# Posts by Helper

Total # Posts: 1,842

**algerbra**

not enough info, please re-check your problem.

**ALGEBRA**

see your first post below, I solved it for you and explained

**maths**

P = a + b + c add the three sides P = 8x - 7w + 3x + 9y + 3y + 5w combine like terms

**math**

by the cofunction property cos B = sin A so, if angle B = 33 angle A = ?

**precalc**

Sine is an odd function, sin(-Î¸)= -sin Î¸

**precalculus**

2 rads to converts radian to degrees, multiply by 180/pi 2 * 180/pi = (2 * 180)/3.14 = ?

**algebra**

3x + 9y = 18 y = mx + b solve for y, 9y = -3x + 18 y = -3x/9 + 18/9 simplify the equation

**Math**

A = pi r^2 pi = 3.14 r = 5 A = (3.14)*(5^2) A = (3.14)*(25) A = ? m^2 do the multiplication for your answer I don't know what this sentence means. Is this the same as the surface area and it would be 10m?

**ALGEBRA**

I followed that 3 + x(12*4) = 24 multiply 12*4 3 + 48x = 24 subtract 3 from both sides 3 - 3 + 48x = 24 - 3 48x = 21 divide both sides by 48 48x/48 = 21/48 x = 21/48 reduce fraction x = 7/16

**ALGEBRA**

what is 'pemdas'?

**ALGEBRA**

3 + x(12*4) - 24 if that is the problem then, 3 + 48x - 24 48x - 21 48x = 21 x = 21/48 x = 7/16 you can only combine 'like terms' x terms can only be added to other x terms, constant terms can only be added to other constant terms. do you understand?

**ALGEBRA**

I need to see the original problem first to help you. why did you add 48x + 3 to equal 51x? then the 'x' is gone in the next line?

**Statistics**

see 1st link below under 'Related Questions' for this exact problem

**Taxes**

No. Each partner includes his or her share of the partnership's income or loss on his or her personal tax return.

**5th grade**

17,13,27,33,25 put the numbers in order, from smallest to largest 13, 17, 25, 27, 33 the median is the number in the middle so, the median would be 25 for the mean, add all the numbers and then divide the sum by the number of numbers that you added. 13 + 17 + 25 + 27 + 33 = ? ...

**Algebra -- Help**

Train A has a lead of 12 min. RT = D T = time train B T + .20 = time train A 90T = distance train B 80(T + .20) = distance train A 80(T + .20) = 90T 80T + 16 = 90T 16 = 10T T = 1.6 hours train B overtake train A = 1.6 hours

**geomitry**

x = 1st angle 90 - x = 2nd angle 5x - 16 = 3rd angle x + 90 - x + 5x - 16 = 180 solve for x

**math**

what is the figure? square, cube, sphere, etc?

**algebra**

-6m + 3/11 = 77/11 to solve subtract 3/11 from both sides then divide both sides by -6

**Pre-algebra**

A = 1/2 bh multiply both sides by 2 2A = bh to find h, divide both sides by b can you finish this?

**math**

sketch a right triangle A = 55 degrees c = 50 a = unknown (kite height) sin 55 deg = a/c = a/50 = 0.8192 solve for a

**help math ahhhh**

9. 5x + 4y = 1 3x ? 4y = 7 what does ? mean ?

**mathematics**

simplify 2/(x^(-3/2))= 2x^(3/2)

**AiMS MATH**

Natural numbers are the counting numbers, 1, 2, 3, etc Integers are the counting numbers, together with their opposites and zero. whole numbers are the counting numbers without the zero. Rational numbers are the set of all numbers that can be written as quotients, ie, 1/2. ...

**math**

yes, correct good job! :)

**math**

5 * (thirdrt 48) - (thirdrt 750) breakdown the radicals 5 * (3rt 8)(3rt 6) - (3rt 125)(3rt 6) can you do this now?

**math i need help please**

B. what are you having trouble with? did you find r (common ratio)? post what you found for r and the first term so I can understand what part of this you don't understand.

**MATH I NEED HELP PLEASE!**

Reposting a problem in all caps is rude. it's like you are shouting.

**Analytical Geometry**

(sin^2 x)/(sec^2 x - 1) (sin^2 x)/(tan^2 x) (sin^2 x)/(sin^2 x/cos^2 x) (sin^2 x) * (cos^2 x/sin^2 x) cos^2 x therefore, (sin^2 x)/(sec^2 x - 1) = cos^2 x

**geometry**

is this a triangle? is this a right triangle? need more specific info to solve

**MATH HELP ME NOW PLEASE!!**

see your above latest post

**algebra**

w = width 4w + 6 = length P = 2w + 2L 42 = 2w + 2(4w + 6) Solve for w

**algebra**

y = 2x + 5 y = 3x substitute, y = 3x in y = 2x + 5 y = 2x + 5 3x = 2x + 5 solve for x, use x value to find y What do the "?" mean? I see them in most of your posted problems. In this case, the "?" in this problem are part of the answer, so it didn't ...

**arithmetic**

Add 17 + 5 = 22 therefore, 17/18 + 5/18 = 22/18

**math**

G = Glen's present age B = Ben's present age B = 4/7 G G + 15 + B + 15 = 63 substitute, B = 4/7 G G + 15 + 4/7 G + 15 = 63 Solve for G

**Trig**

cos^2 x = 1 take square root of both sides +- cos x = 1 cos x = 1 cos x = -1 for what angle value is cos = 1 and cos = -1 ?

**physics**

should have added above, 1 mi = 5280 feet 1 mi = 1609.344 meters 1 mi/min = 60 mi/hr 1 mi/min = 88 ft/sec 1 mi/min = 26.8224 meters/sec sorry for the confusion. I wish there was a 'do over' button. :)

**physics**

1.00 mi in 4.00 min 1 mile/min = 60 mph 1 mile/4 min = 0.25 mi/min 1. 0.25 x 60 mi/hr = ? mph 2. 0.25 x 88 ft/sec = ? ft/sec 3. 0.25 x 26.8224 meters/sec = ? meters/sec

**Math**

circles that form E? how can a circle form an E? I don't understand

**alg2**

3x âˆ’ 7 (sqrt x) + 2 = 0 -7(sqrt x) = -3x - 2 divide both sides by -7 (sqrt x) = 1/7(3x + 2) square both sides x = 1/49 (3x + 2)^2 expand the right side you will have a quadratic equation that can be solved either by completing the square or using the ...

**alg 2**

x^3/4 * x^3/4 * x^3/4 = x^9/64

**5th grade math**

w = 78 L = 68 p = 2w + 2L p = 2(78) + 2(68) can you do this now?

**algebra 2**

v^2 + 8v + 6 = 0 this cannot be factored either complete the square or use the quadratic formula to solve

**algebra 2**

quadratic formula x = (-b +- (sqrt(b^2 - 4ac))/2a 5x^2 + 3 = -7x 5x^2 + 7x + 3 = 0 a = 5, b = 7, c = 3 plug these into the formula and solve

**alg. 2**

2.25 + .15x = 1.50 + .18x solve for x

**math**

incomplete problem

**Junior Math**

(t^2-1)/(t^2+7t+10) - (2t+4)/(t^2-t-6) factor the denominators first (t^2-1)/(t+2)t+5) - (2t+4)/(t-3)(t+2) LCD is (t+2)(t+5)(t-3) Now, can you combine over the LCD?

**ALGEBRA**

x + 2y - 4 = 0 x + 2y = 4 to find x-intercept, y = 0 x + 2(0) = 4 x = 4 x-intercept = (4.0) slope intercept form (which you got right above) y = mx + b for Line A is y = -1/2 x + 2 slope m = -1/2 If two lines are perpendicular, the slope of one is the negative reciprocal of ...

**math**

5/4 x + 1/8 = 5/8 + x 5/4 x = 4/8 + x multiply both sides by 8, (LCD of 4 and 8) then solve for x

**math**

you need to use parentheses 5/4x1 divided by 8x = 5/8 + x ? what is "4x1"?

**Algebra 1**

you're very welcome :)

**Algebra 1**

f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ? 5^2 = 5 x 5 = 25 f(5) = 5^2 + 3 f(5) = 25 + 3 f(5) = 28

**Algebra 1**

No, f(5) does not = 10 f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ? 5^2 = ? 5^2 + 3 = ? show me how you got 10

**Algebra 1**

f(x) = x^2 + 3 f(2) = 2^2 + 3 f(2) = ? 2^2 = 4 f(2) = 2^2 + 3 f(2) = 4 + 3 f(2) = 7 the answer for f(2) is 7 when x = 2, the function value = 7 now, you do the other one

**Algebra 1**

just plug in the values for x and solve f(x) = x^2 + 3 f(2) = 2^2 + 3 f(2) = ? f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ?

**math 5th grade**

5/5 * 2/3 = ? 100, 10, 1, 1/10

**Math**

I = PRT 525 = 3500 *.06 * T Solve for T (time) this is simple interest

**rectangular area**

you're welcome

**rectangular area**

A = Lw 240 = 24w w = ?

**To helper**

I do when they post more than one of the same type problem, but I understand and will only set up for now on

**Cylinder Height**

r = radius 3r = height (h) SA = 2(pi)(r)(h) + 2(pi)(r^2) SA = 2(pi)(r)(3r) + 2(pi)(r^2) SA = 6(pi)(r^2) + 2(pi)(r^2) SA = 8(pi)r^2 402 = 8(pi)r^2 402 = 8(3.14)r^2 402 = 25.12r^2 16.00318 = r^2 rounding 16.00318 = 16 16 = r^2 r = 4 height = 3r = 3(4) = 12

**algebra**

|x + 5| > 9 remove absolute value sign x + 5 > 9 x > 4 -x - 5 > 9 -x > 14 when you divide by a negative, reverse the sense of the inequality x < -14 x > 4 x < -14

**math**

(3xy - 10) - (xy + 5) 3xy - 10 - xy - 5 2xy - 15

**TO Helper**

I figured those were yours. I'm going through those now (and others). I try to help everyone I can. I don't exactly understand the donut problem either because the equation doesn't seem to work if all donuts were sold. I'm hoping REINY or another math tutor ...

**TO Helper**

the screen name "Anonymous" belongs to anyone who left the name field blank, so I have no idea which posts are yours. I scan all problems and help where I can. I am not a tutor so I only help on problems I am sure of.

**MATH ALGEBRA**

2x- 3y + 30 = 0 ? to find x and y intercepts, put equation in the form ax + by = c x intercept = (c/a, 0) y intercept = (0, c/b) to find x-intercept, y = 0 2x - 3(0) = -30 2x = -30 x = -15 x intercept = (c/a, 0) x intercept = (-15, 0) to find y-intercept, x = 0 2(0) - 3y = -30...

**4th Grade**

2/9 * 36 = 72/9 = 8

**Algebra 1**

-0.2x < -10 divide both sides by -0.2 when dividing by a neg, reverse the sense of the inequality x > 50

**algerbra**

yes, you are correct

**alg. 2**

x^2 - 16x + 4 = 0 x^2 - 16x = -4 (-16^2)/4 = 256/4 = 64 x^2 - 16x + 64 = -4 + 64 x^2 - 16x + 64 = 60 (x - 8)^2 = 60

**MATH_ALGEBRA**

you're welcome :)

**MATH_ALGEBRA**

(1) F + 1000P = 32 (2) F + 3500P = 44.50 you have to solve these 2 equations simultaneously By elimination method, to eliminate F, multiply one of the equations by -1 -1(F + 1000P = 32)= -F - 1000P = -32 Now ADD these two equations together -F - 1000P = -32 F + 3500P = 44.50 0...

**MATH-ALGEBRA**

y = 2/5x - 3 P (0,5) parallel lines have equal slopes slope intercept form of an equation y = mx + b m = slope, b = y-intercept parallel to y = 2/5x - 3, and through P(0, 5) m = 2/5 y intercept = 5 so, the equation would be D. y = 2/5x + 5

**math**

A = B + 5 B = C + 7 C = THE DIFFERENCE BETWEEN 13 AND 9 D = A - B C = 13 - 9 = 4 B = C + 7 = 4 + 7 = 11 A = B + 5 = 11 + 5 = 16 D = A - B = 16 - 11 = 5 A = 16 B = 11 C = 4 D = 5

**algebra**

quadratic formula x = (-b +- (sqrt(b^2 - 4ac)))/2a 1) x^2 = 9 x^2 - 9 a = 1, b = 0, c = -9 x = 0 +- (sqrt(0^2 - 4(1)(-9)))/2(1) x = + - (sqrt(0 + 36))/2 x = +- (sqrt36)/2 x = +- 6/2 x = +- 3 x = 3, -3 you try number 2

**math**

Supplementary angles: two angles whose measures total 180 deg x = 1st angle 3x - 4 = 2nd angle x + 3x - 4 = 180 solve for x to find the angles

**algebra**

for michele (3x-2)/(5)-2<(2x-3)/(2) multiple both sides by LCD of 10 2(3x - 2) - 20 < 5(2x - 3) 6x - 4 - 20 < 10x - 15 6x - 24 < 10x - 15 -9 < 4x -9/4 < x x > -9/4

**Math**

if this your problem | 1 - 4x/3 | < 3 remove absolute value sign 1 - 4x/3 < 3 and -1 + 4x/3 < 3 1 - 4x/3 < 3 -4x/3 < 2 -4x < 6 x > -6/4 x > -3/2 -1 + 4x/3 < 3 4x/3 < 4 4x < 12 x < 3 so solution is -3/2 < x < 3

**math**

from above .03 = value of mixture this should be x + 100 = mixture total number of oz

**math**

x = number oz of cheaper tea .02x = value of cheaper tea 100 = number oz of better tea .05 * 100 = 5.00 = value of better tea .03 = value of mixture .03(x + 100) = value of mixture .02x + 5.00 = .03(x + 100) .02x + 5.00 = 3.00 + .03x 2.00 = .01x x = 200 200 oz of .02 tea

**Intermediate Algebra**

V = 2(pi * L^2) or V = 2pi * 2L^2

**algebra**

(4/(x + 2) - 4/x)/2 = 1 rewrite as (4/(x + 2) - 4/x) * 1/2 = 1 4/(2(x + 2)) - 4/2x = 1 4/(2x + 4) - 4/2x = 1 LCD 2x(2x + 4) (8x - 4(2x + 4))/(2x(2x + 4)) = 1 multiply both sides by 2x(2x + 4) 8x - 4(2x + 4) = 2x(2x + 4) 8x - 8x -16 = 4x^2 + 8x -16 = 4x^2 + 8x 4x^2 + 8x + 16 = ...

**math!!!**

g(x) = 2x^2 + x - 1 The degree of an equation that has not more than one variable in each term is the exponent of the highest power to which that variable is raised in the equation. b. 2 is the answer

**math!!!**

h = -6(t - 2.5)^2 + 38.5 plug in a few values for t when t = 1, h = 25 when t = 2, h = 37 when t = 2.5, h = 38 when t = 3, h = 37 you try, what do you think the answer is

**Algebra**

x = each base vertex angle = 1/2x + 10 solve x + x + 1/2x + 10 = 180

**Algebra II**

3/x^3 divided by 1/x^2 is this your problem? instead of dividing, invert and multiply 3/x^3 * x^2/1 = 3x^2/x^3 = 3x^-1 = 3/x

**algebra**

8/26 = m/13 cross multiply means denominator of 1st * numerator of 2nd numerator of 1st * denominator of 2nd 26M = 104 M = 4

**algebra**

11T/28-T / 4 = 1 rewrite problem 11T/28 - T * 1/4 = 1 11T/(4(28 - t)) = 1 11T/(112 - 4T) = 1 11T = 112 - 4T 15T = 112 T = 7.47

**advance algebra**

X=smaller number y= bigger number y - x = 192 9x = bigger number 9x - x = 192 8x = 192 x = 24 smaller number bigger number = 9x = 9(24) = 216

**calculus**

A = Lw 25 = Lw w = 25/L P = 2w + 2L P = 2(25/L) + 2L P = 50/L + 2L

**Algebra 1**

5x + y = 5x + (3x âˆ’ 11) = 13. where are you getting these problems? there is no way to solve the way you have written this. copy the problem exactly from your book

**Algebra 1**

no way to solve this

**math**

cannot solve either as separate equations

**math**

see your other post

**ALGEBRA**

4 + x(10 - 8) 4 + 10x - 8x 4 + 2x 2x = -4 x = -2

**Algebra 1**

5y + 4x = -41 what are you solving for? copy the complete problem from your book there isn't anything to solve for above, unless 5y + 4x = -41 5y = -41 - 4x y = (-41 - 4x)/5 4x = -41 - 5y x = (-41 - 5y)/4 is this what you want there is nothing else to solve for

**algebra**

don't understand what you need done repost

**MATH**

881/5 = 176 1/5

**Algebra 1**

5y + 4x = -41 what are you solving for?

**Algebra 1**

incomplete problem try again :)