface area.

physics
Displacement = V*T1 + V*T2 + V*T3. Disp. = 60*(40/60) + 60*(20/60)[45o] + (-60(50/60), Disp. = 40 + (14.14+14.14i) + (-50) = 4.14 + 14.14i = 14.73km[73.7o]. T = T1+T2+T3 = 40 + 20 + 50 = 110 Min. = 1.833 Hours. V = Disp./T = 14.73km[73.7o]/1.833 = 8.03km/h[73.7o].

phyics
M1 = 68kg, V1 = ?. M2 = 0.057kg, V2 = 38 m/s. M1*V1 = -M2*V2. 68*V1 = -(0.057*38), V1 =

Physics
Circumference = pi*2r = 3.14 * 7.2 m. V = 0.15rev/s * 7.2m/rev =

Math
The force E needed to make a machine pull a load is partly constant and partly varies as the load L to be pulled.For a load of 20kg the force needed is 14N while 20N is needed for a load of 30kg find: a)The formula connecting E and L. b)E when L=50kg

Resistance, Circuits
Given: L = 9.0 m. Dia. = 8.0*10^-2 mm = 8.0*10^-5 m. R = 224 Ohms. R = p*L/A. p = A*R/L. = Resistivity. A = pi*r^2 = 3.14 * (4*10^-5)^2 = 50.3*10^-10m^2. p = (50.3*10^-10 * 224)/9 = 1.3*10^-7 Ohm-meters.

physics
Given: M1 = 3kg. M2 = 2kg. h = 14.9m. d = 14.9 - 5 = 9.9m Traveled. V^2 = Vo^2 ) 2g*d = 0 + 19.6*9.9 = 194, V = 13.93 m/s = Velocity of each body. Momentum1 = M1*V. Momentum2 = M2*V. KE1 = 0.5M1*V^2. KE2 = 0.5M2*V^2.

Physics Help!
M*g = 54 * 9.8 = 529.2 N. = Wt. of skier. Fp = 529.2*sin15 = 137 N. = Force parallel to the hill. Fn = 529.2*Cos15 = 511 N. = Normal force. Fap-Fp = M*a. Fap-137 = 54*1.2, Fap = 201.8 N. = Applied force = Tension in rope.

Math Help please & thankyou
You are welcome!

Math Help please & thankyou
6/20 = 3/10 = 0.3 = 30%. 3/10 was obtained by dividing the numerator and denominator by 2.

physics help please
Momentum = M*Va = 33 * 4.1 = 135.2.

physics help please
Circumference = pi*2r = 3.14 * 4.4 = 13.8 m. Va = 9m/s * 6.28rad/13.8m = 4.1 rad/s. = Angular velocity.

Math
Cost = $250/100 = $2.50/pencil. Loss = 2.50 - 1.75 = $.75/pencil. (0.75/2.50) * 100% = 30% Loss.

Physics
Correction: V = 62.8cm/rev * 2rev/s = 125.7 cm/s.

Physics
Circumference = pi*2r = 3.14 * 20 = 62.8 cm. V = 62.8m/rev. * 2rev/s = 125.7 m/s.

physics
Correction: F = Fk = Force of kinetic friction.

physics
F-Fk = M*a. F-Fk = M*0, F-Fk = 0, F = Fk. = Force of kinetic energy.

math
95 = 1*95 = 1 * 5*19 = Prime factors of 95.

Physics
PE = M*g*h. 100 = 2 * 9.8 * h. h = ?.

Physics
PE = M*g*h Joules.

Math
Cindy, how did you get 3/40? The answer will be greater than 15, because 15 1/5 = 15 + 1/5 = 15/1 + 1/5 = 75/5 + 1/5 = 76/5. Note: I found a common denominator for the two fractions and added them.

Math
Use only the positive(absolute) value of the results inside the brackets. The student should do P5 and P6, and use the six points for graphing. The sketch will resemble a parabola that opens upward. Y = |x-3| - 2. Y = |0-3| - 2 = 3 - 2 = 1. P1(0,1). Y = |1-3| - 2 = 2 - 2 = 0. ...

Physics
M*g = 21 * 9.8 = 205.8 N. = Wt. of crate = Normal force(Fn). Fk = u*Fn = 205.8u. Fap-Fk = M*a. 350-205.8u = 21*0, u = ?.

Math
post it.

Mathematics- Algebra
You are welcome!

Mathematics- Algebra
a^7 * y^7 = (ay)^7.

physics
Vo = 49m/s[30o] = Initial velocity. Xo = 49*Cos30 = 42.4 m/s = Ver. component. Yo = 49*sin30 = 24.5 m/s = Hor. component. A. Y^2 = Yo^2 + 2g*h. 0 = 24.5^2 + (-19.6)*h, h = 30.63 meters. B. Range = Vo^2*sin(2A)/g Range = 49^2*sin(60)/9.8 = 212.2 m. C. Y = Yo + g*Tr. 0 = 24.5...

Math
Slope = Y/X = 10/20 = 0.50

Physics
post it.

Physics
h = 3.2*sin36 = 1.88 m. Ht. of incline. V^2 = Vo^2 + 2g*h = 0 + 19.6*1.88 = 36.9 V = 6.1 m/s = Final velocity. V^2 = Vo^2 + 2a*d. 6.1^2 = 0 + 2*a*3.2, a = 5.8 m/s^2. Another Method: M*g = 12*9.8 = 117.6 N. = Wt. of block. Fp = 117.6*sin36 = 69.1 N. = Force parallel to the ...

Physics
M*g = 35 * 9.8 = 343 N. = Wt. of box = Normal force(Fn ). Fk = u*Fn = 0.7 * 343 = 240 N. = Force of kinetic friction. Fap-Fk = M*a. 275-240 = 35a, a = ?.

Physics
M*g = 25 * 9.8 = 245 N. = Wt. of ball. Fap-Mg = M*a. 110-245 = 25a, a = -5.4 m/s^2.

trigonometry
4. Correction: Ac = arc = 2.4 radians.

trigonometry
post it.

trigonometry
4. arc = 6m., D = 5m. Ac = Central angle. Circumference = pi*D = 3.14 * 5m = 15.7m. Arc = (6m/15.7m) * 6.28radians = 2.4 radians. Ac = Arc/Radius = 2.4/2.5 = 0.96 radians.

trigonometry
3. Corrections: Circumference = pi*D = 3.14*200 = 628in Arc1 = 143.7 in. Arc1 = (143.7in/628in) * 360o = 82.4o. Vertex angle = 82.4/2 = 41.2o. Base angles = (180-41.2)/2 = 69.4o each

trigonometry
1. Circumference = pi*D = 3.14 * 15 = 47.1 m. 11.25m/47.1m * 360deg. = 86.0 Deg. 3. Circumference = pi*D = 3.14 * 200 = 628 in. Arc1 = Base(S1) = 143.7 in. Arc2 = Arc3 = (628-143.7)/2 = 242.15 in. = S2 = S3. S1, S2, and S3 are the sides of the triangle. Draw the altitude of ...

HVAC
Tech. B is correct.

Physics
Note: The kinetic energy Eq. derived was not required for this problem. It could have been used to calculate the total kinetic energy after the collision.

Physics
Conservation of Momentum: M1*V1 + M2*V2 = M1*V3 + M2*V4. 1.1*2.7 + 2.4*(-1.9) = 1.1V3 + 2.4V4, 1.1V3 + 2.4V4 = -1.59. Conservation of Kinetic Energy: 0.5M1*V1^2 + 0.5M2*V2^2 = 0.5M1*V3^2 + 0.5M2*V4^2. Divide both sides by 0.5: M1*V1^2 + M2*V2^2 = M1*V3^2 + M2*V4^2. 1.1*2.7^2...

Physics
M1*V1 + M2*V2 = M1*V + M2*V. 103*2 + 110*(-3.2) = 103V + 110V, V = -0.685 m/s. = 0.685 m/s West.

physics
M*g = 12 * 9.8 = 117.6 N. = Wt. of block. Fp = 117.6*sin40 = 75.6 N. = Force parallel to incline. Fn = 117.6*Cos40 = 90.1 N. = Normal force. Fk = u*Fn = o.4 * 90.1 = 36.0 N = Force of kinetic friction. A. Fnet = Fp-Fk = 75.6 - 36.0 = 39.6 N. = Net force. B. Fnet = M*a. 39.6 = ...

Borrowing money
A. Po = 500 + 0.05*500 = $525. = Initial principal or cost.

Geometry
sin60 = 7/L. L = Length of ladder. L is also the hypotenuse of a right triangle.

physics
Y^2 = Yo^2 + 2g*h. 0 = Yo^2 + (-19.6)*150, Yo = 54.2 m/s = Initial ver. component. 1. Y = Yo + g*Tr. 0 = 54.2 -9.8Tr, Tr = 5.53 s. = Rise time. Tf = Tr = 5.53 s. = Fall time. Tr+Tf = 5.53 + 5.53 = 11.1 s. = Time of flight. 2. Vo = 100m/s[Ao]. Yo = 100*sin A, 54.2 = 100*sin A, ...

MATH (HARD!)
d = 1.5(3.6+4.2) = 11.7 miles. Do your teacher know how to solve the problem? Can she get the opinion of another math teacher at the school?

Physics
A. d = 0.5g*t^2. B. V^2 = Vo^2 + 2g*d. Vo = Initial velocity. V^2 = 0 + 19.6*2.10 = 41.16, V = 6.42 m/s. C. V = Vo + g*t. = 0 + 9.8*3.08 = D. V = Vo + g*Tr. 0 = 4.85 - 9.8Tr, Tr = 0.50 s. = Rise time. Tf = Tr = 0.50 s. = Fall time from max ht. to top of tower. Tr+Tf = 0.50 + 0...

Math
A. (-4,9), (-4,3). d^2 = (4-4)^2 + (3-9)^2. d^2 = (0)^2 + (-6)^2 = 0 + 36 = 36, d = 6 = Distance from Maria's house to school. B. (-4,3), (-4,-8). d^2 = (4-4)^2 + (-8-3), (^2. d^2 = (0)^2 + (-11)^2 = 121. d = 11 = Distance from school to grocery store. 6+d = 6+11 = 17 = ...

MAth
To break even: Income = Cost. 12x = 4x + 6000. X = 750 T-shirts.

Physics
T1 = 1.97 s. T2 = ?. 2pi = 6.28 T1 = 2pi*sqrt(L/g). T1^2 = 39.5*L/g, 1.97^2 = 39.5L/9.8, L1 = 0.962 m. L2 = 2.50 * 0.962 = 2.41 m. T2 = 6.28*Sqrt(2.41/9.8) = 3.11s.

physics
h = 1.3*sin30 = 0.65 m. Vo = 50cm = 0.50 m. V = Speed at bottom of the ramp. V^2 = Vo^2 + 2g*h. V^2 = 0.50^2 + 19.8*0.65 = V = 3.60 m/s.

Physics
V^2 = Vo^2 + 2a*d. 0 = (2.2)^2 + 0.4a, a = -12.1 m/s^2. F = M*a = 1500*(-12.1) = -18,150 Joules. The negative sign means the force opposes the motion.

Math
Right now: Moesha is (3G+1) years old. Shanti is 2(3G+1) or (6G+2). A. Sum = ((3G+1)+2) + ((6G+2)+2) = (9G+7) Years. B. Diff. = (6G+2) - (3G+1) = (3G+1). Shanti = (6G+2) + (3G+1) = (9G+3) Years old. C. Moesha = (3G+1)-4 = (3*5+1)-4 = 12 years old. Shanti = (6G+2)-4 = ?.

Math
(5*600) + (5*400) = 5(600+400) = 5*1000 = 5,000. Note: Our first step was to factor out the 5, because it is common to both terms.

Math
Incomplete.

physics
M = 1.57*10^8 kg. Ft = 7.47*10^5 N. Fr = ?. Ft-Fr = M*a. Ft-Fr = M*0, Ft-Fr = 0, Fr = Ft = 7.47*10^5 N.

physics
L = 3300/(2.75*6*8) = 25 cm.

physics
D = 2.75 g/cm3. M = 3.30 kg. = 3,300 g. M = D * V. 3,300 = 2.75 * (6*8*L), L = ?.

physics
0.5M*V^2 = KE. 0.5M*5^2 = 500, M = 40 kg. KE = 0.5*40*10^2 =

Math
1-(1/3+2/7) = 21/21 - (7/21+6/21). 21/21 - 13/21 = 8/21 of those surveyed chose neither color. 8/21 * 1092 = 416 Named neither blue nor red.

maths
a. Cost = 0.2*6 + 0.8*0.5 = $1.60.

maths
Juice = x Liters. Lemonade = 4x Liters. x + 4x = 1 Liter. X = 0.2 Liters. 4X = 4*0.2 = 0.8 Liters. = a. Cost = 0.2*6 + 0.8*0.5 $1.60. b. Profit = Sale Price-Cost = 2.00-1.60 = 0.40. %Profit = (Profit/Cost)*100 =

Maths
d = (3 3/4km)/Lap * 4 1/2Laps. d = 15/4 * 9/2 = 135/8 = 16 7/8 km.

physics
Ro + Ro*0.0068/oC*(T2 -T1) = 1.15Ro. Divide both sides by Ro: 0.0068/oC*(T2-20) = 1.15, T2-20 = 169, T2 = 189oC. %Increase = ((T2-T1)/T1)*100% %Increase = ((189-20)/20)100 = 845%.

As physics
See your previous post: Thu, 11-30-17, 7:02AM.

Physics
Vs = 332 + 0.6T. 341 = 332 + 0.6T, T = 15 degrees Celsius.

Physics
All angles are measured CCW from +x-axis: Fr = 10m[135o] + 20m[30o] + 35m[270o]. Fr = (-7.07+7.07i) + (17.32+10i) + (0-35i), Combine like-terms and convert to polar form: 10.25 - 17.93i = 20.7m[-60o] = 20.7m[60o] S. of E.

physics
Incomplete.

physics
In.etcomple

Finance
The answer is b.

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