Posts by Helper
Total # Posts: 1,843
I'm not sure I'm following you. Do you just want the total 39.60 in the total column? If so, go to Cell E (col E) and click on 'Auto Sum'. One of the choices are "More Functions". Click on that. A box will come up. Type "Product" in that box...
You don't want a sum, you want a product. Use auto sum button, and choose more functions, put multiply or product in the search box and choose 'Product'.
Please check one of your previous posts. You have posted this exact question 4 times today. It has been answered by 3 different tutors. Exactly what is it that you do not understand?
-2/5 x = 6/35 Multiply both sides by 35 -14x = 6 x = -6/14 = -3/7
Assuming you want to solve these simultaneously. 9m + n = 22 m - 3n = 18 To eliminate variable n, mulyiply the first equation by 3 3(9m + n = 22) = 27m + 3n = 66 Now add these two equations together 27m + 3n = 66 m - 3n = 18 28m + 0 = 84 28m = 84 m = 3 Substitute m = 3 in m - ...
V = Lwh w = width w - 2 = height w + 4 = length 8(w + 4) = V 8(w + 4) = w(w - 2)(w + 4) Solve for w
thaokieu, the tutors are not here to do YOUR homework. You have to try to solve these yourself. Post your work for each problem and someone will help if you are stuck.
Chloe, the tutors are not here to do YOUR homework. You have to try to solve these yourself. Post your work for each problem and someone will help if you are stuck. It helps if you draw a picture. The problems I've done for you today all involve right triangles. So read ...
4(8-2x)+2x<5(9+3x) 32 - 8x + 2x < 45 + 15x 32 - 6x < 45 + 15x -21x < 13 When dividing by a neg number, the sense of the inequality is reversed x > -13/21
Draw a triangle. The the road would be the base, which is 1 mile or 5280 feet and the side opposite angle A would be 140. You need angle A. You have side a = 140 feet, and side b = 5280 feet. tan A = opp/adj = a/b = 140/5280 tan A = 140/5280 = ? arctan ? = angle A
Please don't repost a question without checking to see if your original post was answered. See your 1st post at 4:51 pm. This was answered for you.
P = M/(1 + r)^n P = price M = maturity value r = investor's required annual yield/2 n = number of years to maturity x 2 225 = 1000/(1 + r/2)^22 225(1 + r/2)^22 = 1000 (1 + r/2)^22 = 4.4444 take the 22nd root of each side 1 + r/2 = 1.07015 r/2 = 0.07015 r = .1403 r = 14% ...
For each equation, pick values for x and solve for y. Pick at least three pair of x,y values and then plot these points. Draw a line connecting these points. Do this for each equation. The point where these line graphs intersect is the solution.
Are you sure it's only one journal entry? For the $50 mil transaction, $50 DB to Asset Account, $10 mil paid in cash (CR Cash) and the remaining $40 mil is a loan payable (CR Loan Pay). Since $8 mil principal and interest is due each Dec 31, this must be a 5-yr loan (40 ...
I = PRT Divide both sides by PT I/PT = R
And, your question is? y + x = -4 ?
Do this the same way as shown in your 1st post.
Find ordered pairs to graph these equations. x + y = 6 x = 0, y = 6 x = 2, y = 4 x = 4, y = 2 x = 6, y = 0 x - y = 4 Do the same for this equation. Plot the points, for each equation and draw a line for each set of points. The point of intersection is the solution.
If for the following year, the entry should have been to prepaid insurance, an asset account, not to insurance expense. This is because the expense is not for the current year. The expense belongs in the next fiscal year. Current year entry, should have been DB Prepaid ...
I don't see a question.
Do you mean the wall is 12 feet by 16 feet? If so, set up a ratio. 12 : 16 = 4 : x 12/16 = 4/x Cross multiply 12x = 64 x = ?
Do you mean, 5^2 n + 1 = 1/25 ? 25n + 1 = 1/25 multiply both sides by 25 625n + 25 = 1 625n = -24 n = ?
6th grade math
'tghias' is NOT correct.
Do you mean, x^2 - 4 ? x^2 - 4 = (x - 2)(x + 2)
Ratio 5 : 2 5x + 2x = 20 Solve for x.
Re-type your problem. What is 7 4 1 4 ?
What rectangle? Re-read your problem. If you knew absolutely nothing about this problem, could you solve it with the information given?
I guess it depends on your teacher, because (2)^3/2 means (sqrt(2))^3 I've never seen anyone interpret this as (sqrt(2^3)). The first way will always get you the correct, simplified answer. If I were you, I would get in the habit of doing this the first way. Radicals ...
2/3(8)-ln3-2/3(sqrt*8) My answer, 16/3 - ln 3 - 4/3(sqrt(2)) You have 16/3, 2/3 (8) = 16/3 Where you went wrong, You have, 2/3 (sqrt(8)) It should be, 2/3 (0 + 2)^3/2 2/3 (2)^3/2 2/3 (sqrt(2))^3 2/3 (2(sqrt(2))) 4/3 (sqrt(2))
Please do not repost questions without checking to see if your original post was answered. Check your earlier post (2:44 am). This question was answered for you.
Check your problem. Not enough info is given here to solve this problem.
If he spends the same time doing 3 different activities, 80 hrs/3 = ?
n = number of dimes 21 - n = number of quarters .10n = value of dimes .25(21 - n) = value of quarters .10n + .25(21 - n) = 4.20 Solve for n, number of dimes 21 - n = number of quarters
Correct!! Good job!
70 words in 2 min = 70/2 = 35 wpm 120 words in 3 min = 120/3 = 40 wpm wpm = words per min Can you answer now?
Verify this equation, y = 4^x-1 You need parentheses. Is it, y = 4^(x - 1)? Or, y = 4^(x) - 1? Or ?
angle A = 45 deg Special 45-45-90 deg triangles have sides in the ratio of 1:1:(sqrt(2)) OR ratio n : n : n(sqrt(2)) This means, in this problem, side a = 1 (opposite side) side b = 1 (adjacent side) side c = 1*(sqrt(2)) (hypotenuse) tan A = a/b = op/adj tan 45 = ?
Verify this equation, y = 4^x-1 You need parentheses. Is it, y = 4^(x - 1)? Or, y = 4^(x) - 1? Or ? Are you Jamal? Please don't change screen names. And, which is it? In this problem, rotation is about the x-axis. In the 'Jamal' problem, rotation is about the y-axis.
Check your problem. Does the problem state between x = a and x = b?
For compounded annually R = rate, n = number of years FV = orig investment * ((1 + R)^n) 1,000,000 = 182,696 * (1 + R)^15 5 = (1 + R)^15 (15th root(5)) = 1 + R 1.11 = 1 + R .11 = R please check my math
D = RT Distance = Rate x Time T = D/R R = D/T
x = 225 degrees
Do you mean -(sqrt(2))/2 ?
The usual term for the place where two (or more) rivers meet is "confluence". From wiki answers dot com
derivative of f(x)=7x-19 at x=2 f'(x) = 7 f'(2) = 7
"The moon is much smaller than the earth. As a result, the force of gravity on the moon is only about one sixth as strong as gravity on earth. Gravity is what holds us down on the earth's (or moon's) surface. If you were to weigh yourself on a scale here on earth ...
If you would like a timely answer to your post, please post your school subject in the "School Subject" box.
See the first link below under Related Questions. A somewhat similar problem was answered. The link might be helpful if no one else answers.
s = side of square P = 4s 30 <= 4s <= 64 30/4 <= s <= 16 15/2 <= s < 16
Try to solve these inequalities first. Compound inequalities with 'Or', are solved separately and the solutions have 'or' between them. Example. If the solution to the first was x < 2 and the solution for the second was x > 4, then the solution would be, ...
Thanks so much MathMate!!
If possible, could a math tutor check the math post question that "daylo3" asked at 6:42 pm today, that I answered? I don't usually answer posts that I am not 100% sure of the answer. I would like to know if the way I approached this problem is correct? Thanks in...
194 * 10^3 = 194,000 Scientific notation 1.94 x 10^5
Since, the problem states to use R and C for the equation, change the x to C. So, the equation would be, R = 1.4C - 7 Instead of, R = 1.4x - 7
A.) Cost 85, Retail 112 Cost 175, Retail 238 For the equation (x,R), x = cost (85,112), (175,238) Since linear, use y = mx + b R = mx + b slope m = 238 - 112/(175 - 85) slope m = 126/90 = 1.4 R = 1.4x + b To find b, plug in (85,112) 112 = 1.4(85) + b 112 = 119 + b b = -7 R = 1...
Leave in radical form means don't simplify the sqrt (radical) to exact value. Example, exact value of (sqrt(2))= 1.4142 All your answers are correct. Always simplify radicals, ie,(like you did), but wasn't sure, (sqrt(52)) = 2(sqrt(13)) don't leave as (sqrt(52)) (...
A = wL x = width of garden x + 6 = length of garden Area of garden = x(x + 6) x + 6 = width of garden and walkway x + 6 + 6 = x + 12 = length of garden and walkway Area of garden and walkway = (x + 6)(x + 12) Area of garden and walkway - 288 = area of garden (x + 6)(x + 12) - ...
Commutative Property (think commute or move around)is the one that refers to moving stuff around. For addition, the rule is a + b = b + a From purplemath dot com
Assuming you mean 4 - 7^(2x) = 1 7^(2x) = 3 Take logarithm to base 7 of both sides 2x log 7 = log 3 x = log 3/(2 log 7) x = 0.4771/(2 * 0.8451) x = 0.4771/1.6902 x = 0.2823
b. Future value of an asset with interest compounded annually, (you didn't mention how to compound) n = number of years R = rate FV = Original investment * ((1 + R)^n) Cal. Future value of salary, 6%/year 1st year--23,000 2nd year---23,000 + 1,380 = 24,380 3rd year---24,...
Your post in incomplete. What is your question?
Assuming you earn a total of $70. x = amt earned Sat 2x = amt earned Sun 1/2 x = amt earned Fri x + 2x + 1/2 x = 70 Solve for x
My answer above is assuming you meant the United States. I don't know, if your question is for a different country.
I would say true.
MP = (1,3), A = (8,2), B = (x2,y2) Midpoint x = 1/2(x1 + x2) Midpoint y = 1/2(y1 + y2) 1 = 1/2(8 + x2) 2 = 8 + x2 x2 = -6 3 = 1/2(-2 + y2) 6 = -2 + y2 y2 = 8 B = (x2,y2) = (-6,8)
By "around" do you mean perimeter? A six figured polygon with equal sides, is called a regular hexagon.
then? Is this problem complete?
Not subtraction. Division would be used to solve this problem.
Convert all the fractions to fractions with the same denominator, using the LCD. A. 18/30 B. 20/30 C. 15/30 D. 21/30 Now, wouldn't the largest fraction be closest in value to 1?
Is this the exact wording of the problem? Assuming "then subtract from result" is referring to the unknown number n, 7(n/3) - n = 36 7n - 3n = 108 4n = 108 n = 27
I = PRT (Interest = Principal * Rate * Time) .04 interest/yr = .003 mo (.04/12) I = 6000 * 0.003 * 7 You can take it from here.
Integrated Physics and Chemistry
I found Ideal Mechanical Advantage.
Your post was answered below. Please don't repost a question without first checking to see if your 1st post was answered.
Please put the school subject name in the "School Subject" box. Thank you.
Thanks drwls. I could not understand this post at all. :)
See your first post.
There is no need to multiply the left side of the equation by 2.
If you would like a math tutor to help with your problem in a timely manner, please follow directions and put the school subject in the "School Subject" box.
I do not understand your post. Exterior angle? Where? Which one? "find the other interior opposite angle" Other? Interior? Opposite what? "and the third angle of each triangle" How many angles do you expect someone to find? Please re-read your post. Think ...
You need to use parentheses. x-4/x+3 = x-1/x+2 Is the problem, x - 4/(x+3) = (x-1)/x + 2 x - 4/x + 3 = x - 1/(x+2) Or x - 4/x + 3 = x - 1/x + 2 Can you see the difference in these equations? This is probably why no one answered your question.
math 9 helppp
Well, you arrived at the same answer, but the equation is not correct for the problem. Your equation doesn't make sense. Where did you get 380? 380/7 = 54.29 not 55, even rounded it would be 54 or 54.30 not 55. And, it is 3.50 fee/ticket. You can't randomly subtract 3....
math 9 helppp
The equation is 7x = 385 - 7(3.50) 7x = 385 - 24.50 7x = 360.50 x = 51.5 EACH ticket has a 3.50 service fee
| x^3*sqrt(x^2 + 1) dx | = integral sign | x^2 (sqrt(x^2 + 1)) x dx u = x^2 du = 2x dx 1/2 du = x dx 1/2 | u (sqrt(u + 1)) du w = u + 1 dw = du u = w - 1 1/2 | (w - 1) (sqrt(w)) dw 1/2 | (w - 1) w^1/2 dw 1/2 | w^3/2 dw - 1/2 | w^1/2 dw 1/2 (2/5 w^5/2) - 1/2 ( 2/3 w^3/2) + C 2/...
Not correct 121t^4 + 44t + 4
I pasted below an example that reiny (tutor here) did recently. 10 and 55 are done in this example. Follow what reiny did for 45. EXAMPLE 10 = 2*5 75 = 3*5*5 55 = 5*11 The GCF is the largest number that divides into all three numbers, in this case 5 the GCF ≤ the ...
(6x^2-3x-9)-(2x^2+8x+3) Remove parentheses and change the sign of the terms inside the parenthese Combine like terms 6x^2 - 3x - 9 - 2x^2 -8x - 3 I leave the rest to you
Add the two 3x^2 + 7x - 3 + 5x + 2 = ?
2z^2 IS 2z^2 or 2*z*z
The time x cannot be negative. You must have made a mistake. The two equations are, distance gone by car = 64x distance gone by truck = 56(x+1/4) Since the distances are equal, 64x = 56(x + 1/4) 64x = 56x + 56/4 64x = 56x + 14 8x = 14 x = 1.75 From above (Reiny's ...
If P1(x1,y1) and P2 (x2,y2) are two points on a line, the number m defined by the equation Slope m = (y2 - y1)/(x2 - x1) is called the slope of the line.
3.4 + (5x - 1.7) plug 2.2 in for x 3.4 + 5(2.2) - 1.7 3.4 + 11.0 - 1.7 You can take it from here
Slope-intercept form y = mx + b m = slope b = y-intercept 5X - 2Y = -10 2y = 5x + 10 y = 5/2 x + 5 Slope m = 5/3 y-intercept b = 5
$1167 ttl value of bills $147 ttl value of other bills $1020 value of tens and twenties n = number of tens and twenties 10n = ttl value of tens 20n = ttl value of twenties 10n + 20n = 1020 Solve for n, number of tens and twenties (equal number of both)
2x + 5y = 4 Add -2x to both sides 5y = -2x + 4 divide both sides by 5 y = -2/5 y + 4/5 So, slope m = -2/5 Perpendicular lines, the slopes are negative reciprocals of each other. Slope = -2/5 m1 * m2 = -1 -2/5 * m2 = -1 m2 = -1/(-2/5) m2 = 5/2 Now you have to find b, for the ...
I'm not sure what your question is ? 1 mile = 5280 feet 2 miles = 2 * 5280 ft = ? feet You can do the multiplication
Perimeter ABCD = 54 L = 12 in Perimeter LMNO = x L = 2.4 ft = 28.8 in P = 2w + 2L Use Ratio to find x (perimeter LMNO) 12/28.8 = 54/x Cross multiply 12x = 1555.2 x = 129.6 LMNO P = 129.6 L = 28.8 P = 2w + 2L 129.6 = 2w + 2(28.8) Solve for w, width of LMNO
After all that, I confused myself and did the wrong problem I think. IF your problem is |x cos(x^2) dx just like your 2nd reply says, ignore the above. I wrote down | x cos (x^2) but integrated | x cos^2 x dx So, your very first post IS correct if it is cos x^2 and not cos^2 x...